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Angular Momentum

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Angular Momentum AP Physics C Mrs. Coyle http://a.espncdn.com/media/oly/2005/1024/photo/g_kwan_195.jpg Remember: Torque t=r x F = rFsinf Cross Product The cross ... – PowerPoint PPT presentation

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Title: Angular Momentum


1
Angular Momentum
  • AP Physics C
  • Mrs. Coyle

http//a.espncdn.com/media/oly/2005/1024/photo/g_k
wan_195.jpg
2
Remember Torque
  • tr- x F rFsinf

3
Cross Product
  • The cross product of two vectors AxB is a third
    vector that is perpendicular to the plane of A
    and B (according to the right hand rule).

4
Properties of the Cross Product
  • 1) AxB-BxA (not commutative)
  • 2) AxA0 (or if A is // B, AxB0)
  • 3)AxBAB, when A __ B

5
Properties of the Cross Product, Contd
  • 4) Ax(BC)AxB AxC (distributive)
  • 5)

6
Properties of Cross Products of Unit Vectors
  • ixi0
  • jxj0
  • kxk0
  • ixjk
  • jxkI
  • kxij

7
Using Determinants
  • or

8
Example 3
  • Two vectors are given by A-3i4j and B2i3j.
  • Find
  • a)AxB
  • b) the angle between A and B
  • Ans a)-17.0k, b)70.6o

9
Angular Momentum, L
  • For a particle of mass m at position r and
    linear momentum p.

10
Angular Momentum, L r x p
  • The instantaneous angular momentum of a
    particle relative to the origin is defined as the
    cross product of the particles instantaneous
    position vector r and its instantaneous linear
    momentum p
  • L r x p

11
Angular Momentum
  • L r mv sin f
  • is the angle between r and p .
  • Remember pmv

12
Rotational Analog of Newtons Second Law
  • St and L must be measured about the same origin.
  • For origin fixed in an inertial frame.

13
Units of Angular Momentum
  • SI units (kg.m2)/ s

14
Direction of Angular Momentum
  • The magnitude and direction of L depend on the
    choice of origin
  • The direction of L is perpendicular to the plane
    formed by r and p.

15
Example Uniform Circular Motion
  • A particle in uniform circular motion has a
    constant angular momentum about an axis through
    the center of its path.

16
Angular Momentum of a System of Particles
  • The vector sum of the angular momenta of the
    individual particles
  • Ltot L1 L2 Ln SLi

17
Note
  • Any torques associated with the internal forces
    acting in a system of particles are zero.
  • So

18
Resultant Torque about the CM
  • The resultant torque acting on a system about an
    axis through the center of mass equals the time
    rate of change of angular momentum of the system
    regardless of the motion of the center of mass
    (even if the center of mass is accelerating).

19
Ex 11
  • A light rod 1.00m in length joins two
    particles, with masses 4kg and 3kg at its ends.
    The combination moves in the xy plane about a
    pivot the center of the rod, counterclockwise.
    Determine the angular momentum of the system
    about the origin when the speed of each particle
    is 5m/s.
  • Ans 17.5k kg m2 /s
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