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Title: DO NOW:


1
  • DO NOW

2
Do Now (2/18/14)
  • Pass in your hw, lab, and Do Now!!!
  • A concave mirror with a radius of curvature of
    1.0 m is used to collect light from a distant
    star. The distance between the mirror and the
    image of the star is most nearly

a) 0.25 m b) 0.50 m c) 0.75 m d) 1.0 m e) 2.0 m
3
Objectives
  • Describe the causes of interference patterns due
    to diffraction and thin films.
  • Use the diffraction equation.
  • Describe the effects of polarization of light.
  • Determine the wavelength of a light source using
    a diffraction pattern.

4
Brainstorm
  • Discuss with your elbow partner (2 min)
  • Do you think light is a wave or a particle? Why
    or why not?

5
Intensity
  • Is the energy it carries per unit of time.
  • Proportional to the square of the amplitude of
    the wave.
  • Color of light is related to its ? or f, not
    intensity.
  • What characteristic of sound is most similar to
    light intensity?

6
Polarization
  • Polarizing filters
  • Only possible if light travels as a wave.
  • I I0cos2(?) (Maluss Law)

7
Huygens Principle
  • In the 17th Century, Christian Huygens proposed a
    theory stating every point on a wave front can
    be considered as a source of tiny wavelets that
    spread out in the forward direction at the speed
    of the wave.

8
Huygens Principle
  • Every point of a wave front may be considered the
    source of secondary wavelets that spread out in
    all directions with a speed equal to the speed of
    propagation of the waves.

9
Huygens Principle
  • Other scientists immediately understood that
    Huygens principle predicted that all waves
    should then spread into the shadow behind an
    obstacle.
  • We call this bending of waves diffraction.
  • If light is a wave, it should undergo the process
    of diffraction, and should also be able to
    undergo the process of interference.

10
Light Particle or Wave?
  • A light source illuminating a single slit

http//images.google.com/imgres?imgurlhttp//www.
peace-files.com/QF-L-11/07_Double-Slit-03.jpgimgr
efurlhttp//www.peace-files.com/QF-L-11/01_QF-Dou
ble-slit.htmlh267w400sz26hlenstart68um
1tbnidK6ikhnty_r8L4Mtbnh83tbnw124prev/ima
ges3Fq3Dyoung2527s2Bdouble2Bslit26start3D54
26ndsp3D1826um3D126hl3Den26rls3Dcom.micros
oft26sa3DN
11
Light Particle or Wave?
  • Particle theory prediction for the pattern
    produced by two slits, side by side

http//images.google.com/imgres?imgurlhttp//www.
peace-files.com/QF-L-11/07_Double-Slit-03.jpgimgr
efurlhttp//www.peace-files.com/QF-L-11/01_QF-Dou
ble-slit.htmlh267w400sz26hlenstart68um
1tbnidK6ikhnty_r8L4Mtbnh83tbnw124prev/ima
ges3Fq3Dyoung2527s2Bdouble2Bslit26start3D54
26ndsp3D1826um3D126hl3Den26rls3Dcom.micros
oft26sa3DN
12
Light Particle or Wave?
  • Wave theory prediction for the pattern produced
    by two slits, side by side
  • Note to easily observe light-wave interference,
    light from the two sources would have to be
    coherent and monochromatic.

http//images.google.com/imgres?imgurlhttp//www.
peace-files.com/QF-L-11/07_Double-Slit-03.jpgimgr
efurlhttp//www.peace-files.com/QF-L-11/01_QF-Dou
ble-slit.htmlh267w400sz26hlenstart68um
1tbnidK6ikhnty_r8L4Mtbnh83tbnw124prev/ima
ges3Fq3Dyoung2527s2Bdouble2Bslit26start3D54
26ndsp3D1826um3D126hl3Den26rls3Dcom.micros
oft26sa3DN
13
Youngs Double Slit Experiment
  • Young saw an interference pattern.
  • To explain this alternating pattern of bright and
    dark fringes, he understood that at any point on
    the viewing screen (other than at the center),
    the two rays of light would have to travel
    different distances to arrive at the screen.

x
?
L
14
Youngs Double Slit Experiment
  • If this path length difference is an integer
    multiple of the lights wavelength, a bright
    fringe is seen.
  • A dark fringe is seen anytime the path length
    difference is ½ of the ?.

