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Title: Acids and Bases


1
Acids and Bases
2
Acids
  • Svante Arrhenius, a Swedish chemist, defines an
    acid as a substance that yields hydrogen ions
    (H) when dissolved in water.
  • Formulas for acids contain one or more ionizable
    hydrogen atoms as well as an anion.

3
Naming Acids
  • In some cases two different names seem to be
    assigned to the same chemical formula.
  • HCl(g) hydrogen chloride
  • HCl(l) hydrogen chloride
  • HCl(aq) hydrochloric acid
  • The name assigned to the compound depends on its
    physical state. In the gaseous or pure liquid
    state, HCl is a molecular compound called
    hydrogen chloride. When it is dissolved in
    water, the molecules break apart into H and Cl-
    ions in this state, the substance is called
    hydrochloric acid.

4
  • Binary acids (formed by hydrogen and one other
    element) are named with a hydro- prefix and an
    -ic ending on the anion root.
  • Ex- HCl
  • HBr

Hydrochloric acid
Hydrobromic acid
5
  • The formulas for oxoacids, (acids that contain
    hydrogen and an anion containing oxygen) are
    usually written with the H first, followed by the
    anion, as illustrated in the following examples
  • H2CO3 HNO3 HClO2

Carbonic acid
Nitric acid
Chlorous acid
If the anion ends in -ate then the acid ends in
-ic, if the anion ends in -ite, then the acid
ends in -ous. Remember, ic goes with the
higher oxidation state, N has an oxidation state
of ___ in HNO3 (nitric acid) and ___ in HNO2
(nitrous acid)
5
3
6
Acids
  • Acids have a sour taste for example, vinegar
    owes its sourness to acetic acid, and lemons and
    citrus fruits contain citric acid.
  • Acids cause color changes in plant dyes for
    example, they change the color of blue litmus to
    red.
  • Acids react with certain metals to produce
    hydrogen gas.
  • Acids react with carbonates and bicarbonates to
    produce carbon dioxide gas.
  • Aqueous acid solutions conduct electricity.

7
Brønsted Acid
  • Arrheniuss definitions of acids are limited in
    that they apply only to aqueous solutions.
    Broader definitions were proposed by the Danish
    chemist Johannes Brønsted. A Brønsted acid is a
    proton donor.
  • HCl(aq) H(aq) Cl-

Remember, the H ion is really just a proton (a
hydrogen atom is one proton and one electron, you
pull off the electron and all you are left with
is
8
  • The size of a proton is about 10-15 m, compared
    to the diameter of 10-10 m for an average atom or
    ion. Such an exceedingly small charged particle
    cannot exist as a separate entity in aqueous
    solution owing to its strong attraction for the
    negative region of the polar water molecule.
    Consequently, the proton exists in a hydrated
    form as H3O, and is referred to as the hydronium
    ion
  • H H2O H3O

9
  • Since the acidic properties of the proton are
    unaffected by hydration, we will generally use
    H(aq) to represent the hydrated proton. This
    notation is for convenience only, because H3O is
    closer to reality. Keep in mind that both
    notations represent the same species in aqueous
    solution.

H(aq) H3O(aq)
10
  • Monoprotic acids
  • each unit of acid yields one hydrogen upon
    ionization
  • Diprotic acids
  • each unit of an acid gives up two H ions
  • Triprotic acids
  • yields three H ions upon ionization

HCl
H2CO3
H3PO4
11
  • Diprotic acids give up their two H ions in
    separate steps
  • H2SO4(aq) H(aq) HSO4-(aq)
  • HSO4-(aq) H(aq) SO4-2(aq)
  • Triprotic acids give up their H ions in three
    separate steps.

Is HSO4- a strong or weak acid? Explain
Weak, only partially ionizes
12
Bases
  • In another definition formulated by Svante
    Arrhenius, a base can be described as a substance
    that yields hydroxide ions (OH-) when dissolved
    in water. Some examples are
  • NaOH
  • KOH
  • Ba(OH)2

Sodium hydroxide
Potassium hydroxide
Barium hydroxide
13
  • Ammonia (NH3) is also classified as a common
    base. At first glance this may seem to be an
    exception to the definition of a base. Note that
    as long as a substance yields hydroxide ions when
    dissolved in water, it need not contain hydroxide
    ions in its structure to be considered a base.
    In fact, when ammonia dissolves in water, the
    following reaction occurs
  • NH3 H2O NH4 OH-

Thus it is properly classified as a base.
14
Bases
  • Bases have a bitter taste
  • Bases feel slippery for example, soaps, which
    contain bases, exhibit this property
  • Bases cause color changes in plant dyes for
    example, they change the color of red litmus to
    blue
  • Aqueous base solutions conduct electricity

15
Brønsted Base
  • A Brønsted base is defined by Johannes Brønsted
    as being a substance capable of accepting a
    proton.

