4.5 REINFORCED EARTH (terre armee) - PowerPoint PPT Presentation

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4.5 REINFORCED EARTH (terre armee)

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4.5 reinforced earth (terre armee) ... the strips are laid in the layers of the fill and bolted to the retaining wall ... amount of clay size (2mm):10 % design ... – PowerPoint PPT presentation

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Title: 4.5 REINFORCED EARTH (terre armee)


1
4.5 REINFORCED EARTH (terre armee)
  • FILLS CAN BE FORMED PLACING "REINFORCEMENTS" IN
    THEM AND COMPACTING (GLASS FIBRE REINFORCED,
    PLASTIC FIBRE, TRYLENE FIBRE, FLEXIBLE GALVANISED
    STEEL STRIPS ETC.) ( 5 MM THICK FLEXIBLE). THE
    STRIPS ARE LAID IN THE LAYERS OF THE FILL AND
    BOLTED TO THE RETAINING WALL AT THE FACING OF THE
    FILL. THESE STRIPS EXTEND SUFFICIENTLY FAR INTO
    THE SOIL BEHIND THE WALL. THE MAIN IDEA IS THAT
    WHEN SLIDING STARTS TO OCCUR IN THE SOIL (ZONE 1)
    THE ANCHORED STRIPS WILL PROVIDE A COMPLEMENTARY
    SHEAR STRENGTH (ZONE 2) AND THERE WILL STOP
    FURTHER DEFORMATION.

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  • FILL MATERIAL - SEVERAL SPEC'S
  • GENERALLY SHOULD BE GRANULAR IN NATURE
  • PARTICLES D lt 80 mM SHOULD BE lt 15
  • MAX. PARTICLE SIZE 350 MM
  • MAX. 25 OF THE FILL gt 150 MM
  • ANOTHER SPEC MAX. PARTICLE SIZE 125 MM 63 mM
    PASSING lt 10
  • OR
  • IF 63 mM PASSING gt10
  • LL lt45 PIlt20
  • (WL ) (IP )
  • HOWEVER MAX. AMOUNT OF CLAY SIZE (2mm)10 DESIGN

5
  • HORIZONTAL AND VERTICAL STRIP SPACINGS Sh Sv
    Schlosser Mc Kittr.
  • AT DEPTH Z, STRIP TENSION
  • Ts K . sv . Sh . Sv Ministere
    de Trans.
  • K for z lt 6 m
  • K for z gt 6 m KKA

Earth pressure coefficient
Calculated vertical stress e.g. using Meyerhofs
coeff. distribution)
6
  • THIS IS BASED ON THE OBSERVATIONS OF FULL SCALE
    WALLS SF 3 IS USED TO ULTIMATE TENSILE STRENGTH
    OF GALVANISED STEEL.
  • BOND FAILURE
  • Effective bond length is that projecting beyond
    the "failure surface"
  • If not measured in a shear box coefficient of
    friction is taken to be 0.40 for plain strips and
    tan f' for ribbed strips or 0.90 (arc tan 42) (m
    atanf', a 0.46-0.50, plain strips 0.48 tan 40
    0.40)

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  • FOR H lt 6 M F IS ASSUMED TO REDUCE LINEARLY FROM
    UNITY AT THE FREE SURFACE TO TANf' AT A DEPTH OF
    6 M.
  • TAKING A FACTOR OF SAFETY OF 1.5 AGAINST BOND
    FAILURE THE REQUIRED BOND LENGTH LA AT DEPTH Z IS

Ministere desTransports 1979
8
  • LA IS 0.8H OR 5 M WHICH EVER IS GREATER.
    THIS IS INTERNAL STABILITY. THE STRUCTURE MUST
    BE CHECKED FOR EXTERNAL STABILITY. LET US GO
    THROUGH THE STEPS.
  • I. CHECK STABILITY OF EACH LAYER BY CALCULATING
    THE MAX. TENSILE FORCE T. PER METER RUN OF WALL
    TO BE RESISTED IN ith LAYER. THIS FORCE IS TAKEN
    TO BE THE SUM OF THE TENSIONS CREATED BY FIVE
    POSSIBLE LOADINGS.

9
Due to bending moment cause by external loading
on wall
Due to KA.g.zi
Due to surcharge q
Due to horizontal loading at top
Due to strip loading at top of wall
10
  • II. HAVING EVALUATED Ti CHECK TENSILE FAILURE
    PULL - OUT FAILURE

F.S.
total length of each reinforcement in the ith
layer.
Required reinforcement perimeter per meter run of
wall
11
  • III. ONCE THE STABILITY OF EACH AND EVERY LAYER
    OF REINFORCEMENT HAS BEEN CHECKED THE OVERALL
    STABILITY OF SEVERAL TRIAL WEDGES IS CHECKED
    USING A GRAPHICAL METHOD.

Effective bond length
12


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