Title: Kinematics of Rigid Bodies in Three Dimensions
 1Chapter 18
- Kinematics of Rigid Bodies in Three Dimensions
218.1 Introduction
- The fundamental relations developed for the plane 
 motion of rigid bodies may also be applied to the
 general motion of three dimensional bodies.
- The current chapter is concerned with evaluation 
 of the angular momentum and its rate of change
 for three dimensional motion and application to
 effective forces, the impulse-momentum and the
 work-energy principles.
318.2 Rigid Body Angular Momentum in Three 
Dimensions
- Angular momentum of a body about its mass center,
418.2 Rigid Body Angular Momentum in Three 
Dimensions 
 518.2 Rigid Body Angular Momentum in Three 
Dimensions
- Transformation of into is 
 characterized by the inertia tensor for the body,
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 7z 
 818.2 Rigid Body Angular Momentum in Three 
Dimensions 
 918.2 Rigid Body Angular Momentum in Three 
Dimensions 
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 1118.3 Principle of Impulse and Momentum 
- The free-body diagram equation is used to develop 
 component and moment equations.
- For bodies rotating about a fixed point, 
 eliminate the impulse of the reactions at O by
 writing equation for moments of momenta and
 impulses about O.
1218.4 Kinetic Energy
- Kinetic energy of particles forming rigid body,
- With these results, the principles of work and 
 energy and conservation of energy may be applied
 to the three-dimensional motion of a rigid body.
1318.4 Kinetic Energy 
 14Sample Problem 18.1
- SOLUTION 
- Apply the principle of impulse and momentum. 
 Since the initial momenta is zero, the system of
 impulses must be equivalent to the final system
 of momenta.
- Assume that the supporting cables remain taut 
 such that the vertical velocity and the rotation
 about an axis normal to the plate is zero.
- Rectangular plate of mass m that is suspended 
 from two wires is hit at D in a direction
 perpendicular to the plate.
- Immediately after the impact, determine 
-  the velocity of the mass center G, 
-  the angular velocity of the plate.
- Principle of impulse and momentum yields two 
 equations for linear momentum and two equations
 for angular momentum.
- Solve for the two horizontal components of the 
 linear and angular velocity vectors.
15Sample Problem 18.1
- SOLUTION 
- Apply the principle of impulse and momentum. 
 Since the initial momenta is zero, the system of
 impulses must be equivalent to the final system
 of momenta.
16Sample Problem 18.1 
 17Sample Problem 18.1 
 18Sample Problem 18.2
- SOLUTION 
- The disk rotates about the vertical axis through 
 O as well as about OG. Combine the rotation
 components for the angular velocity of the disk.
- A homogeneous disk of mass m ismounted on an 
 axle OG of negligible mass. The disk rotates
 counter-clockwise at the rate ?1 about OG.
- Determine 
- the angular velocity of the disk 
- its angular momentum about O, 
- its kinetic energy 
- the vector and couple at G equivalent to the 
 momenta of the particles of the disk.
- Compute the angular momentum of the disk using 
 principle axes of inertia and noting that O is a
 fixed point.
- The kinetic energy is computed from the angular 
 velocity and moments of inertia.
- The vector and couple at G are also computed from 
 the angular velocity and moments of inertia.
19Sample Problem 18.2 
 20Sample Problem 18.2 
 21Sample Problem 18.2 
 2218.5 Motion of a Rigid Body in Three Dimensions
- Transformation of into is 
 independent of the system of coordinate axes.
- Convenient to use body fixed axes Gxyz where 
 moments and products of inertia are not time
 dependent.
- Define rate of change of change of with 
 respect to the rotating frame,
 Then, 
 2318.6 Eulers Eqs of Motion  DAlemberts 
Principle
- With and Gxyz chosen to correspond 
 to the principal axes of inertia,
 Eulers Equations
- System of external forces are equivalent to the 
 vector and couple,
2418.7 Motion About a Fixed Point or a Fixed Axis
- For a rigid body rotation around a fixed Z 
 axis(?z  ?, ?x?z0),
2518.8 Rotation About a Fixed Axis
- If symmetrical with respect to the xy plane, 
 IxzIyz0 and,
- A rotating shaft requires both static 
 and dynamic balancing to avoid
 excessive vibration and bearing reactions.