16
Lewis Acids and Bases
  • G.N. Lewis formulated a definition for what is
    now called a Lewis base a substance that can
    donate a pair or electrons. A Lewis acid is a
    substance that can accept a pair of electrons.

17
  • The significance of the Lewis concept is that it
    is much more general than other definitions. For
    example, the reaction between boron trifluoride
    and ammonia is a Lewis acid-base reaction.

18
Strength of Acids and Bases
  • Strong acids are strong electrolytes, which, for
    practical purposes, are assumed to ionize
    completely in water. That means that at
    equilibrium, solutions of strong acids will not
    contain any nonionized acid molecules.
  • Like strong acids, strong bases are all strong
    electrolytes that ionize completely in water.

19
  • The most common strong acids are HClO4, HCl, HNO3
    and H2SO4. Hydroxides of alkali metals and
    alkaline Earth metals are strong bases (like
    NaOH, KOH and Ba(OH)2).
  • Other strong acids and strong bases are listed on
    your Relative Strengths of Acids and Bases
    Reference Sheet.

20
  • The strength of an acid is measured by its
    tendency to ionize
  • HX ? H X-
  • The strength of the H-X bond influences the
    extent to which an acid undergoes ionization.
    The stronger the bond (the higher the bond
    dissociation energy in kJ/mol), the more
    difficult it is for the HX molecule to break up
    and hence the weaker the acid.

21
Bond Dissociation Energies for Hydrogen Halides
and Acid Strengths
Bond Bond Dissociation Energy (kJ/mol) Acid Strength
H-F 568.2
H-Cl 431.9
H-Br 366.1
H-I 298.3
weak
strong
strong
strong
22
The Strength of Oxoacids
Oxoacids contain hydrogen, oxygen, and one other
element Z, which occupies a central position. To
compare oxoacid strength, it is convenient to
separate the oxoacids into two groups.
23
Oxoacids having different central atoms that are
from the same group of the periodic table and
that have the same oxidation number. Within this
group, acid strength increases with increasing
electronegativity of the central atom.
HClO3 gt HBrO3
24
Oxoacids having the same central atom but
different numbers of attached groups. Within
this group, acid strength increases as the
oxidation number of the central atom increases.
HClO4 gt HClO3 gt HClO2 gt HClO
Which of the following should be a stronger acid,
sulfurous or sulfuric?
H2SO4 gt H2SO3
25
  • You are going to remember these trends because
  • HCl is a strong acid and HF (with the higher bond
    dissociation energy) isnt.
  • HClO4 is a strong acid and HClO3 (where the Cl
    has a lower oxidation number because it has fewer
    oxygen atoms attached to it) isnt.

26
  • Note H3O is the strongest acid that can exist
    in aqueous solutions. Acids stronger than H3O
    react with water to produce H3O and their
    conjugate bases.
  • Thus, HCl, which is a stronger acid than H3O,
    reacts with water completely to form H3O and
    Cl-.
  • HCl(aq) H2O(l) H3O(aq) Cl-(aq)

27
  • The OH- ion is the strongest base that can exist
    in aqueous solution. Bases stronger than OH-
    react with water to produce OH- and their
    conjugate acids.
  • For example, the oxide ion, (O-2) is a stronger
    base than OH-, so it reacts with water completely
    as follows
  • O-2(aq) H2O(l) ? 2OH-(aq)
  • For this reason, the oxide ion does not exist in
    aqueous solutions.

