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Title: Network and Computer Security (CS 475) Modular Arithmetic


1
Network and Computer Security (CS 475)
Modular Arithmetic
  • Jeremy R. Johnson

2
Introduction
  • Objective To become familiar with modular
    arithmetic and some key algorithmic constructions
    that are important for computer algebra
    algorithms.
  • Modular Arithmetic
  • Modular inverses and the extended Euclidean
    algorithm
  • Fermats theorem
  • Eulers Identity
  • Chinese Remainder Theorem
  • References Rivest, Shamir, Adelman.

3
Modular Arithmetic (Zn)
  • Definition a ? b (mod n) ? n (b - a)
  • Alternatively, a qn b
  • Properties (equivalence relation)
  • a ? a (mod n)
    Reflexive
  • a ? b (mod n) ? b ? a (mod n) Symmetric
  • a ? b (mod n) and b ? c (mod n) ? a ? c (mod n)
    Transitive
  • Definition An equivalence class mod n
  • a x x ? a (mod n) a qn q ? Z

4
Modular Arithmetic (Zn)
  • It is possible to perform arithmetic with
    equivalence classes mod n.
  • a b ab
  • a b ab
  • In order for this to make sense, you must get the
    same answer (equivalence) class independent of
    the choice of a and b. In other words, if you
    replace a and b by numbers equivalent to a or b
    mod n you end of with the sum/product being in
    the same equivalence class.
  • a1 ? a2 (mod n) and b1 ? b2 (mod n) ? a1 b1 ?
    a2 b2 (mod n)
  • a1 b1 ? a2 b2 (mod n)
  • (a q1n) (b q2n) a b (q1 q2)n
  • (a q1n) (b q2n) a b (bq1 aq2
    q1 q2)n

5
Representation of Zn
  • The equivalence classes a mod n, are typically
    represented by the representatives a.
  • Positive Representation Choose the smallest
    positive integer in the class a then the
    representation is 0,1,,n-1.
  • Symmetric Representation Choose the integer
    with the smallest absolute value in the class
    a. The representation is -?(n-1)/2? ,, ?n/2?
    . When n is even, choose the positive
    representative with absolute value n/2.
  • E.G. Z6 -2,-1,0,1,2,3, Z5 -2,-1,0,1,2

6
Modular Inverses
  • Definition x is the inverse of a mod n, if ax ?
    1 (mod n)
  • The equation ax ? 1 (mod n) has a solution iff
    gcd(a,n) 1.
  • By the Extended Euclidean Algorithm, there exist
    x and y such that ax ny gcd(a,n). When
    gcd(a,n) 1, we get ax ny 1. Taking this
    equation mod n, we see that ax ? 1 (mod n)
  • By taking the equation mod n, we mean applying
    the mod n homomorphism ?m Z ? Zm, which maps
    the integer a to the equivalence class a. This
    mapping preserves sums and products.
  • I.E.
  • ?m(ab) ?m(a) ?m(b), ?m(ab) ?m(a) ?m(b)

7
Fermats Theorem
  • Theorem If a ? 0 ? Zp, then ap-1 ? 1 (mod p).
    More generally, if
  • a ? Zp, then ap ? a (mod p).
  • Proof Assume that a ? 0 ? Zp. Then
  • a 2a (p-1)a (p-1)! ap-1
  • Also, since ai ? aj (mod p) ? i ? j (mod
    p), the numbers a, 2a, , (p-1)a are
    distinct elements of Zp. Therefore they are
    equal to 1,2,,(p-1) and their product is equal
    to
  • (p-1)! mod p. This implies that
  • (p-1)! ap-1 ? (p-1)! (mod p) ? ap-1 ? 1 (mod
    p).

8
Euler phi function
  • Definition phi(n) a 0 lt a lt n and
    gcd(a,n) 1
  • Properties
  • ?(p) p-1, for prime p.
  • ?(pe) (p-1)p(e-1)
  • ? (mn) ? (m) ?(n) for gcd(m,n) 1.
  • ?(pq) (p-1)(q-1)
  • Examples
  • ?(15) ?(3) ?(5) 24 8.
    1,2,4,7,8,11,13,14
  • ?(9) (3-1)3(2-1) 23 6 1,2,4,5,7,8

9
Eulers Identity
  • The number of elements in Zn that have
    multiplicative inverses is equal to phi(n).
  • Theorem Let (Zn) be the elements of Zn with
    inverses (called units). If a ? (Zn), then
    a?(n) ? 1 (mod n).
  • Proof. The same proof presented for Fermats
    theorem can be used to prove this theorem.

10
Chinese Remainder Theorem
  • Theorem If gcd(m,n) 1, then given a and b
    there exist an integer solution to the system
  • x ? a (mod m) and x b (mod n).
  • Proof
  • Consider the map x ? (x mod m, x mod n).
  • This map is a 1-1 map from Zmn to Zm ? Zn, since
    if x and y map to the same pair, then x ? y (mod
    m) and x ? y (mod n). Since gcd(m,n) 1, this
    implies that x ? y (mod mn).
  • Since there are mn elements in both Zmn and Zm ?
    Zn, the map is also onto. This means that for
    every pair (a,b) we can find the desired x.

11
Alternative Interpretation of CRT
  • Let Zm ? Zn denote the set of pairs (a,b) where a
    ? Zm and b ? Zn. We can perform arithmetic on Zm
    ? Zn by performing componentwise modular
    arithmetic.
  • (a,b) (c,d) (ab,cd)
  • (a,b)(c,d) (ac,bd)
  • Theorem Zmn ? Zm ? Zn. I.E. There is a 1-1
    mapping from Zmn onto Zm ? Zn that preserves
    arithmetic.
  • (ac mod m, bd mod n) (a mod m, b mod n)(c
    mod m, d mod n)
  • (ac mod m, bd mod n) (a mod m, b mod n)(c
    mod m, d mod n)
  • The CRT implies that the map is onto. I.E. for
    every pair (a,b) there is an integer x such that
    (x mod m, x mod n) (a,b).

12
Constructive Chinese Remainder Theorem
  • Theorem If gcd(m,n) 1, then there exist em and
    en (orthogonal idempotents)
  • em ? 1 (mod m)
  • em ? 0 (mod n)
  • en ? 0 (mod m)
  • en ? 1 (mod n)
  • It follows that aem b en ? a (mod m) and ?
    b (mod n).
  • Proof.
  • Since gcd(m,n) 1, by the Extended Euclidean
    Algorithm, there exist x and y with mx ny
    1. Set em ny and en mx
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