THIS - PowerPoint PPT Presentation

1 / 31
About This Presentation
Title:

THIS

Description:

Na2CO3, FeCl3, KNO3, NH4C2H3O2, ZnSO4, Ba(NO3)2, RbF A 400 Na2CO3 and RbF A 400 A solution of calcium hypochlorite, a common additive to swimming-pool water, is a. – PowerPoint PPT presentation

Number of Views:37
Avg rating:3.0/5.0
Slides: 32
Provided by: Cary159
Category:
Tags: this

less

Transcript and Presenter's Notes

Title: THIS


1
THIS
IS
Acid/Base Chemistry!
2
Starting Materials Materials after neutralization Equation to Use Sample Problem Calculate pH
STRONG ACIDS        
Strong Acid alone H pH-logH 0.1M HNO3  
Strong Acid weak(acid or base) H and HA (ignore HA) pH-logH 0.1M HNO3 and 0.4M acetic acid  
STRONG BASES        
Strong Base alone OH- pOH-logOH- 0.1M Ba(OH)2  
Strong Base weak (acid or base) OH- and A- (ignore A-) pOH-logOH- 0.1M Ba(OH)2 and 0.1M sodium acetate  
WEAK ACIDS        
Weak Acid alone H and HA RICE Ka 0.3M HCN  
WEAK BASES        
Weak Base alone OH- and B RICE Kb 0.2M NH3  
SALTS        
Both strong parents     NaCl 7
Strong Acid Parent     NH4Cl Below 7
Strong Base Parent     NaF Above 7
Both Weak Parents   Compare Ka vs. Kb   KaKb(neutral) KagtKb(acidic) KbgtKa (basic)            
3
The correct equilibrium expression for the
hydrolysis of CO32
A 200
4
K ( HCO3 OH ) / CO32
A 200
5
H2PO4 HBO32 ? HPO42 H2BO3 The equilibrium
constant for the reaction represented by the
equation above is greater than 1.0. Which of the
following gives the correct relative strengths of
the acids and bases in the reaction?
  Acids   Bases
a. H2PO4 gt H2BO3 and HBO32 gt HPO42
b. H2BO3 gt H2PO4 and HBO32 gt HPO42
c. H2PO4 gt H2BO3 and HPO42 gt HBO32
d. H2BO3 gt H2PO4 and HPO42 gt HBO32
A 300
6
A
A 300
7
Which of the following salts are basic? Na2CO3,
FeCl3, KNO3, NH4C2H3O2, ZnSO4, Ba(NO3)2, RbF
A 400
8
Na2CO3 and RbF
A 400
9
A solution of calcium hypochlorite, a common
additive to swimming-pool water, is a. basic
because of the hydrolysis of the OCl ionb.
basic because Ca(OH)2 is a weak and insoluble
basec. acidic because of the hydrolysis of the
Ca2 ionsd. acidic because the acid HOCl is
formed
A 500
10
A
A 500
11
Consider the reaction HNO2(aq) H2O(l) ?
H3O(aq) NO2(aq). Which species is a conjugate
base?
B 100
12
NO2-
B 100
13
The pH of a solution at 25C in which OH 3.9
x 105 M is
B 200
14
9.59
B 200
15
Calculate the pOH of a 4.9 M solution of HCl.
B 300
16
14.69
B 300
17
For weak acid, HX, Ka 6.9 x 106. Calculate the
pH of a 0.13 M solution of HX.
B 400
18
3.02
B 400
19
Calculate the pOH of a 0.12 M solution of acetic
acid (Ka  1.8 x 105).
B 500
20
11.17
B 500
21
What concentration of acetic acid (Ka 1.80 x
105) has the same pH as that of 5.33 x 103 M
HCl?
C 100
22
1.58M
C 100
23
Saccharin is a monoprotic acid. If the pH of a
4.41 x103 M solution of this acid is 2.53, what
is the Ka of saccharin?
C 200
24
6.0 x 10-3
C 200
25
A monoprotic weak acid when dissolved in water is
0.75 dissociated and produces a solution with a
pH of 3.11. Calculate the Ka of the acid.
C 300
26
5.9 x 10-6
C 300
27
Calculate the pH of a 0.059 M solution of Ca(OH)2.
C 400
28
13.07
C 400
29
The pH of a 0.150 M solution of a weak base is
10.98. Calculate the pH of a 0.0603 M solution of
the base.
C 400
30
11.28
C 500
31
Thank You for Playing Jeopardy!
Game Designed By C. Harr-MAIT
Write a Comment
User Comments (0)
About PowerShow.com