Title: Lecture VII: Agenda Setting
1Lecture VII Agenda Setting
- Recommended Reading
- Romer Rosenthal (1978)
- Baron Ferejohn (1989)
2Lecture VII Agenda Setting
- Recall standard median voter theorem If
- Voters i n (odd) have single-peaked utility
functions over a single good, and - Any voter can freely place a proposal on the
agenda - Then, median voters position dominates, i.e., is
the equilibrium outcome of any sequence of voting
3Lecture VII Agenda Setting
- In most legislatures, access to agenda control is
limited - Agenda setter can secure non-median outcomes
- This result contingent on location of status quo
- e.g., given symmetric, single-peaked utility
functions (e.g. Euclidean, quadratic), agenda
setter can secure p - Further SQ is from median voter, closer p can be
to agenda setters ideal point -
Agenda setter
p
SQ
4Lecture VII Agenda Setting
- Romer Rosenthal (1978) generalize this
situation - Voters utility functions single-peaked, but not
necessarily symmetric - SQ provides different levels of fallback
utility - Main Results
- Median voters position no longer dominates
- What agenda setter can secure hinges on utility
that SQ provides - Absent agenda-setting, cycles may emerge
5Lecture VII Agenda Setting
- If no SQ, E median voters (2s) ideal point
- But if an SQ offers gt Usq1, 1 3 outvote 2 we
could get cycles - If Usq2, setter can obtain E2 Note voter 3 is
pivotal - If Usq3, setter cannot obtain E gt sq
V2(E)
V3(E)
V1(E)
Usq1
Usq3
Usq2
E
E2
6Lecture VII Agenda Setting
- Baron Ferejohn (1989)
- Generalization of Rubenstein bargaining model to
legislative setting where - Number of players / bargainers gt 2
- Majority rule can be used to impose bargains
- Agenda power a function of recognition and
amendment rules (open vs. closed) - Choice of these rules is endogenized
- Main result majority rule closed amendment
procedures generate less equitable distributions
but many equilibria are possible.
7Lecture VII Agenda Setting
- Recall
- Ultimatum game agenda setters power to make a
take-it-or-leave-it offer secures all of the
pie - Finite Repetition in Rubenstein model
- First-mover advantage remains (and increases in
players impatience), but.. - Initial agenda setter has to give other player
their reservation value
8Lecture VII Agenda Setting
- The Model
- Members 1, , n,
- Utility increasing in x, risk-neutral
- Common discount factor, d
- Recognition rule
- Member i has probability pi of being recognized
- Recognition allows i to propose division of x
- xi (x1i, , xni) s.t. ?x ? 1 sq (01, 0n)
- Amendment rule
- Closed or Open
- Voting rule
9Lecture VII Agenda Setting
Leg. 1 Proposes x1
pass
Vote
x11, x21, x31
fail
Recognition
Leg. 2 Proposes x2
pass
x12, x22, x32
Recognition
Vote
fail
Recognition
pass
x13, x23, x33
Vote
Leg. 3 Proposes x3
fail
Recognition
10Lecture VII Agenda Setting
x11, x21, x31
pass
Put Question
Recognition of 2 or 3
x1 gt x2
Leg. 2 Proposes x2
fail
Leg. 1 Proposes x1
Vote on x1 vs x2
x1 lt x2
Recognition of 2 or 3
Recognition
Vote on x1 vs x2
Leg. 3 Proposes x3
Put Question
x11, x21, x31
11Lecture VII Agenda Setting
- An Illustration
- 3 legislators under closed rule
- pi (1/3, 1/3, 1/3), xsq 0, 0, 0
- pi (.4, .4, .2), xsq .2, .2, .1
- Case 1
- The proposer is indifferent over coalition
partners - As pi pj 1/N, all Vi 1/N
- xi 1 1/N, 1/N, 0
12Lecture VII Agenda Setting
- An Illustration
- 3 legislators under closed rule
- pi (1/3, 1/3, 1/3), xsq 0, 0, 0
- pi (.4, .4, .2), xsq .2, .2, .1
- Case 2
- Both 1 2 prefer to coalition with 3 because V3
lt V3 - Thus 3 knows that she is i) the proposer with p
.2 or ii) a member of the majority coalition with
certainty - Further, 3 is indifferent between 1 2 as
coalition partners - Thus, 1 2 know that they are i) the proposer
with p .4 or ii) a member of the majority
coalition with Pr .5
13Lecture VII Agenda Setting
- An Illustration
- 3 legislators under closed rule
- pi (1/3, 1/3, 1/3), xsq 0, 0, 0
- pi (.4, .4, .2), xsq .2, .2, .1
- Case 2
- V1 p1(.9) p2(0) p3(½ .2) (½ 0)
- V2 p2(.9) p1(0) p3(½ .2) (½ 0)
- V3 p3(.8) p1(.1) p2(.1)
14Lecture VII Agenda Setting
- An Illustration
- 3 legislators under closed rule
- pi (1/3, 1/3, 1/3), xsq 0, 0, 0
- pi (.4, .4, .2), xsq .2, .2, .1
- Case 2
- V1 .4(.9) 0 .2(½ .2) 0 .38
- V2 .4(.9) 0 .2(½ .2) 0 .38
- V3 .2(.8) .4(.1) .4(.1) .24
- Counterintuitive legislator 3s smaller V
increases her share of the pie.
15Lecture VII Agenda Setting
- More generally, given equal recognition
probabilities, the expected payoff for any i is,
Probability of being included in majority
coalition continuation value
Probability of Recognition Residual available
to proposer
16Lecture VII Agenda Setting
- How does change to open rule affect results?
- Initial proposer does not know with certainty who
will be recognized after their proposal - Thus, incentive is to propose a distribution that
accounts for possibility that all remaining
members may have opportunity to present
amendments - Distribution becomes increasingly equitable as
- Players become more patient
- As N increases (because insurance coverage
against counter-proposals must be spread more
widely)