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8.6 Proportions

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8.6 Proportions & Similar Triangles Geometry Objectives/Assignments Use proportionality theorems to calculate segment lengths. To solve real-life problems, such as ... – PowerPoint PPT presentation

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Title: 8.6 Proportions


1
8.6 Proportions Similar Triangles
  • Geometry

2
Objectives/Assignments
  • Use proportionality theorems to calculate segment
    lengths.
  • To solve real-life problems, such as determining
    the dimensions of a piece of land.
  • Assignment pp. 502-503 1-30

3
Use Proportionality Theorems
  • In this lesson, you will study four
    proportionality theorems. Similar triangles are
    used to prove each theorem.

4
Theorems 8.4 Triangle Proportionality Theorem
If a line parallel to one side of a triangle
intersects the other two sides, then it divides
the two side proportionally. If TU QS, then
RT
RU

TQ
US
5
Theorems 8.5 Converse of the Triangle
Proportionality Theorem
If a line divides two sides of a triangle
proportionally, then it is parallel to the third
side.
RT
RU
If
, then TU QS.

TQ
US
6
Ex. 1 Finding the length of a segment
  • In the diagram AB ED, BD 8, DC 4, and AE
    12. What is the length of EC?

7
  • Step
  • DC EC
  • BD AE
  • 4 EC
  • 8 12
  • 4(12)
  • 8
  • 6 EC
  • Reason
  • Triangle Proportionality Thm.
  • Substitute
  • Multiply each side by 12.
  • Simplify.



EC
  • So, the length of EC is 6.

8
Ex. 2 Determining Parallels
  • Given the diagram, determine whether MN GH.

LM
56
8


MG
21
3
LN
48
3


NH
16
1
8
3
?
3
1
MN is not parallel to GH.
9
Theorem 8.6
  • If three parallel lines intersect two
    transversals, then they divide the transversals
    proportionally.
  • If r s and s t and l and m intersect, r, s,
    and t, then

UW
VX

WY
XZ
10
Theorem 8.7
  • If a ray bisects an angle of a triangle, then it
    divides the opposite side into segments whose
    lengths are proportional to the lengths of the
    other two sides.
  • If CD bisects ?ACB, then

AD
CA

DB
CB
11
Ex. 3 Using Proportionality Theorems
  • In the diagram ?1 ? ?2 ? ?3, and PQ 9, QR
    15, and ST 11. What is the length of TU?

12
SOLUTION Because corresponding angles are
congruent, the lines are parallel and you can use
Theorem 8.6
PQ
ST
Parallel lines divide transversals proportionally.

QR
TU
9
11

Substitute
15
TU
9 ? TU 15 ? 11 Cross Product property
15(11)
55

TU

Divide each side by 9 and simplify.
9
3
  • So, the length of TU is 55/3 or 18 1/3.

13
Ex. 4 Using the Proportionality Theorem
  • In the diagram, ?CAD ? ?DAB. Use the given side
    lengths to find the length of DC.

14
Solution
  • Since AD is an angle bisector of ?CAB, you can
    apply Theorem 8.7. Let x DC. Then BD 14 x.

AB
BD

Apply Thm. 8.7
AC
DC
9
14-X
Substitute.

15
X
15
Ex. 4 Continued . . .
9 ? x 15 (14 x) 9x 210 15x 24x
210 x 8.75
Cross product property Distributive Property Add
15x to each side Divide each side by 24.
  • So, the length of DC is 8.75 units.

16
Use proportionality Theorems in Real Life
  • Example 5 Finding the length of a segment
  • Building Construction You are insulating your
    attic, as shown. The vertical 2 x 4 studs are
    evenly spaced. Explain why the diagonal cuts at
    the tops of the strips of insulation should have
    the same length.

17
Use proportionality Theorems in Real Life
  • Because the studs AD, BE and CF are each
    vertical, you know they are parallel to each
    other. Using Theorem 8.6, you can conclude that

DE
AB

EF
BC
  • Because the studs are evenly spaced, you know
    that DE EF. So you can conclude that AB BC,
    which means that the diagonal cuts at the tops of
    the strips have the same lengths.

18
Ex. 6 Finding Segment Lengths
  • In the diagram KL MN. Find the values of the
    variables.

19
Solution
  • To find the value of x, you can set up a
    proportion.

9
37.5 - x

Write the proportion Cross product
property Distributive property Add 13.5x to each
side. Divide each side by 22.5
13.5
x
13.5(37.5 x) 9x 506.25 13.5x 9x
506.25 22.5 x 22.5 x
  • Since KL MN, ?JKL ?JMN and

JK
KL

JM
MN
20
Solution
  • To find the value of y, you can set up a
    proportion.

9
7.5

Write the proportion Cross product
property Divide each side by 9.
13.5 9
y
9y 7.5(22.5)
y 18.75
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