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Rectangular Codes

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1. Rectangular Codes. Triplication codes: m1 m2 m3. m1m1m1 m2m2m2 m3m3m3 ... Error detection and correction. Slides based on unknown ous contributor on ... – PowerPoint PPT presentation

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Title: Rectangular Codes


1
Rectangular Codes
  • Triplication codes

m1 m2 m3
Repeated 3 times
m1m1m1 m2m2m2 m3m3m3
At receiving end, a majority vote is taken.
2
Error detection and correction
  • Slides based on unknown ous contributor on the
    web

3
  • Rectangular codes
  • Redundancy

m -1
o o o o xo o o o xo
o o o x
o o o
o xx x x x x
o message positionx check position
n -1
sum mod 2
Itd better use even-parity checking to avoid
contradiction
4
  • For a given size mn, the redundancy will be
    smaller the more the rectangle approaches a
    square.
  • For square codes of size n ,we have (n -1)2
    bits of information. And 2n-1 bits of checking
    along the sides.
  • Note that Rectangular codes also can correct
    bursty error.
  • (k21)x(k11) array codeIf k2 ? 2(k1-1) ? we
    can correct k1 size of bursty errors

5
3.4 Hamming Error-correcting codes
  • Find the best encoding scheme for single-error
    correction for white noise.
  • Suppose there are m independent parity checks.
    ?It means no sum of any combination of the checks
    is any other check.
  • Example check 1 1 2 5 7
    --- (1) check 2
    5 7 8 9 --- (2)
    check 3 1 2 8 9 --- (3)
    It is not independent, because (1)(2)(3)
  • So third parity check provides no new information
    over that of the first two, and is simply wasted
    effort.

6
  • The syndrome which results from writing a 0 for
    each of the m parity checks that is correct and 1
    for each failure can be viewed as an m-bit number
    and can represent at most 2m things.
  • For n bits of the message, 2m ? n 1
  • It is optimal when meets the equality
    condition. ( Hamming Codes )
  • Using Syndrome to find out the position of
    errors. The ideal situation is to use the value
    of Syndrome to point out the position of errors.

7
  • Example 0 0 0 ? no error 0 0 1
    ? error happened in the first position

8
  • Locate errorcheck1 m1 m3 m5 m70check2
    m2 m3 m6 m70check3 m4 m5 m6 m70
  • Viewing m1 , m2 , m4 as check bit
  • Note that the check positions are equally
    corrected with the message positions. The code is
    uniform in its protection. Once encoded there is
    no different between the message and the check
    digits.

9
  • Hamming code
  • when m 10, then n 1023original message
    length 1023 10 1013Redundancy
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