?
dsin?
15
Fringes
  • Diffraction causes fringes

16
Example Problem 24-1
  • 520nm light falls on a pair of narrow slits
    separated by 0.2mm. How far apart are the fringes
    near the center of the pattern on a screen 2.5m
    away?

x 0.064m or 6.4mm
17
Small Angle Approximation
  • How could we approximate Youngs formula for
    small angles??

18
Small Angle Approximation
  • Note For small angles (x ltlt L), sin? tan?, so
    you can approximate the distance between the
    fringes as

19
Diffraction Gratings
  • A special device called a diffraction grating
    consists of many equally-spaced parallel lines
    scratched into a glass plate. The spaces between
    the scratches act as a source of light, and
    interference is observed.
  • The interference equation predicts the location
    of maxima in the interference pattern. The maxima
    are much thinner more defined than the pattern
    created by a double slit.
  • The only difference about these problems
    (compared to old diffraction problems) will be
    that you wont be told the value of d. Instead,
    youll be told the number of lines per distance,
    which is really 1/d.

20
Review
21
Huygens principle
  • Wave theory of light every point on a wave
    front can be considered as a source of tiny
    wavelets that spread out in the forward direction
    at the speed of the wave itself.
  • predicts waves bending around openings
  • http//www.launc.tased.edu.au/online/sciences/phys
    ics/diffrac.html

22
Diffraction
  • Youngs Double slit experiment wave nature of
    light
  • dsin? m? - constructive interference
  • xm (m ?L)/d

http//www.surendranath.org/applets/optics/slits/d
oubleslit/dblsltapplet.html http//micro.magnet.fs
u.edu/primer/java/interference/doubleslit/
23
  • Plane sound waves of wavelength 0.12 m are
    incident on two narrow slits in a box with
    nonreflecting walls, as shown above. At a
    distance of 5.0 m from the center of the slits, a
    first order maximum occurs at point P, which is
    3.0 m from the central maximum. The distance
    between the slits is most nearly
  • a) 0.07 m
  • b) 0.09 m
  • c) 0.16 m
  • d) 0.20 m
  • e) 0.24 m

24
Single Slit Diffraction
  • It turns out that an interference pattern is
    still observed even when theres only one point
    as a source of light.
  • According to Huygens principle, each portion of
    the slit acts as a source of waves. Therefore,
    light from one portion of the slit can interfere
    with light from a different portion.

25
Single Slit Diffraction
  • The only thing that changes about problems with
    single-slit diffraction is that the interference
    equation now predicts the location of minima
    (where the diffraction pattern has minimum
    intensity), for integral m-values.

26
Different Diffraction Patterns
http//www.tau.ac.il/phchlab/experiments/hydrogen
/diffraction_gratings.htm
27
Diffraction Patterns from Edges
  • Diffraction patterns can arise anytime light
    bends when passing around edges of an obstacle.
  • Shadows of objects therefore contain diffraction
    patterns, with a bright spot at their centers.
  • You should also be aware that light wave
    diffraction isnt observed as much in the
    macroscopic (big) world because diffraction
    effects are more pronounced when the size of the
    opening through which the wave passes is close to
    the size of the wavelength of the wave.

28
Do Now (2/19/14)
  • If the distance between two slits is 0.050 mm and
    the distance to a screen is 2.5 m, find the
    spacing between the first and second order bright
    fringes for light of wavelength 600 nm.
  • What color is this light?

29
Single Slit Diffraction
  • Diffraction of light by a slit of narrow width a

30
Example
  • Light of wavelength 580 nm is incident on a slit
    of width 0.3 mm. The observing screen is placed 2
    m from the slit. Find the positions of the first
    dark fringes and the width of the central bright
    fringe.

31
Brewsters Law
32
Polarizing Angle
  • The angle of incidence that satisfies Brewsters
    Law.

33
Thin-Film Interference
34
Thin Film Interference
  • When light encounters the boundary between two
    substances with different indices of refraction ,
    some of the light will be reflected and some will
    be transmitted.
  • Interference happens.
  • Constructive interference happens when the 2nd
    wave exits the whole mess in phase with the 1st
    wave.
  • ? Depth of film 1/2?

