System Function of discrete-time systems - PowerPoint PPT Presentation

About This Presentation
Title:

System Function of discrete-time systems

Description:

System Function of discrete-time systems System representation Where the input signal is {x(n)} of z-transform X(z) The output is {y(n)} of z-transform Y(z). – PowerPoint PPT presentation

Number of Views:216
Avg rating:3.0/5.0
Slides: 37
Provided by: Professor48
Category:

less

Transcript and Presenter's Notes

Title: System Function of discrete-time systems


1
System Function of discrete-time systems
  • System representation
  • Where the input signal is x(n) of z-transform
    X(z)
  • The output is y(n) of z-transform Y(z).

2
System Function of discrete-time systems
  • The system has an impulse response h(n)
  • Define so that
  • and hence
  • Clearly when X(z) 1 then G(z) Y(z) i.e. G(z)
    is the z-transform of the impulse response h(n)

3
Frequency Response
  • Let the input be
  • Then the output is
  • Where
  • and

4
System Function of discrete-time systems
  • However
  • While the amplitude phase responses are
  • And hence

5
System Functions-Amplitude response
  • Evidently
  • And hence
  • Thus
  • ie for real systems amplitude is an even
    function, and phase an odd function of frequency

6
System Functions-Amplitude response
  • Moreover from
  • Since at is finite we
    obtain

7
System Functions-Phase response
  • From
  • At we have
  • Thus for real systems the amplitude response must
    approach zero frequency with zero slope, while
    the phase rsponse must be zero at the origin

8
System Functions-Phase response
  • For ,
  • Hence

9
System Functions-Group delay
  • Thus
  • where

10
Suppression of a frequency band
  • A real rational transfer function H(z) cannot
    suppress a band of frequencies completely.
  • i.e. cannot be identically zero for
  • in
  • This may be demonstrated as follows

11
System Function of discrete-time systems
  • To produce a zero at say we must
    have in the numerator of H(z) a factor of the
    form
  • Therefore for one zero in the band
    the factor is
  • and since there are an infinite number of points
    in the band we need factors in the numerator as

12
System Function of discrete-time systems
  • Clearly the result is not a rational function
  • Hence it cannot be the transfer function of a
    digital signal processing system.

13
Stability Test
  • For stability a DSP transfer function must have
    poles inside the unit circle on the z-plane.
  • We need to have a means of determining whether
    the denominator of a given transfer function has
    all its zeros inside the unit circle.
  • The procedures for doing so are called stability
    tests.

14
Stability Test
  • Let the transfer function to be tested be
  • where n is the order of the transfer function.
    Set A 1.
  • For stability Dn(z) must have no zeros in
    the region

15
Stability Test
  • Consider the simple case of a quadratic
    denominator
  • Rewrite as (ignore the factor )
  • If the roots are complex, say
  • then

16
Stability Test
  • Thus and
  • For stability and thus
  • For real roots
  • If choose root with largest
    absolute value and make less than 1

17
Stability Test
  • Thus
  • And since quantities are positive we obtain
  • Similarly for
  • Thus jointly we have

18
Stability Test
  • These conditions form the Stability Triangle

Stability region inside triangle
19
Stability Test
  • For higher order functions most tests rely on an
    iterative precedure that involves
  • reduction of the polynomial degree by unity
  • a simple test
  • Jury-Marden Test We write Dn(z) as
  • where is a constant chosen to make of
    degree (n - 1)

20
Stability Test
  • Repeat equation
  • Hence
  • And thus
  • Set
  • so that
  • is of degree (n-1) when

21
Stability Test
  • Rouches Theorem If the polynomials and
    are such that in the same region
  • then has the same number of
    zeros in that region as

22
Stability Test
  • we observe that Dn(z) has as many zeros as
    either or
    depending on whether
  • or
  • Ie or

23
Stability Test
  • Thus if then is
    unstable as it has as many zeros as
    which has at most (n - 1) zeros within z lt 1.
  • If then can have as
    many zeros within z lt 1 as
  • The zero at z 0 can be removed and the
    procedure repeated for the remaining polynomial

24
Stability Test
  • An alternative test Consider
  • So that
  • For this equation to be a polynomial we require
    the constant term in the numerator to be zero so
    as to be able to cancel through a factor z

25
Stability Test
  • Thus or
  • The rest of the argument is similar to the
    previous case

26
Further Stability Test
  • Given that and
  • show that on the unit circle for any real
  • Construct
  • Repeat the previous arguments

27
Digital Two-Pairs
  • The LTI discrete-time systems considered so far
    are single-input, single-output
  • Often such systems can be efficiently realised by
    interconnecting two-input, two-output structures,
    known as two-pairs

28
Digital Two-Pairs
  • Figures below show two commonly used block
    diagram representations of a two-pair
  • Here and denote the two outputs, and
    and denote the two inputs, where the
    dependencies on the variable z has been omitted
    for simplicity

29
Digital Two-Pairs
  • The input-output relation of a digital two-pair
    is given by
  • In the above relation the matrix t given by
  • is called the transfer matrix of the two-pair

30
Digital Two-Pairs
  • An alternate characterisation of the two-pair is
    in terms of its chain parameters as
  • where the matrix G given by
  • is called the chain matrix of the two-pair

31
Digital Two-Pairs
  • The transfer and chain parameters are related as

32
Two-Pair Interconnections
  • Cascade Connection - G-cascade
  • Here

33
Two-Pair Interconnections
  • But from figure, and
  • Substituting the above relations in the first
    equation on the previous slide and combining the
    two equations we get
  • Hence,

34
Two-Pair Interconnections
  • Cascade Connection - t-cascade
  • Here

35
Two-Pair Interconnections
  • But from figure, and
  • Substituting the above relations in the first
    equation on the previous slide and combining the
    two equations we get
  • Hence,

36
Two-Pair Interconnections
  • Constrained Two-Pair
  • It can be shown that

H(z)
Write a Comment
User Comments (0)
About PowerShow.com