Hypothesis Tests for two Means, Two Variances, or Two Proportions Suggested Problems - PowerPoint PPT Presentation

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Hypothesis Tests for two Means, Two Variances, or Two Proportions Suggested Problems

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The ductility of metal bar stock is an important property of the raw material ... if there is a significant difference in ductility between the two products. ... – PowerPoint PPT presentation

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Title: Hypothesis Tests for two Means, Two Variances, or Two Proportions Suggested Problems


1
Hypothesis Tests for two Means, Two Variances, or
Two Proportions Suggested Problems
2
Barnes 10.1
  • The ductility of metal bar stock is an important
    property of the raw material for companies
    engaged in extrusion manufacturing, such as in
    the making of electrical conduit. It is equally
    important that the metal be neither too ductile
    nor not ductile enough. Two suppliers currently
    provide raw materials to your company. A sample
    of 14 bars is taken from the inventory of each
    suppliers product, and the average ductilities
    from the samples are x-bar1 46 and x-bar2 53.
    The standard deviation of each meausre is known
    to be ?1 5 and ?2 7. Based on this
    information, determine if there is a significant
    difference in ductility between the two products.

3
Barnes 10.1
  • Solving by hand
  • H0 p .50
  • H1 p gt .50
  • n (50)1000 500
  • Confidence level 99
  • Z? Z.01 2.3268
  • The rejection region is z gt za z.01 2.3268
  • The sample proportion is
  • The value of the test statistic is

4
Barnes 10.2
  • Two companies sell varnish to the general public.
    Seventeen cans of vendor As product and 12 cans
    of vendor Bs product are purchased at random
    locations. Each cans contents are used to paint
    a 1-square foot area on a test board, and the
    drying time for each sample is measured and
    recorded. The following results have been
    obtained x-barA 20, x-barB 24, sA 3.5, and
    sB 5.0. If it is important that Bs product not
    take longer than As to dry, determine if this
    data set implies a significant difference in
    drying times between the two products.

5
Barnes 10.3
  • Determine if a significant difference exists
    between the variables of the two populations
    studied in Exercise 10.2.

6
Barnes 9.12
  • Solving by hand
  • H0 ? 90.50
  • H1 ? lt 90.50
  • n 22, x-bar 89, s 3
  • Confidence level 95
  • The rejection region is t lt ta,n 1 t .05,
    22-1 1.721
  • The value of the test statistic is

7
Barnes 10.7
  • The Field Research Group of the Indianapolis
    Branch Laboratory of the Day, Tee, and Tee
    Development Corporation is chared with not
    allowing any cost-reduced product to be put into
    the field before it has been shown to be at least
    as reliable as the product thart it is replacing.
    Because all items that DTT provides to its
    customers are on a lease-only basis, it is
    possible to obtain very good records in regard to
    the number of products of a particular type that
    have experienced any difficulty. The Illinois
    branch of DTT agreed to allow a field test of
    the comparison, two samples of 1000 each of the
    old Autocaller 1.0 and the new Autocaller 2.0 are
    put into service in Illinois customers homes.
    After 6 months, 52 of the old units and 66 of the
    new units have required repair operations. What
    may we conclude about the relative reliability of
    the two products? If we are interested in being
    able to detect a difference of .75, what is your
    opinion of the sample sizes that were used?

8
Barnes 9.19
  • A producer of brass rivets claims that its rivets
    diameters have ? .01 inch. A sample of 10
    rivets has s .018. What can you conclude about
    the rivet makers claim? Is the sample adequately
    sized to make any decision?

9
Example 9.19
  • Solving by hand
  • H0 ?2 .0001
  • H1 ?2 gt .0001
  • n 10, s .018
  • Confidence level 95

10
Example 9.19
  • Since 29.16 gt 3.325, then reject the null
    hypothesis, thus the brass rivet producers claim
    is not accurate

11
Barnes 9.25
  • The proportion of people missing a particular
    class day must be less than .25. A sample of 100
    days is taken, yielding an average proportion of
    .23. What is your conclusion?

12
Barnes 9.25
  • Solving by hand
  • H0 p .25
  • H1 p lt .25
  • n 100
  • Confidence level 99
  • Z? Z.01 2.3268
  • The rejection region is z lt za z.01 2.3268
  • The sample proportion is
  • The value of the test statistic is

13
Barnes 9.25
  • Since 4.6188 lt 2.3268, then reject the null
    hypothesis
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