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Answers to Matrices Questions

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Exercise 5 See Algebra and Matrices. Change the linear equations shown above into Matrix form. ... Try to solve these equations using the inverse of the ... – PowerPoint PPT presentation

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Title: Answers to Matrices Questions


1
Answers to Matrices Questions
2
Exercise 1 See Introduction to Matrices
  • Work through the slideshow until you are
    confident that you understand the different types
    of matrices and how they work. This is very
    important for the next section.
  • This is something that only you can do.
  • Identify the different types of matrix shown on
    the next page see next.
  • Label each one with size details and name, e.g.
    4x5 matrix, or 6x6 identity matrix see next.

3
Exercise 1 Continued
  • 5 6 This is a 3x1 Column
    Vector. 7
  • 5 6 7 This is a 1x3 Row Vector.
  • 10 12 15 17 This is a 3x2
    Rectangular Matrix. 7 15
  • 9 8 This is a 2x2 Square Matrix. 4
    5
  • 7 0 0 This is a 3x3 Diagonal Matrix
    0 5 0 0 0 2

4
Exercise 1 Continued
  • 0 0 This is a 2x2 Square Zero Matrix.
    0 0
  • 5 6 2 4 1 5 7 3 This is
    a 4x4 Square Matrix. 7 1 5 2
    1 2 8 5
  • 1 0 0 0 1 0 This is a
    3x3 Identity Matrix. 0 0 1
  • 5 0 0 0 5 0 This is
    a 3x3 Scalar Matrix. 0 0 5

5
Exercise 1 Continued
  • Find the Transpose and the Opposite of matrices
    a, b and c.
  • Original Transpose Opposite
  • 5 5 6 7 -5 6 -6
    7 -7
  • 5 6 7 5 -5 -6 -7 6 7
  • 10 12 10 15 7 -10 -12 15
    17 12 17 15 -15 -17 7
    15 -7 -15

6
Exercise 2 See Mathematical Operations on
Matrices 1
  • Add the following matrices, where possible
  • 5 7 12 6 8
    14
  • 10 12 8 12 18 24 15
    17 9 42 24 59 7 15
    4 13 11 28
  • 9 8 7 6 5 4 Not possible
    4 5 6 7 8 9 1 3 2

7
Exercise 2 Continued
  • Subtract the following matrices, where possible
  • 5 - 7 -2 6 8 -2
  • 10 12 - 8 12 2 0 15
    17 9 42 6 -25 7 15
    4 13 3 2
  • 9 8 7 - 6 5 4 Not possible
    4 5 6 7 8 9 1 3 2
  • -9 8 7 - -6 5 4 Not possible
    4 -5 6 7 -8 -9 1 -3
    2

8
Exercise 3 See Mathematical Operations on
Matrices 2
  • Attempt the following Multiplications of Matrices
    by a scalar
  • 3x 1 2 3 3x1 3x2 3x3 3 6 9
    4 5 6 3x4 3x5 3x6 12
    15 18
  • 2x 1 2 3 2x1 2x2 2x3 2 4 6
    4 5 6 2x4 2x5 2x6 8 10 12
  • 5x 1 2 3 5x1 5x2 5x3 5 10
    15 4 5 6 5x4 5x5 5x6 20 25
    30
  • Please note that for Matrix X, 3X2X5X.
  • 4x 2 -3 7 4x2 4x-3 4x7 8 -12
    28 -8 10 9 4x-8 4x10 4x9 -32 40
    36

9
Exercise 3 - Continued
  • Attempt the following Multiplications of
    Matrices
  • 1 2 3 1 (1x1)(2x2) (3x3) 149
    14 14 2
    3
  • 1 2 3 1 (1x1)(2x2)(3x3) 1 4 9
    14 4 5 6 2 (4x1)(5x2)(6x3)
    41018 32 3

10
Exercise 3 - Continued
  • Attempt the following Multiplications of
    Matrices
  • 2 -3 7 8 1 (1x2) (2x-3) (3x7)
    (4x8) -8 10 9 10 2
    (1x-8)(2x10)(3x9)(4x10)
    3 4
    (2) (-6) (21) (32)
    (-8)(20) (27) (40)
    49 79

11
Exercise 4 See Mathematical Operations on
Matrices 3
  • A 2 4 B 1 8 C 3 8 D 1 2
    4 5 1 8 2 5
    0 2
  • Find the determinants of the above matrices.
  • 2 4 (2x5) (4x4) 10-16 -6 4
    5
  • 1 8 (1x8) (8x1) 8-8 0 1 8
  • 3 8 (3x5) (8x2) 15-16 -1 2
    5
  • 1 2 (1x2) (2x0) 2-0 2 0
    2

12
Exercise 4 Continued
  • A 2 4 B 1 8 C 3 8 D 1 2
    4 5 1 8
    2 5 0 2
  • Find the inverse matrix of each of the above
    matrices.
  • detA -6 A-1 1 _5 -4
    -6 -4 2
  • detA 0 A-1 Not solvable because detB 0
  • detA -1 A-1 1 _5 -8
    -1 -2 3
  • detA 2 A-1 1 _2 -2
    2 0 1

13
Exercise 5 See Algebra and Matrices
  • Change the linear equations shown above into
    Matrix form.
  • 2x y 8 and 3x 2y 14
  • 2 1x 8 3 2y 14
  • x 2y 13 and 4x 5y -13
  • 1 2x 13 4 -5y -13
  • 2x 3y 7 and 3x y -6
  • 2 3 x 7 3 -1y -6

14
Exercise 5 Continued
  • Try to solve these equations using the inverse of
    the matrix, as shown.
  • 2x y 8 and 3x 2y 14
  • 2 1x 8 3 2y 14
  • Inverse of 2 1 1 2 -1 2 -1
    3 2 1 -3 2 -3 2
  • Multiply both sides to get 1 0x (16-14)
    2 0 1y (-2428) 4
  • Therefore x2 and y4

15
Exercise 5 Continued
  • Try to solve these equations using the inverse of
    the matrix, as shown.
  • x 2y 13 and 4x 5y -13
  • 1 2x 13 4 -5y -13
  • Inverse of 1 2 1 -5 -2 4
    -5 -13 -4 1
  • Multiply both sides to get 1 -13 0x 1
    (-65)(26) 3 -13 0 -13y -13
    (-52)(-13) 5
  • Therefore x3 and y5

16
Exercise 5 Continued
  • Try to solve these equations using the inverse of
    the matrix, as shown.
  • 2x 3y 7 and 3x y -6
  • 2 3x 7 3 -1y -6
  • Inverse of 2 3 1 -1 -3
    3 -1 -11 -3 2
  • Multiply both sides to get 1 -11 0x 1
    (-7)(18) 1 11 -110 -11y -11
    (-21)(-12) -11-33
  • Therefore x-1 and y3
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