Title: Parallel Compensator for Continuous and Relay Control Systems with Difficult Plants
1Parallel Compensator for Continuous and Relay
Control Systems with Difficult Plants
- Ryszard Gessing
- Silesian University of Technology Gliwice, Poland
2Outline of Presentation
- Introduction
- Parallel Compensator
- Approximate Description of the CL System
- Choice of the Replacement Plant
- Accounting of the Control Saturation
- Relay Implementation
- Final Conlusions
3Introduction
- Smith predictor (compensator), 1958
- Deng, Iwai and Mizumoto 1999 for minimum phase
plants - Gessing ACC 2004 for nonminimum phase plants
4Outline of Presentation
- Introduction
- Parallel Compensator
- Approximate Description of the CL System
- Choice of the Replacement Plant
- Accounting of the Control Saturation
- Relay Implementation
- Final Conlusions
5Plant
is stable
Parallel Compensator
Replacement Plant
6 const
It should be
In steady state
7Outline of Presentation
- Introduction
- Parallel Compensator
- Approximate Description of the CL System
- Choice of the Replacement Plant
- Accounting of the Control Saturation
- Relay Implementation
- Final Conlusions
8Regulator (for a large k)
Closed loop System
9Outline of Presentation
- Introduction
- Parallel Compensator
- Approximate Description of the CL System
- Choice of the Replacement Plant
- Accounting of the Control Saturation
- Relay Implementation
- Final Conlusions
10Replacement plant
is chosen so that
n degree of M(s), T is chosen so that
then the CL system is stable for very large k
11CL system description
Characteristic equation
or
which has (n-1)-multiple root
12Example 1
Plant
For the replacement
plant is
and parallel compensator
Assume k1000 which gives
13For r1(t-1) we obtain
Settling time
for t 1, u 1000 for t 1.15, u -140
Acceptable responses for
14Outline of Presentation
- Introduction
- Parallel Compensator
- Approximate Description of the CL System
- Choice of the Replacement Plant
- Accounting of the Control Saturation
- Relay Implementation
- Final Conlusions
15(No Transcript)
16Example 2
Data as in Example 1
For
insignificant increase of settling time
For
settling time 5
17Comparison with regulator PID
Settling time 12.2 about 4-times longer.
18Outline of Presentation
- Introduction
- Parallel Compensator
- Approximate Description of the CL System
- Choice of the Replacement Plant
- Accounting of the Control Saturation
- Relay Implementation
- Final Conlusions
19During fast switchings we have
20Equivalent systems
Relay system
Continuous system
switched amplitude
then both the systems are equivalent, i.e. for
the same reference values r(t) we obtain the
same outputs y(t) in both the systems.
21Example 3
The plant and parallel comensator the same as in
previous examples.
Relay system h0.01, H10 solid line
Continuous system k1000, dotted line
For h0.005 both the outputs are
nondistinguishable.
22Relay system h0.005, H20
Continuous system
The outputs y for both the systems are
nondinguishable.
23Comparison
Sliding mode control
Parallel compensator
Ass minimum phase plant
without this assuption
Characteristic equation
24Outline of Presentation
- Introduction
- Parallel Compensator
- Approximate Description of the CL System
- Choice of the Replacement Plant
- Accounting of the Control Saturation
- Relay Implementation
- Final Conlusions
25- Easy for desinging
- Some freedom in choosing the replacement plant
and shaping dynamics - Shortening of transients
- It has some robustness with respect to change of
the plant parameters. - Implementation of sliding mode control without
necessity of applying of higher order derivatives - Equivalence of continuous and relay systems
- Plant must be stable
- Regulator has a high order