28
Amphoteric Compounds
As you could see from the previous two examples,
water will act as either an acid or a base,
depending on the strength of the acid or base
with which it is reacting. Any species that can
react as either an acid or a base is described as
amphoteric.
H2SO4(aq) H2O(l) ? H3O(aq) HSO4-(aq)
Proton acceptor (base)
  • NH3(g) H2O(l) ? OH-(aq) NH4(aq)

Proton donor (acid)
29
  • An extension of the Brønsted definition of acids
    and bases is the concept of the conjugate
    acid-base pair

CH3COOH(aq) H2O(l) CH3COO-(aq)
H3O(aq)
A conjugate acid-base pair is defined as an acid
and its conjugate base (whats left after the H
was removed from the acid) or a base and its
conjugate acid (substance formed by the addition
of the H to the base).
Because the acid and base are always stronger
than the conjugate acid and conjugate base, the
direction of the reaction proceeds from acid/base
? conjugate acid/conjugate base.
30
  • Identify the acid, base, conjugate acid and
    conjugate base in the following reaction
    (Reaction proceeds from stronger to weaker)
  • NH3(aq) H2O(l) NH4(aq) OH-(aq)

31
The Acid-Base Properties of Water
  • Water is a very weak electrolyte and therefore a
    poor conductor of electricity, but it does
    undergo ionization to a small extent
  • H2O(l) H(aq) OH-(aq)

This reaction is sometimes called the
autoionization of water.
32
  • In the study of acid-base reactions in aqueous
    solutions, the hydrogen ion concentration is the
    key, because it indicates the acidity or
    alkalinity of the solution. Expressing the
    hydrogen ion as H, we can write the equilibrium
    constant for the autoionization of water as

kw
33
  • kw HOH-
  • kw is called the ion-product constant, and is the
    product of the molar concentrations of H and OH-
    ions at a particular temperature.

34
  • In pure water at 25 oC, the concentrations of H
    and OH- ions are equal and found to be H 1.0
    x 10-7 M and OH- 1.0 x 10-7 M. Thus,
  • kw HOH-
  • kw (1.0 x 10-7)(1.0 x 10-7)
  • kw 1.0 x 10-14

35
  • Whether we have pure water or an aqueous solution
    of dissolved species, the following relation
    ALWAYS holds at 25 oC
  • kw HOH- 1.0 x 10-14

36
Because HCl is a strong acid HCl ? H Cl-
  • Calculate the concentration of OH- ions in an HCl
    solution whose hydrogen ion concentration is 1.3
    M.

37
  • pH A Measure of Acidity

Because the concentrations of H and OH- ions in
aqueous solutions are frequently very small
numbers and therefore inconvenient to work with,
Soren Sorensen in 1909 proposed a more practical
measure called pH. The pH of a solution is
defined as the negative logarithm of the hydrogen
ion concentration (in mol/L) pH -log H
pH is a dimensionless quantity (it will not have
a label)
38
Since pH is simply a way to express hydrogen ion
concentration, acidic and basic solutions at 25
oC can be distinguished by their pH values, as
follows Acidic solutions H gt 1.0 x 10-7 M,
pH lt 7.00 In an acidic solution there is an
excess of H ions H gt OH- Basic
solutions H lt 1.0 x 10-7 M, pH gt 7.00 In a
basic solution there is an excess of OH- ions
OH- gt H Neutral solutions H 1.0 x 10-7
M, pH 7.00 Whenever H OH-, the aqueous
solution is said to be neutral.
Note when concentration has two significant
figures, pH will have two numbers TO THE RIGHT OF
THE DECIMAL!
39
  • Calculate the pH of a 1.0 x 10-3 M HCl solution.

40
  • The concentration of H ions in a bottle of table
    wine was 3.2 x 10-4 M right after the cork was
    removed. Only half of the wine was consumed.
    The other half, after it had been standing open
    to the air for a month, was found to have a
    hydrogen ion concentration equal to 1.0 x 10-3 M.
    Calculate the pH of the wine on these two
    occasions.

When the wine was first opened After the wine
sat for a month
Why did the acidity increase?
Some of the ethanol converted to acetic acid, a
reaction that takes place in the presence of O2.
41
  • Given the pH of a solution, you can figure out
    the H concentration by using the simple
    formula
  • H 10-pH

What is the hydrogen ion concentration of an acid
with a pH of 3.00?
42
A pH meter is commonly used in the laboratory to
determine the pH of a solution. Although many pH
meters have scales marked with values from 1 to
14, pH values can, in fact, be less than 1 and
greater than 14.
43
A pOH scale analogous to the pH scale can be
devised using the negative logarithm of the
hydroxide ion concentration of a solution. Thus
we define pOH as pOH -logOH-
44
Now consider again the ion-product constant for
water kw HOH- 1.0 x 10-14 Taking the
negative logarithm of both sides we
obtain -logH -logOH- -log(1.0 x 10-14)
Logs make adders multiply
-logH -logOH- 14.00
pH
pOH
45
  • In a NaOH solution OH- is 2.9 x 10-4 M.
    Calculate the pH of the solution.

