Chords halving the area of a planar convex set - PowerPoint PPT Presentation

1 / 36
About This Presentation
Title:

Chords halving the area of a planar convex set

Description:

Title: Presentaci n de PowerPoint Last modified by: Cinzia Document presentation format: Presentazione su schermo Other titles: Times New Roman Dise o ... – PowerPoint PPT presentation

Number of Views:60
Avg rating:3.0/5.0
Slides: 37
Provided by: unif170
Category:

less

Transcript and Presenter's Notes

Title: Chords halving the area of a planar convex set


1
Chords halving the area of a planar convex set
  • Grüne , E. Martínez, C. Miori,
  • S. Segura Gomis

2
1.Introduction
  • Problem to determine some inequalities
    describing geometric properties of the chords
    halving the area of a planar bounded convex set
    K.
  • - A. Ebbers-Baumann, A. Grüne, R. Klein
    Geometric dilation of closed planar curves New
    lower bounds. To appear in Theory and
    Applications dedicated to Euro-CG 04, 2004.

3
2. Definitions
  • 2.1 Halving partner.
  • Let K be a planar convex set.
  • Let p be a point on .
  • Then the unique halving partner p' on
  • is the intersection point between the straight
    line pp' halving the area of K and its
    boundary.

4
2. Definitions
  • 2.2 Breadth measures.
  • . v-length

5
2. Definitions
  • 2.2 Breadth measures.
  • . diameter

6
2. Definitions
  • 2.2 Breadth measures.
  • . minimal width

7
2. Definitions
  • 2.2 Breadth measures.
  • . v-breadth

8
2. Definitions
  • 2.3 v-halving distance
  • is the distance of the halving pair with
    direction v.

9
  • Proposition 1

10
  • Proof of Proposition 1
  • it is trivial.
  • Rotating v in there is at least, by
    continuity, a direction v0 such that the maximal
    chord in this direction divides K into two
    subsets of equal area. Then
  • For every v, Then

11
3. Overview of the results
 
12
3. Overview of the results
 
13
3. Overview of the results
 
14
3. Overview of the results
 
15
3. Overview of the results
 
16
  • Lemma 1 (Kubota)
  • If is a convex body, then
  • Lemma 2 (Grüne , Martínez, , Segura)
  • If is a convex body, then
  • This bound cannot be improved.

17
Lemma 1 Lemma 2
18
Lemma 1 Lemma 2
19
  • Proposition 2
  • If is a convex body, then
    .
  • This bound cannot be improved.
  • Lemma 3
  • If is a convex body, and
    is an arbitrary direction, then
    .
  • This bound cannot be improved.

20
  • Proof of the Lemma 3

21
  • Proof of Proposition 2
  • Let be the direction such that
  • Then we get

22
  • Proposition 3
  • For any convex body K we have
  • This bound is tight.

23
  • Proof of the Proposition 3
  • . D pq
  • .

24
  • Assume
  • .
  • .
  • .

25

Contradiction!
26
3. Overview of the results
 
27
3. Overview of the results
 
28
3. Overview of the results
 
29
3. Overview of the results
 
30
3. Overview of the results
 
31
3. Overview of the results
 
32
3. Overview of the results
 
33
4. Conjecture and open problems
4.1 In the family of all bounded convex
sets where the maximum is attained if and only
if K is a disc. The conjecture was first posed by
Santaló. The best bound known up to now, which is
a consequence of Pals Theorem, is
34
4. Conjecture and open problems
4.2 Are discs the only planar convex sets with
constant v-halving distance? Equivalently, is
the lower bound of the ratio attained ONLY by a
disc?
35
5. Final remark
  • The chords halving the area of a planar bounded
    convex set are involved in the so called
    fencing problems which consider the best way to
    divide by a fence such sets into two subsets of
    equal area.

36
5. Final remark
  • The chords halving the area of a planar bounded
    convex set are involved in the so called
    fencing problems which consider the best way to
    divide by a fence such sets into two subsets of
    equal area.

- H. T. Croft, K. J. Falconer, R. K. Guy
Unsolved problems in Geometry. Springer-Verlag,
New York (1991), A26 - C.M, C. Peri, S. Segura
Gomis On fencing problems, J. Math. Anal. Appl.
(2004), 464-476.
Write a Comment
User Comments (0)
About PowerShow.com