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MECH 221 FLUID MECHANICS (Fall 06/07) Tutorial 7

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MECH 221 FLUID MECHANICS (Fall 06/07) Tutorial 7 Outline Conservation of Momentum (Navier-Stokes Equation) Dimensional Analysis Buckingham Pi Theorem Normalization ... – PowerPoint PPT presentation

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Title: MECH 221 FLUID MECHANICS (Fall 06/07) Tutorial 7


1
MECH 221 FLUID MECHANICS(Fall 06/07)Tutorial 7
2
Outline
  1. Conservation of Momentum(Navier-Stokes Equation)
  2. Dimensional Analysis
  3. Buckingham Pi Theorem
  4. Normalization Method

3
1. Conservation of Momentum (Navier-Stokes
Equations)
  • In Chapter 3, for inviscid flows, only pressure
    forces act on the control volume V since the
    viscous forces (stress) were neglected and the
    resultant equations are the Eulers equations.
    The equations for conservation of momentum for
    inviscid flows were derived based on Newtons
    second law in the Lagrangian form.

4
1. Conservation of Momentum (Navier-Stokes
Equations)
  • Eulers equation
  • This is the Integral Form of Eulers equation.


5
1. Conservation of Momentum (Navier-Stokes
Equations)
  • This is the Differential Form of Eulers
    equation.


6
1. Conservation of Momentum (Navier-Stokes
Equations)
  • Here we should include the viscous stresses to
    derive the momentum conservation equations.
  • With the viscous stress, the total stress on the
    fluid is the sum of pressure stress(
    , here the negative sign implies that tension is
    positive) and viscous stress ( ), and is
    described by the stress tensor given by

7
1. Conservation of Momentum (Navier-Stokes
Equations)
  • Here, we generalize the body force (b) due to all
    types of far field forces. They may include those
    due to gravity , electromagnetic force,
    etc.
  • As a result, the total force on the control
    volume in a Lagrangian frame is given by

8
1. Conservation of Momentum (Navier-Stokes
Equations)
  • The Newtons second law then is stated as
  • Hence, we have

9
1. Conservation of Momentum (Navier-Stokes
Equations)
  • By the substitution of the total stress into the
    above equation, we have
  • which is integral form of the momentum
    equation.

10
1. Conservation of Momentum (Navier-Stokes
Equations)
  • For the differential form, we now apply the
    divergence theorem to the surface integrals to
    reach
  • Hence, V?0, the integrands are independent of V.
    Therefore,
  • which are the momentum equations in differential
    form for viscous flows. These equations are also
    named as the Navier-Stokes equations.

11
1. Conservation of Momentum (Navier-Stokes
Equations)
  • For the incompressible fluids where
    constant.
  • If the variation in viscosity is negligible
    (Newtonian fluids), the continuity equation
    becomes , then the shear stress tensor
    reduces to .

12
1. Conservation of Momentum (Navier-Stokes
Equations)
  • The substitution of the viscous stress into the
    momentum equations leads to
  • where is the Laplacian operator
    which in a Cartesian coordinate system reads

13
2.1 Buckingham Pi Theorem
  • Given the quantities that are required to
    describe a physical law, the number of
    dimensionless product (the Pis, Np) that can
    be formed to describe the physics equals the
    number of quantities (Nv) minus the rank of the
    quantities, i.e., NpNv Nm,

14
2.1 Example
  • Viscous drag on an infinitely long circular
    cylinder in a steady uniform flow at free stream
    of an incompressible fluid.
  • Geometrical similarity is automatically satisfied
    since the diameter (R) is the only length scale
    involved.

15
2.1 Example
  • Dynamics similarity

16
2.1 Example
  • Both sides must have the same dimensions!

17
2.1 Example
  • where is the kinematic viscosity.
  • The non-dimensional parameters are

18
2.1 Example
  • Therefore, the functional relationship must be of
    the form
  • The number of dimensionless groups is Np2

19
2.1 Example
  • The matrix of the exponents is
  • The rank of the matrix (Nm) is the order of the
    largest non-zero determinant formed from the rows
    and columns of a matrix, i.e. Nm3.

20
2.1 Example
  • Problems
  • No clear physics can be based on to know the
    involved quantities
  • Assumption is not easy to
    justified.

21
2.2 Normalization Method
  • The more physical method for obtaining the
    relevant parameters that govern the problem is to
    perform the non-dimensional normalization on the
    Navier-Stokes equations
  • where the body force is taken as that due to
    gravity.

22
2.2 Normalization Method
  • As a demonstration of the method, we consider the
    simple steady flow of incompressible fluids,
    similar to that shown above for steady flows past
    a long cylinder.
  • Then the Navier-Stokes equations reduce to

23
2.2 Normalization Method
  • If the proper scales of the problem are
  • Here the flow domain under consideration is
    assumed such that the scales in x, y and z
    directions are the same

24
2.2 Normalization Method
  • Using these scales, the variables are normalized
    to obtain the non-dimensional variables as
  • Note that the non-dimensional variable with
    are of order one, O(1).
  • The velocity scale U and the length scale L are
    well defined, but the scale P remains to be
    determined.

25
2.2 Normalization Method
  • The Navier-Stokes equations then become
  • where is the unit vector in the direction of
    gravity which is dimensionless.

26
2.2 Normalization Method
  • The coefficient of in the continuity
    equation can be divided to yield
  • Dividing the momentum equations by in
    the first term of left hand side gives

27
2.2 Normalization Method
  • Since the quantities with are of O(1), the
    coefficients appeared in each term on the right
    hand side measure the ratios of each forces to
    the inertia force. i.e.,
  • where Re is called as Reynolds number and Fr as
    Froude number.

28
2.2 Normalization Method
  • Conservation of mass
  • Conservation of momentum

29
2.2 Example
  • Given that
  • Velocity U U8cos(?t)
  • Pressure P
  • Length L

30
2.2 Example
  • Momentum conservation equation with viscous
    effect

31
2.2 Example
  • Normalized parameters

32
2.2 Example
  • Normalization

33
2.2 Example
  • Normalization

34
2.2 Example
  • Since

35
The End
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