Air (n1.00)
Oil (n1.28)
Water (n1.33)
35
Thin Film Interference
  • Destructive interference happens when the 2nd
    wave exits the whole mess out of phase with the
    1st wave.
  • ? Depth of film 1/4?

Air (n1.00)
Oil (n1.28)
Water (n1.33)
36
Thin-Film Interference
  • When light is reflected upon trying to enter a
    substance with a higher n-value, it is also
    shifted by 180, which is equal to a path
    difference of 1/2?.

Air (n1.00)
Glass (n1.56)
Glass (n1.56)
Air (n1.00)
37
Thin-Film Interference
  • Constructive interference will happen when the
    second wave undergoes a total phase change of ?.
  • But since during reflection it undergoes a phase
    change of 1/2? when it reflects from the top soap
    layer, it only needs to undergo a phase change of
    1/2? as it travels the thickness of the film
    (twice).

Air (n1.00)
Soap (n1.28)
Air (n1.00)
38
Thin Film Interference
  • Constructive
  • Destructive

39
Thin Film Interference
  • The wavelength of light, ?n, in a medium with
    index of refraction n is
  • Where ? is the wavelength of light in free space

40
Example
  • Calculate the minimum thickness of a soap-bubble
    film (n1.33) that will result in constructive
    interference in the reflected light if the film
    is illuminated by light with a wavelength in free
    space of 602 nm.

113 nm
41
AP Practice!
  • Try to finish the first two problems before the
    end of today.

42
Lab How wide is a human hair?
  • A human hair can act just like a double slit. The
    light going around both edges will bend/diffract
    and create an interference pattern.
  • This lab will include a writeup

43
Electromagnetic Waves and Optics
  • AP PHYSICS
  • UNIT 11
  • GIANCOLI
  • CH.22 - 24

44
Electromagnetic Waves
  • We already know that a changing B-field or flux
    will produce an electric field (i.e. causes the
    movement of charges or current)
  • Conversely, James Maxwell came up with the idea
    that a changing electric field can produce a
    magnetic field.

45
Electromagnetic Waves
  • Accelerating charge gives rise to EM waves that
    can even travel through a vacuum.
  • The oscillating electric and magnetic fields are
    perpendicular to one another.
  • EM waves move through a vacuum at c
    3.00x108 m/s.

46
Electromagnetic Waves
  • The wave-speed equation still applies

47
Speed of Light (c)
  • Ole Roemer first determined that the speed of
    light was finite.
  • He found that the period of Io, one of Jupiters
    moons, varied slightly depending on the relative
    motion of Earth and Jupiter.
  • If the Earth was moving away from Jupiter during
    Ios orbit the light would have to travel a
    longer distance, increasing I0s apparent orbital
    period.

48
Electromagnetic Spectrum
49
Inverse Square Relationship
50
Ch.22 Homework
  • Read sections 22.1 22.2 (no math in either),
    22.3-22.4 and 22.7
  • Questions 1, 3, 5, 10 13
  • Problems 5-6, 9 16
  • Due Tomorrow

51
Ch.22 Homework Answers
  • 5. 1.88E10 Hz
  • 6. 1.008E-10 m
  • 9. 8.33min
  • 16. radio hears 0.14s soon

52
Physics of Sight
  • We see an object in one of two ways
  • The object is a source of light (sun, fire, light
    bulb filament)
  • The object reflects light
  • Reflected Light rays scatter from each point on
    an object.
  • Our brains construct the image of an object
    assuming that the light entering our eyes travels
    in straight lines.

53
Law of Reflection
  • The angle of reflection is equal to the angle of
    incidence.

?1
?2
?1
?2
54
Plane Mirrors
  • The image formed by a plane mirror is a virtual
    image (cannot be projected onto a screen)

55
Spherical Mirrors
  • Concave mirrors reflect incoming parallel light
    rays so that they pass through a common focal
    point
  • Convex mirrors reflect incoming parallel light
    rays so that they appear like they are coming
    from a focal point behind the mirror.

