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Partial fractions

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Section 6.3 Partial Fractions Advanced Algebra What is Partial Fraction Decomposition? There are times when we are working with Rational Functions of the form ... – PowerPoint PPT presentation

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Title: Partial fractions


1
Section 6.3 Partial Fractions
Advanced Algebra
2
What is Partial Fraction Decomposition?
  • There are times when we are working with Rational
  • Functions of the form when we
    want to
  • split it up into two simpler fractions. The
    process that we go through to do this is called
    partial fraction decomposition

3
Lets say you had the following
What would you need to do to add them together?
Multiply by a common denominator to both fractions
Write as one fraction and simplify the numerator
The final answer
Partial Fraction Decomposition is the reverse of
what we just did here
4
Break into 2 smaller fractions
Multiply by LCD
Cancel anything necessary
Collect like terms and set equal
5
Multiply by the common denominator.
Collect like terms together and set them equal to
each other.
Solve two equations with two unknowns.
6
This technique is called Partial Fractions
Solve two equations with two unknowns.
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8
Sometimes you might get a repeated factor
(multiplicity) in the denominator
Repeated roots we must use two terms for partial
fractions.
9
Partial-Fraction Decomposition Repeated linear
factor
10
Now we have 3 equations with 3 unknowns. Solve
like in previous section.
11
If the degree of the numerator is higher than the
degree of the denominator, use long division
first.
(from example one)
12
What if the denominator has a non-factorable
quadratic in it?
Partial Fraction Decomposition can get very
complicated, very quickly when there are
non-factorable quadratics and repeated linear
factorshere is an easy example
Now just solve the 3 by 3 system A3, B2 and C4
13
A nice shortcut if you have non-repeated linear
factorsthe Heaviside Shortcutnamed after
mathematician Oliver Heaviside (1850-1925)
Tell yourself, if x is 5, then x-5 is 0. Cover
up the x-5 and put 5 in for the x in what is left
Do the same for the other linear factor
Which should probably be simplified
14
A challenging example
first degree numerator
irreducible quadratic factor
repeated root
15
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17
expand ((-2x4)/((x21)(x-1)2))
3
F2
p
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