First, figure out the pOH
Then use the pOH to figure out the pH
46
  • Calculate the pH of a 0.0020 M Ba(OH)2 solution.

47
  • To determine the hydroxide ion when given the
    pOH, you need to use the formula
  • 10-pOH OH-

What is the molarity of a NaOH solution that has
a pH of 11.30?
48
Weak Acids and Acid Ionization Constants
  • Most acids are weak acids, which ionize only to a
    limited extent in water. At equilibrium, aqueous
    solutions of weak acids contain a mixture of
    nonionized acid molecules, H3O ions, and the
    conjugate base.
  • The limited ionization of weak acids is related
    to the equilibrium constant for ionization, which
    is represented as ka.

49
  • Consider a weak monoprotic acid, HA. Its
    ionization in water is represented by
  • HA(aq) H2O(l) H3O(aq) A-(aq)
  • or simply
  • HA(aq) H(aq) A-(aq)

50
  • Write the equilibrium expression for the
    ionization of HA.

ka, the acid ionization constant, is the
equilibrium constant for the ionization of an
acid.
51
  • At a given temperature, the strength of the acid
    HA is measured quantitatively by the magnitude of
    ka. The larger ka, the stronger the acid that
    is, the greater the concentration of H ions at
    equilibrium due to its ionization. Keep in mind,
    however, that only weak acids have ka values
    associated with them.

52
  • You have a reference sheet that lists a number of
    weak acids and their ka values at 25 oC.
    Although all of the acids on that sheet are weak,
    within the group there is great variation in
    their strengths.
  • For example, ka for HF (6.8 x 10-4) is about 1.5
    million times greater than that for HCN (6.2 x
    10-10).

53
  • Generally, we can calculate the hydrogen ion
    concentration or pH of an acid solution at
    equilibrium, given the initial concentration of
    the acid and its ka value.
  • Alternatively, if we know the pH of a weak acid
    solution and its initial concentration, we can
    determine its ka.

54
  • Suppose we are asked to calculate the pH of a
    0.50 M HF solution at 25 oC. The ionization of
    HF is given by

55
  • The first step is to identify all the species
    present in solution that may affect its pH.
    Because weak acids ionize to a small extent, at
    equilibrium the major species present are
    nonionized HF and some H and F- ions.
  • Another major species is H2O, but its very small
    Kw (1.0 x 10-14) means that water is not a
    significant contributor to the H ion
    concentration. Therefore, unless otherwise
    stated, we will always ignore the H or OH- ions
    produced by the autoionization of water.

56
  • HF(aq) H(aq) F-(aq)
  • We can summarize the changes in the
    concentrations of HF, H, and F- in the table
    below

HF(aq) H(aq) F-(aq)
I
C
E
57
  • The equilibrium concentrations of HF, H and F-,
    expressed in terms of the unknown x, are
    substituted into the ionization constant
    expression to give

(x)(x) 0.50 - x
Ka
6.8 x 10-4
Rearranging this expression, we write
x2 6.8 x 10-4x 3.4 x 10-4 0
58
  • This is a quadratic equation which can be solved
    using the quadratic formula. Or, we can try
    using a shortcut to solve for x.
  • Because HF is a weak acid and weak acids ionize
    only to a slight extent, we reason that x must be
    small compared to 0.50. Therefore we can make
    the approximation
  • 0.50 x 0.50

59
  • Now the ionization constant expression becomes

x2 0.50 - x
x2 0.50
6.8 x 10-4

Rearranging, we get x2 (0.50)(6.8 x 10-4)
3.4 x 10-4 x v3.4 x 10-4 0.018 M
60
  • Thus we have solved for x without having to use
    the quadratic equation. At equilibrium, we have