56
Spherical Mirrors
  • C Center of curvature
  • F focal point
  • r radius of curvature
  • f focal length

C
F
C
F
f
57
Spherical Aberration
  • Technically speaking spherical mirrors do not
    focus the rays perfectly. And the more spherical
    a mirror is, the more the image will appear
    blurred. This defect is called spherical
    aberration. For very sensitive applications
    parabolic mirrors are used.

http//wisp.physics.wisc.edu/astro104/lecture7/F06
_13.jpg
58
Concentrating Solar Power (CSP) Plants
  • The suns rays are focused on pipe filled a fluid
    to collect the energy in order to generate
    electricity.

http//images.google.com/imgres?imgurlhttp//www.
flabeg.com/images/g_03_solar_mirrors.jpgimgrefurl
http//www.flabeg.com/en/03_solar_mirrors.htmlh
385w385sz25hlenstart120um1tbnid2JjpA8c
5Og3NrMtbnh123tbnw123prev/images3Fq3Dpara
bolic2Bmirror26start3D10826ndsp3D1826um3D1
26hl3Den26rls3Dcom.microsoft26sa3DN
http//en.wikipedia.org/wiki/Solar_thermal_energy
High-Temperature_Collectors_Concentrated_solar_po
wer_.28CSP.29_plants
59
Drawing Ray Diagram Rules
  • Rule 1 Draw a ray going out from the object
    parallel to the principal axis that reflects back
    through the focal point.

60
Drawing Ray Diagram Rules
  • Rule 2 Draw a ray that goes through the focal
    point (or in a direction like it came from the
    focal point) then reflects back parallel to the
    axis.

61
Drawing Ray Diagram Rules
  • Rule 3 Draw a ray from the object through the
    center of curvature. This ray will strike the
    mirror at a right angle and will reflect back on
    itself.

62
r gtobject distance gt f
focal point is
Image is Real, larger inverted
63
object distance lt f
Image is Virtual, larger upright
64
Ray Diagram for Convex Mirror
Image is always Virtual, smaller upright
focal point is (-)
Uses rear view mirror, convenience store mirror
65
The Mirror Equation
  • h0 is always ()
  • hi is () if upright, (-) if inverted with
    respect to the object
  • ()si ? image in front of mirror
  • (-) si ? image behind mirror
  • f () for concave mirrors, (-) for convex mirrors

66
Example Problem 23-4
  • A 10cm-tall object is placed 12cm in front of a
    convex mirror that has a radius of curvature of
    35cm. Completely describe the reflected image.
    (What is its location? Its height? Is it real or
    virtual? Upright or inverted?)

si -7.1cm, hi 5.92cm, virtual and upright
67
Example Problems 23-4 and 23-5
  • A concave mirror with a radius of curvature of
    14cm is used to focus the Suns rays. Where are
    the rays focused, relative to the surface of the
    mirror?
  • You are standing 3.0m from a convex security
    mirror in a store. You estimate the height of
    your image to be half of your actual height.
    Estimate the focal point of the mirror.

7cm from the surface of the mirror at the focal
point
f -3m
68
Refraction
  • All lenses redirect light rays by the process of
    refraction

n1
n2
?2
?1
69
Lenses
  • Lenses can be grouped into two main categories
    converging and diverging lenses.

70
Ray Diagrams for Lenses
71
Example Problem
  • Use a ray diagram to show the image height and
    position for the given object.

F
F
72
Thin Lens Calculations
  • The mirror equation still applies, but now its
    called the thin lens equation. (The magnification
    equation is still the same, too.)
  • Sign conventions for using the equations are
    somewhat different now
  • s0 is () if it is on the same side of the lens
    as the incoming light which is most of the time.
  • If si is () then the image is on the opposite
    side of the incoming light, (-) if on the same
    side.
  • f is () for converging lenses, (-) for diverging
    lenses.

73
Multiple Lenses
  • If two thin lenses in a row are used to form an
    image, first find the image of the first lens
    alone. Then the light approaches a 2nd lens as if
    it had come from the image. This means that the
    image formed by lens 1 becomes the object for
    lens 2.

F
74
Multiple Lenses
  • The magnification for multiple lenses is just the
    product of the individual magnifications of lens
    1 2.
  • (Example) Two converging lenses, each of focal
    length 20cm, are place 50cm apart from one
    another, and an object is place 10cm to the left
    of the first lens. Where is the final image
    formed, and what is the magnification of the
    entire system?
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