Equilibrium Law - PowerPoint PPT Presentation

1 / 7
About This Presentation
Title:

Equilibrium Law

Description:

Step 1: Set up the 'equilibrium law' equation. Kc ... By substituting equilibrium concentrations into equilibrium law, we can calculate Kc ... – PowerPoint PPT presentation

Number of Views:28
Avg rating:3.0/5.0
Slides: 8
Provided by: JeremySc5
Category:

less

Transcript and Presenter's Notes

Title: Equilibrium Law


1
Equilibrium Law
2
Introduction to the Equilibrium law
  • Read 14.3 to PE1

H2O
H2O2
H22O2
H22O2
2H2(g) O2(g) ? 2H2O (g)
2H2(g) O2(g) ? 2H2O (g)
2H2(g) O2(g) ? 2H2O (g)
2H2(g) O2(g) ? 2H2O (g)
2H2(g) O2(g) ? 2H2O (g)
Step 1 Set up the equilibrium law equation
Step 2 Product concentrations go in numerator
Step 3 Concentration in mass action expression
is raised to the coefficient of the product
Step 4 Reactant concentrations go in denominator
Step 5 Concentrations in mass action expression
are raised to the coefficients of reactants
3
Equilibrium law important points
  • State (g, l, s, aq) may or may not be added at
    this point since we will only be dealing with
    gasses for this section. Later it will matter.
  • The equilibrium law includes concentrations of
    products and reactants in mol/L (M)
  • The value of Kc will depend on temperature, thus
    this is listed along with the Kc value
  • Tabulated values of Kc are unitless
  • By substituting equilibrium concentrations into
    equilibrium law, we can calculate Kc
  • Do RE 14.31, 35, 36, 37 (pg. 589)

4
Equilibrium law RE 14.31, 14.35
  • CO(g) 2H2(g) ? CH3OH(g)

CH3OH
0.398
CO H22
C2H4(g) H2O(g) ? C2H5OH(g)
C2H5OH
300
C2H4 H2O
5
Equilibrium law RE 14.36, 14.37
  • CO(g) 2H2(g) ? CH3OH(g)

CH3OH
0.500
CO H22
x 0.210 0.1002 (0.500)
0.00105 M
N2(g) 3H2(g) ? 2NH3(g)
NH32
64
N2 H23
x3 0.2802 / 0.00840 (64)
0.146
x3 0.146
x 0.53 M
6
When Kc ? mass action expression
  • We can use the equilibrium law to determine if an
    equation is at equilibrium or not
  • If mass action expression equals equilibrium
    constant then equilibrium exists
  • Q - consider C2H4(g) H2O(g) ? C2H5OH(g)
  • If Kc 300, s 0.0197 M, 0.0200 M, 0.175 M
    which direction will the reaction need to shift?

C2H5OH
300
C2H4 H2O
444 ? 300
444 must be reduced to 300. Thus, the top must
decrease and the bottom must increase. A shift to
left is required to establish equilibrium.
7
More equilibrium law problems
  • Do RE 14.32, 33 (pg. 589). For each, state in
    which direction the reaction needs to shift

PCl5
0.18
PCl3 Cl2
8.24 ? 0.18
Top must ?, bottom must ? - shift to left is
needed
SO2(g) NO2(g) ? NO(g) SO3(g)
NO SO3
85
SO2 NO2
88.9 ? 85
Top must ?, bottom must ? - shift to left is
needed
For more lessons, visit www.chalkbored.com
Write a Comment
User Comments (0)
About PowerShow.com