HF H F-
(0.50 0.018) M 0.48 M
0.018 M
This is determined by going back to the ICE chart
0.018 M
And the pH of the solution is
pH -log(0.018) 1.74
61
  • How good is this approximation? The
    approximation is valid if the following
    expression is equal to or less than 5

Molarity of H at equilibrium
Initial concentration of weak acid
If this is greater than 5, you must use the
quadratic formula
62
The Quadratic Equation
  • -b vb2 4ac
  • 2a

x
The values from the equation shown below, (from
slide 57), can now be substituted in to the
quadratic equation.
x2 6.8 x 10-4x 3.4 x 10-4 0
a 1 b 6.8 x 10-4 c -3.4 x 10-4
63
  • -b vb2 4ac
  • 2a

x
-6.8 x 10-4 v(6.8 x 10-4)2 4(1)(-3.4 x 10-4)
2(1)
x
-6.8 x 10-4 ?.0014 2(1)
x
Note this is the same value as we estimated
earlier!
x .018 M or -.018 M
The second solution is physically impossible
because the concentration of ions produced as a
result of ionization cannot be negative.
pH -log(0.018) 1.74
64
Suppose we decrease the concentration of the HF
solution to .05M. What is the new pH?
65
Percent Ionization
  • We have seen that the magnitude of ka indicates
    the strength of an acid. Another measure of the
    strength of an acid is its percent ionization,
    which is defined as

H concentration at equilibrium Initial
concentration of acid
Percent ionization
X 100
66
  • The stronger the acid, the greater the percent
    ionization.
  • The extent to which a weak acid ionizes depends
    on the initial concentration of the acid. The
    more dilute the solution, the greater the percent
    ionization.

67
Diprotic and Polyprotic Acids
  • The treatment of diprotic and polyprotic acids is
    more involved than that of monoprotic acids
    because these substances yield more than one
    hydrogen atom per molecule.
  • These acids ionize in a stepwise manner, that is,
    they lose one proton at a time.
  • An ionization constant expression should be
    written for each ionization step.

68
  • Oxalic acid (H2C2O4) is a poisonous substance
    used chiefly as a bleaching and cleansing agent
    (for example, to remove bathtub rings).
    Calculate the concentrations of all the species
    present at equilibrium in a 0.10 M solution.
    Oxalic acids ka 5.6 x 10-2

69
  • H2C2O4 H HC2O4-

H2C2O4(aq) H(aq) HC2O4-(aq)
I (M)
C (M)
E (M)
Let me save you some work, you need to use the
quadratic formula for this one
70
  • When the equilibrium for the first stage of
    ionization is reached, the concentrations are

H HC2O4- H2C2O4
71
  • Next we consider the second stage of ionization.
  • At this stage, the major species will be HC2O4-,
    (this serves as the acid in the second stage),
    H, and C2O4-2 (the conjugate base).

72
HC2O4- H C2O4-2
HC2O4-(aq) H(aq) C2O4-2(aq)
I (M) 0.052 0.052 0.00
C (M)
E (M)
73
HC2O4-2 HC2O4-
Ka
5.4 x 10-5
Let me save you some work, you DONT need to use
the quadratic formula for this one, 0.052 y and
0.052 y 0.052
74
  • Testing the approximation - checking the 5 rule

75
  • At equilibrium

H2C2O4 HC2O4- H C2O4-2
76
  • This example shows that for diprotic acids, if
    ka1 ka2, then we can assume that the
    concentration of H ions is the product of only
    the first stage of ionization.

77
Calculate the pH of a .25 M solution of sulfurous
acid.
78
Weak Bases and Base Ionization Constants
  • Weak bases, like weak acids, are weak
    electrolytes.
  • Ammonia is a weak base that ionizes only to a
    limited extent in water
  • NH3(aq) H2O(l) NH4 OH-(aq)

79
  • The equilibrium constant is given by

NH4OH- NH3
kb
Where kb is called the base ionization constant.
80
  • Follow the same procedures you used with weak
    acids when solving problems involving weak bases.
  • The main difference is that you will calculate
    OH- first, rather than H.

81
The Relationship Between the Ionization Constants
of Acids and Their Conjugate Bases
  • For any conjugate acid-base pair it is always
    true that
  • kakb kw

82
  • Calculate the Kb of the conjugate base of acetic
    acid

83
Acid Base Properties of Salts
  • Salts (which are one of the products of an
    acid-base neutralization reaction) are strong
    electrolytes that completely dissociate into ions
    in water. The term salt hydrolysis describes the
    reaction of an anion or a cation of a salt, or
    both, with water. Salt hydrolysis usually
    affects the pH of a solution.