26Sample Problem 18.3
- SOLUTION 
- Evaluate the system of effective forces by 
 reducing them to a vector attached at G and
 couple
- Expressing that the system of external forces is 
 equivalent to the system of effective forces,
 write vector expressions for the sum of moments
 about A and the summation of forces.
Rod AB with weight W  40 lb is pinned at A to a 
vertical axle which rotates with constant angular 
velocity ?  15 rad/s. The rod position is 
maintained by a horizontal wire BC. Determine 
the tension in the wire and the reaction at A.
- Solve for the wire tension and the reactions at A.
27Sample Problem 18.3
- SOLUTION 
- Evaluate the system of effective forces by 
 reducing them to a vector attached at G
 and couple
28Sample Problem 18.3 
 29Prob. 18.65
- A homogeneous 8 lb disk is mounted on the 
 horizontal shaft AB. The plane of the disk forms
 a 20? angle with the yz plane as shown.
- Knowing that the shaft rotates with a constant 
 angular velocity ? of magnitude 10 rad/sec,
 determine the dynamic reactions at points A and B.
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 32Prob. 18.78
- The essential structure of a certain type of 
 aircraft turn indicator is shown.
- Each spring has a constant of 40 lb/ft, and the 
 7-oz. uniform disk of 2 in. radius spins at the
 rate of 10,000 rpm.
- The springs are stretched and exert equal 
 vertical forces on yoke AB when the airplane is
 traveling in a straight path.
- Determine the angle through which the yoke will 
 rotate when the pilot executes a horizontal turn
 of 2250 ft radius to the right at a speed of 500
 mi/hr. Indicate whether point A will move up or
 down.
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 34Start of Class 
 3518.9 Motion of a Gyroscope. Eulerian Angles
- A gyroscope consists of a rotor with its mass 
 center fixed in space but which can spin freely
 about its geometric axis and assume any
 orientation.
- From a reference position with gimbals and a 
 reference diameter of the rotor aligned, the
 gyroscope may be brought to any orientation
 through a succession of three steps
- rotation of outer gimbal through f about AA, 
- rotation of inner gimbal through ? about BB 
- rotation of the rotor through ? about CC.
-  j, q, and y are called the Eulerian Angles and 
3618.9 Motion of a Gyroscope. Eulerian Angles
z'
y'
x'
let I be the moment of inertia about the z 
axis let I ' be the moment of inertia about the x 
 y axes
align fixed x'y'z' coordinate system as shown
attach xyz coord. system to orange frame (inner 
gimbal) 
 3718.9 Motion of a Gyroscope. Eulerian Angles
z'
y'
x'
align fixed x'y'z' coordinate system as shown
attach xyz coord. system to orange frame (inner 
gimbal) 
 3818.10 Steady Precession of a Gyroscope
?z
Steady precession, 
 3918.10 Steady Precession of a Gyroscope 
 4018.11 Motion of an Axisymmetrical Body Under No 
Force
- Define the Z axis to be aligned with and z 
 in a rotating axes system along the axis of
 symmetry. The x axis is chosen to lie in the Zz
 plane.
-  ?  constant and body is in steady precession.
x axis lies in Zz plane (although it doesnt look 
like it) 
 4118.11 Motion of an Axisymmetrical Body Under No 
Force
Two cases of motion of an axisymmetrical body 
which under no force which involve no precession 
 4218.11 Motion of an Axisymmetrical Body Under No 
Force
The motion of a body about a fixed point (or its 
mass center) can be represented by the motion of 
a body cone rolling on a space cone. In the case 
of steady precession the two cones are circular.
- I lt I. Case of an elongated body. g lt q and 
 the vector w lies inside the angle ZGz. The
 space cone and body cone are tangent externally
 the spin and precession are both counterclockwise
 from the positive z axis. The precession is said
 to be direct.
43Prob. 18.123
- A coin is tossed into the air. It is observed to 
 spin at a rate of 600 rpm about the axis GC and
 to precess about the axis GD.
- Knowing that GC forms an angle of 15? with GD, 
 determine
- the angle that the velocity vector of the 
 coin forms with GD
- the rate of precession of the coin about GD
44Prob. 18.123
The total angular velocity of the coin can be 
written as 
 45Prob. 18.123
The angle ß is the solution to part (a). From 
slide 40,
?
ß 
 46Prob. 18.123
Recall that
?
ß
?x
?z
From slide 40, 
 47End of Class