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Spontaneous Generation of Life

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Two members of a gene pair segregate (separate) from each other during the ... the Pacific Ocean in the city of Bikini Bottom, square pants (S) are dominant to ... – PowerPoint PPT presentation

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Title: Spontaneous Generation of Life


1
Spontaneous Generation of Life?
2
Animalcules- tiny people in sperm?
3
Blending of Parents traits
4
So What REALLY Happens?
  • The number of chromosomes divide to make gamete
    cells.
  • When does this occur?
  • Before sexual reproduction

5
Law of Segregation
  • Two members of a gene pair segregate (separate)
    from each other during the formation of gametes.
  • What is a gene pair?
  • When, in meiosis does segregation occur?
  • Anaphase I

6
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7
Test Crosses
  • SS x SS - true breeding (100 homozygous
    dominant.)
  • ss x ss - true breeding (100 homozygous
    recessive.)
  • How do you determine whether an individual with
    the dominant phenotype is homozygous or
    heterozygous?

8
Test Cross
  • Used to detect heterozygous condition.
  • In peas, the allele for tall plant height (T) is
    dominant over the allele for short plant height
    (t)
  • What cross would you do to determine the
    genotype of a tall pea plant?
  • What results would you expect if the tall plant
    is TT?
  • What results would you expect if the tall plant
    is Tt?

9
Law of Independent Assortment
  • Alleles for different traits assort (segregate)
    independently of one another.
  • Genes on different chromosomes behave
    independently in gamete production.
  • Why does this law not apply to a one trait
    cross?
  • When, in meiosis does this occur?

10

11
Probability
  • Probability the of times an event is expected
    to happen / the of opportunities for an event
    to happen.
  • For example, The probability of rolling a 2 on a
    dice in one trial is
  • 1/6
  • The rule of multiplication states that the
    probability of two or more events happening at
    the same time is the product of the independent
    events.
  • What is the probability of rolling two 2s?
  • (1/6) x (1/6) 1/36
  • How can the principles of probability be used to
    predict the outcomes of genetic crosses?

12
  • Ie. RrYy x RrYy
  • What is the probability of obtaining an
    offspring with the genotype rrYY?

13
  • What would the gametes of a plant of genotype
    SsYy have?
  • SY, Sy, sY, and sy
  • Each gamete will receive either an S or
  • s allele, and either a Y or y allele.
  • Following a SsYy x SsYy cross, what fraction of
    the offspring are predicted to have a genotype
    that is heterozygous for both characteristics?

14
  • When lots of genes are considered, you must use
    probabilities to answer questions.
  • AaBbCcDdEeFf x AaBbCcDdEeFf
  • What proportion of progeny will be AAbbCcDDeeFf?

15
  • In the cross AaBbCcDdEeFf x AaBbCcDdEeFf
  • What proportion of the progeny will be
    AaBBccddEEff?

16
Ratio9331
17
  • Deep down in the Pacific Ocean in the city of
    Bikini Bottom, square pants (S) are dominant to
    round pants (s), and yellow skin (Y) is dominant
    to green skin (y). Sponge bob is a Yellow
    skinned, square pants sponge, whose mother had
    green skin and round pants.
  • A. What is Sponge Bobs genotype?
  • B. Sponge Bob wants children and he mates with a
    spongey woman with square pants and green skin.
    Her father had curved ears. What is her
    genotype?
  • C. What is the phenotypic ratio of the children
    that are expected as a result of this mating?
  • D. How many of their children will have the
    following genotype?
  • PPYy? Ppyy?

18
  • A man with brown eyes marries a woman with blue
    eyes. The mans mother had blue eyes. What is
    the probability that they will have a blue-eyed
    child? 
  • B brown     b blue
  • You do not immediately know the genotype of the
    brown-eyed man because he could be either Bb or
    BB.  Begin to state the cross by using a blank
    for the unknown gene.  One of the genes of the
    brown-eyed man must be B or he would have blue
    eyes.  His genotype is B_ and the cross is B_ x
    bb -- .  Fill in any blanks in a problem by
    using other information in the problem.  The
    brown-eyed man had a blue-eyed mother.  Her
    genotype must be bb (If she had even one B gene
    she would have brown eyes).  The man's mother
    could give him only a b gene so his genotype must
    be Bb.  The cross now is Bb x bb --.  Do the
    cross. 

19
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