84
Salts that Produce Neutral Solutions
  • NaNO3 Na NO3-

85
Salts that Produce Neutral Solutions
  • NaNO3 Na NO3-

86
Salts that Produce Neutral Solutions
  • NaNO3 Na NO3-

Consequently, NaNO3 and other salts formed from a
strong acid and a strong base do not affect the
pH of a solution.
87
Salts that Produce Basic Solutions
  • NaCH3COO Na CH3COO-

88
Salts that Produce Basic Solutions
  • NaCH3COO Na CH3COO-

89
Salts that Produce Basic Solutions
  • CH3COO- OH- CH3COOH

Because the CH3COO- ions would bond with the H
ions, the OH- ions (which are left behind when
the H ions come off of the water molecules)
affect the pH of the solution. In other words,
solutions produced by salts made from strong
bases and weak acids will be basic in nature.
90
Salts that Produce Acidic Solutions
  • NH4Cl NH4 Cl-

91
Salts that Produce Acidic Solutions
  • NH4Cl NH4 Cl-

NH3 H
Because the Cl- ions wouldnt bond with the H
ions, and the H ion that would separate from the
NH4, it would leave excess H in solution. In
other words, solutions produced by salts made
from strong acids and weak bases will be acidic
in nature.
92
  • When the cation of a salt comes from a weak base
    and the anion comes from a weak acid, you need to
    compare the ka and kb values to determine if the
    solution will be acidic or basic. For example,
  • NH4NO2 NH4 NO2-
  • Ka 5.7 x 10-10 NH4 NH3 H
  • Kb 1.4 x 10-11 NO2- HNO2 OH-

If Kb gt Ka, the solution will be basic, if Ka gt
Kb, the solution will be acidic..
therefore an aqueous solution of NH4NO2 will be
acidic.
93
  • Oxides can be classified as acidic, basic, or
    amphoteric.
  • All alkali metal oxides and all alkaline earth
    metal oxides except BeO are basic.
  • Beryllium oxide and several metallic oxides in
    the boron family (Group 3A) and carbon family
    (Group 4A) are amphoteric.

Na2O H2O ?
2NaOH
2Ba(OH)2
BaO H2O ?
94
  • Nonmetalic oxides that react with water to form
    acids are sometimes referred to as acidic
    anhydrides.

CO2 H2O ?
H2CO3
SO3 H2O ?
H2SO4
N2O5 H2O ?
2HNO3
4H3PO4
P4O10 H2O ?
2HClO4
Cl2O7 H2O ?
95
Buffer Solutions
  • A buffer solution is a solution of (1) a weak
    acid or a weak base and (2) its salt both
    components must be present. The solution has the
    ability to resist changes in pH upon the addition
    of small amounts of either acid or base.
  • Buffers are very important to chemical and
    biological systems. The pH in the human body
    varies greatly from one fluid to another for
    example, the pH of blood is about 7.4, whereas
    the gastric juice in our stomach has a pH of
    about 1.5. These pH values, which are crucial
    for proper enzyme function and the balance of
    osmotic pressure, are maintained by buffers in
    most cases.

96
CH3COOH CH3COO- H
  • NaCH3COO CH3COO- Na

If you add a base to this solution, the OH- will
be neutralized by the acetic acid in the buffer,
therefore you will not notice a significant
difference in the pH of the solution.
97
CH3COOH CH3COO- H
  • NaCH3COO CH3COO- Na

If you add an acid to this solution, the acetate
ion will bond to the H, so no appreciable change
in pH will be observed because it is such a small
increase in H
98
  • The buffering capacity, that is, the
    effectiveness of the buffer solution, depends on
    the amount of acid and conjugate base from which
    the buffer is made. The larger the amount, the
    greater the buffering capacity.

99
  • In general, a buffer system can be represented as
    salt-acid or conjugate base-acid. Thus the
    sodium acetate-acetic acid buffer system we
    discussed can be written as
  • CH3COONa/CH3COOH
  • or simply
  • CH3COO-/CH3COOH.

100
  • Which of the following are buffer systems?

