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Title: 14_Lecture.ppt


1
Chapter 14 NMR Spectroscopy
Organic Chemistry 6th Edition Paula Yurkanis
Bruice
2
Nuclear Magnetic Resonance (NMR) Spectroscopy
Identify the carbonhydrogen framework of an
organic compound
Certain nuclei, such as 1H, 13C, 15N, 19F, and
31P, have non-zero value for their spin quantum
number this property allows them to be studied
by NMR
3
The spin state of a nucleus is affected by an
applied magnetic field
4
The energy difference between the spin states
increases with the strength of the applied
magnetic field
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An NMR Spectrometer
In pulsed Fourier transform (FT) spectrometers,
the magnetic field is held constant, and a radio
frequency (rf) pulse of short duration excites
all the protons simultaneously
7
The electrons surrounding a nucleus decrease the
effective magnetic field sensed by the nucleus
Beffective Bo Blocal
8
Chemically equivalent protons protons in the
same chemical environment
Each set of chemically equivalent protons in a
compound gives rise to a signal in an 1H NMR
spectrum of that compound
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The Chemical Shift
The reference point of an NMR spectrum is defined
by the position of TMS (zero ppm)
The chemical shift is a measure of how far the
signal is from the reference signal
11
1H NMR spectrum of 1-bromo-2,2-dimethylpropane
The greater the chemical shift, the higher the
frequency
The chemical shift is independent of the
operating frequency of the spectrometer
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Protons in electron-poor environments show
signals at high frequencies
Electron withdrawal causes NMR signals to appear
at higher frequency (at larger d values)
14
Characteristic Values of Chemical Shifts
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Diamagnetic Anisotropy
The unusual chemical shifts associated with
hydrogens bonded to carbons that form p bonds
The p electrons are freer to move than the s
electrons in response to a magnetic field
18
The protons show signals at higher frequencies
because they sense a larger effective magnetic
field
benzene
19
The alkene and aldehyde protons also show signals
at higher frequencies
alkene
aldehyde
20
The alkyne proton shows a signal at a lower
frequency than it would if the p electrons did
not induce a magnetic field
alkyne
21
1H NMR spectrum of 1-bromo-2,2-dimethylpropane
The area under each signal is proportional to the
number of protons giving rise to the signal
22
Integration Line
The area under each signal is proportional to the
number of protons that give rise to that signal
The height of each integration step is
proportional to the area under a specific signal
The integration tells us the relative number of
protons that give rise to each signal, not the
absolute number
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Splitting of the Signals
  • An 1H NMR signal is split into N 1 peaks,
    where N is
  • the number of equivalent protons bonded to
    adjacent
  • carbons
  • Coupled protons split each others signal
  • The number of peaks in a signal is called the
    multiplicity
  • of the signal
  • The splitting of signals, caused by spinspin
    coupling,
  • occurs when different kinds of protons are
    close to one
  • another

25
It is not the number of protons giving rise to a
signal that determines the multiplicity of the
signal
It is the number of protons bonded to the
immediately adjacent carbons that determines the
multiplicity
a a triplet b a quartet c a singlet
26
Equivalent protons do not split each others
signal
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The ways in which the magnetic fields of three
protons can be aligned
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Splitting is observed if the protons are
separated by no more than three s bonds
Long-range coupling occurs over ?systems, such as
benzene
32
More Examples of 1H NMR Spectra
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The three vinylic protons are at relatively high
frequency because of diamagnetic anisotropy
35
The signals for the Hc, Hd, and He protons
overlap because the electronic effect of an ethyl
substituent is similar to that of a hydrogen
36
The signals for the Ha, Hb, and Hc protons do not
overlap because of the strong electron-withdrawing
property of the nitro group
37
Coupling Constants
The coupling constant (J) is the distance between
two adjacent peaks of a split NMR signal in hertz
Coupled protons have the same coupling constant
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Summary
1. The number of chemical shifts ? specify the
number of proton environments in the compound
2. The chemical shift ??values specify the nature
of the chemical environment alkyl, alkene, etc.
3. The integration values specify the relative
number of protons
4. The splitting specifies the number of
neighboring protons
5. The coupling constants specify the orientation
of the coupled protons
40
A Splitting Diagram for a Doublet of Doublets
41
Complex Splitting
JAC JAB Triplet
JAC gt JAB Doublet of doublets
42
The trans coupling constant is greater than the
cis coupling constant
43
A Splitting Diagram for a Quartet of Triplets
44
Why is the signal for Ha a quintet rather than a
triplet of triplet?
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The Difference between a Quartet and a Doublet
of Doublets
47
When two different sets of protons split a
signal, the multiplicity of the signal is
determined by using the N 1 rule separately for
each set of the hydrogens, as long as the
coupling constants for the two sets are different
When the coupling constants are similar, the
multiplicity of a signal can be determined by
treating both sets of adjacent hydrogens as
though they were equivalent
48
Replacing one of the enantiotopic hydrogens by a
deuterium or any other atom or group other than
CH3 or OH forms a chiral molecule
prochiral carbon
Ha is the pro-R-hydrogen, whereas Hb is the
pro-S-hydrogen and they are chemically
equivalent
49
Diastereotopic hydrogens have different chemical
shifts
50
Diastereotopic hydrogens are not chemically
equivalent
51
The three methyl protons are chemically
equivalent because of rotation about the CC
bond
We see one signal for the methyl group in the 1H
NMR spectrum
52
1H NMR spectra of cyclohexane-d11 at various
temperatures
axial
equatorial
equatorial
axial
The rate of chairchair conversion
is temperature dependent
53
Protons Bonded to Oxygen and Nitrogen
The greater the extent of the hydrogen bond, the
greater the chemical shift
These protons can undergo proton exchange
They always appear as broad signals
54
pure ethanol
ethanol with acid
55
A 60-MHz 1H NMR spectrum
A 300-MHz 1H NMR spectrum
56
To observe well-defined splitting patterns, the
difference in the chemical shifts (in Hz) must be
10 times the coupling constant values
57
13C NMR Spectroscopy
  • The number of signals reflects the number of
    different
  • kinds of carbons in a compound.
  • The overall intensity of a 13C signal is about
    6400 times
  • less than the intensity of an 1H signal.
  • The chemical shift ranges over 220 ppm.
  • The reference compound is TMS.

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Proton-Decoupled 13C NMR of 2-Butanol
61
Proton-Coupled 13C NMR of 2-Butanol
62
The intensity of a signal is somewhat related to
the number of carbons giving rise to it
Carbons that are not attached to hydrogens give
very small signals
63
DEPT 13C NMR distinguishes CH3, CH2, and CH
groups
64
The COSY spectrum identifies protons that are
coupled
Cross peaks indicate pairs of protons that are
coupled
65
COSY Spectrum of 1-Nitropropane
66
The HETCOR spectrum of 2-methyl-3-pentanone indica
tes coupling between protons and the carbon to
which they are attached
67
Unknown Identification Using Spectroscopy
Example 1 13C-NMR of C5H9Br
68
Example 1 1H-NMR of C5H9Br
69
Example 1 IR of C5H9Br
Answer
70
Example 2 13C-NMR of C6H10O4
71
Example 2 1H-NMR of C6H10O4
72
Example 2 IR of C6H10O4
Answer
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