NaClO4/HClO4
KF/HF
101
A "very convenient" equation for dealing with
buffer solutions is the Henderson-Hasselback
equation.
A- HA
pH pKa log
102
  1. Calculate the pH of a buffer system containing
    1.0 M CH3COOH and 1.0 M CH3COONa.
  2. What is the pH of the buffer system after the
    addition of 0.10 mole of gaseous HCl to 1 L of
    the solution. Assume that the volume of the
    solution does not change when the HCl is added.

103
  • To appreciate the effectiveness of the
    CH3COONa/CH3COOH buffer, let us find out what
    would happen if 0.10 mol HCl were added to 1 L of
    water, and compare the increase in H ion
    concentration.

104
Calculate the pH of a buffer system containing
.50 M C6H5COOH and 1.0 M C6H5COOK.
105
What is the pH of the previous buffer system
after the addition of 0.10 mole of gaseous HCl to
1 L of the solution. Assume that the volume of
the solution does not change when the HCl is
added.
106
Acid Base Titrations
  • Quantitative studies of acid-base neutralization
    reactions are most conveniently carried out using
    a technique known as titration. In titration, a
    solution of accurately known concentration,
    called a standard solution, is added gradually to
    another solution of unknown concentration, until
    the chemical reaction between the two solutions
    is complete.

107
  • If we know the volumes of the standard solution,
    we can calculate the concentration of the unknown
    solution.
  • Sodium hydroxide is one of the bases commonly
    used in the laboratory. However, it is difficult
    to obtain solid sodium hydroxide in a pure form
    because it is hygroscopic, (it has a tendency to
    absorb water from air), and its solution reacts
    with carbon dioxide. For these reasons, a
    solution of sodium hydroxide must be standardized
    before it can be used in accurate analytical
    work.

108
  • We can standardize the sodium hydroxide solution
    by titrating it against an acid solution of
    accurately known concentration. The acid often
    chosen for this task is a monoprotic acid called
    potassium hydrogen phthalate (abbreviated as
    KHP), for which the molecular formula is KHC8H4O4.

109
  • The procedure for the titration of KHP and NaOH
    is as follows
  • Add a known amount of KHP to an Erlenmeyer flask.
    Add some distilled water to make up a solution.
  • Next, carefully add NaOH solution from a buret
    until the equivalence point is reached. The
    equivalence point is the point at which the acid
    has completely reacted with or been neutralized
    by the base.

110
  • The equivalence point is usually signaled by a
    sharp change in the color of an indicator. In an
    acid-base titration, indicators are substances
    that have distinctly different colors in acidic
    and basic solutions. One common indicator is
    phenolphthalein.

Phenolphthalein indicates the presence of a/n
_________. Phenolphthalein is ________ in acidic
solutions, _______ in neutral solutions and
________ in basic solutions.
base
colorless
colorless
pink
111
  • At the equivalence point, all the KHP present has
    been neutralized by the added NaOH and the
    solution is still colorless. However, if we add
    just one more drop of NaOH solution from the
    buret, the solution will immediately turn pink
    because the solution is now basic.

112
Apparatus for acid-base titration.
A NaOH solution is added from the buret to a KHP
solution in an Erlenmeyer flask.
A faint pink color appears when the equivalence
point is reached. If your solution turns
fuchsia, you have gone past the equivalence point
113
  • The neutralization reaction between NaOH and KHP
    is one of the simplest types of acid-base
    neutralization known. A neutralization reaction
    is a reaction between an acid and a base.
  • Aqueous strong acid-strong base reactions produce
    water and a salt, (an ionic compound made up of a
    cation other than H and an anion other than OH-
    or O-2)

114
  • The reaction between KHP and sodium hydroxide is
  • KHC8H4O4(aq) NaOH(aq) ? KNaC8H4O4(aq) H2O(l)

acid
base
salt
water
115
  • You can use the following format to solve
    acid-base neutralization problems

116
What is the molarity of the acid if 16.1 mL of
0.610 M NaOH was required to neutralize 20.0 mL
of H2SO4?
117
The reaction between HCl, a strong acid, and
NaOH, a strong base, can be represented by
HCl(aq) NaOH(aq) ? NaCl(aq) H2O(l)
The pH profile of the titration of this
neutralization reaction is known as a titration
curve.
118
  • Consider the addition of 0.10 M NaOH solution
    (from a buret) to an Erlenmeyer flask containing
    25 mL of 0.10 M HCl.

119
  • It is possible to calculate the pH of a solution
    at every stage of titration.
  • What is the pH of the solution after the addition
    of 10.0 mL of 0.10 M NaOH to 25.0 mL of 0.10 M
    HCl?

120
  • At the equivalence point of a titration between a
    weak acid and a strong base, the pH will be
    greater than 7.

121
at neutralization
  • Because
  • CH3COOH NaOH ? CH3COONa H2O

CH3COO- Na
This acetate ion has an affinity for the H ion
in the water, (thus leaving the OH- behind,
making the solution basic.)
122
The pka of a weak acid can be determined
experimentally
The flat portion of the titration curve before
the equivalence point is called the buffer
region. In this part of the pH scale, the acid
and conjugate base are both present in
significant concentrations and the solution
resists changes in pH. As base is added to a
solution in this buffer region, acetic acid
reacts with it to form acetate ion, without a
large change in pH.
123
At the half-equivalence point, CH3COOH
CH3COO-, so   Ka H3O
1/2 way
In the middle of the buffer region lies the
half-equivalence point. Here the volume of base
added is half that required to reach the
equivalence point and half the acetic acid has
been converted to the conjugate base, acetate
ion. This means that the concentrations of acetic
acid and acetate ion are equal. If we examine the
equilibrium expression at the half-equivalence
point, we find something interesting
124
At the half-equivalence point, CH3COOH
CH3COO-, so   ka H3O
Taking the negative log of both sides yields pka
pH ka 10-pH This gives us an experimental
way to determine the ka of a weak acid, and using
a ka table, the identity of an unknown weak acid.
125
Predict the identity of the weak acid that was
titrated against the NaOH.
126
  • A slightly different curve results when you
    titrate a strong acid vs a weak base. At the
    equivalence point of a titration between a strong
    acid and a weak base, the pH will be less than 7.

127
  • Because
  • HCl NH3 ? NH4Cl

at neutralization
NH3 H
The pH of less than 7 is due to the presence of
H ions formed by the hydrolysis of NH4
128
Acid-Base Indicators
  • An indicator is usually a weak organic acid or
    base that has distinctly different colors in its
    nonionized (molecular) form and ionized form.
    The end point of a titration occurs when the
    indicator changes color.
  • However, not all indicators change color at the
    same pH, so the choice of indicator for a
    particular titration depends on the nature of the
    acid and base used in the titration (that is,
    whether they are strong or weak).
  • By choosing the proper indicator for a titration,
    we can use the end point to determine the
    equivalence point.

129
  • Let us consider a weak monoprotic acid that we
    will call HIn. To be an effective indicator, HIn
    and its conjugate base, ___, must have distinctly
    different colors.

In-
One color
A different color
130
  • If the indicator is in a sufficiently acidic
    environment, the equilibrium, according to Le
    Chateliers principle, shifts to the __________
    and the predominant color will be that of ______,

left
HIn
131
  • In a basic environment, the equilibrium shifts to
    the right because

The H and the OH- will form water, thus removing
the H from the system and therefore shifting the
equilibrium to the right. The predominant color
will then be that of In-.
132
  • The end point of an indicator does not occur at a
    specific pH rather, there is a range of pH
    within which the end point will occur. In
    practice, we choose an indicator whose end point
    lies on the steep part of the titration curve.
    Because the equivalence point also lies on the
    steep part of the curve, this choice ensures that
    the pH at the equivalence point will fall within
    the range over which the indicator changes color.

133
Some Common Acid-Base Indicators
Indicator In acid In base pH range
Thymol blue Red Yellow 1.2 - 2.8
Bromophenol blue Yellow Bluish purple 3.0 4.6
Methyl orange Orange Yellow 3.1 4.4
Methyl red Red Yellow 4.2 6.3
Chlorophenol blue Yellow Red 4.8 6.4
Bromothymol blue Yellow Blue 6.0 7.6
Cresol red Yellow Red 7.2 8.8
Phenolphthalein Colorless Reddish pink 8.3 10.0
The pH range is defined as the range over which
the indicator changes from the acid color to the
base color.
134
  • This is THE END of your CHEM II NOTES!!!
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