Rate of Return Analysis: Single Alternative - PowerPoint PPT Presentation

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Rate of Return Analysis: Single Alternative

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ROR is the interest rate at which the benefits are equivalent to the costs. ... 1- Descartes Rule of Signs. The total number of real-number roots is always ... – PowerPoint PPT presentation

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Title: Rate of Return Analysis: Single Alternative


1
Chapter 7
  • Rate of Return Analysis Single Alternative

2
Recall
  • ROR is the interest rate at which the benefits
    are equivalent to the costs.
  • PW (Benefits) PW (Costs)
  • NPW (i) 0
  • AW (i)0

3
How to find ROR
  • A- One factor
  • -100 (P/A, i, 5) 0
  • Look for the value in the table. If it is in the
    table, that is
  • your i.
  • If the value is not in the table, it is between
    two other
  • values (one less, one more). Use interpolation to
    find i.
  • B- More than one factor
  • -100 (P/A, i, n) (P/F, i, n)0
  • Find the value than make NPW( i)0.Use trial
  • and error.

4
Problems with ROR
  • 1- Multiple Values In some cash flows, when
    solving for i NPW (i) 0, there is more than
    one answer for i.
  • 2- Computational Difficulty Trial-and Error

5
Multiple Rate of Return
  • Conventional (simple cash flow)
  • There is only one sign change in conventional
    (simple) cash flow.
  • Example
  • Year Cash Flow
  • 0 -10,000
  • 1 3,000
  • 2 3,000
  • 3 3,000
  • 4 3,000
  • There is always one answer for i in a
    conventional cash
  • flow.

6
Non-conventional Cash Flow
  • There is more than one sign change in the cash
    flow.
  • Example
  • Year Cash Flow
  • 0 -10,000
  • 1 3,000
  • 2 3,000
  • 3 3,000
  • 4 3,000
  • 5 -1,000
  • 6 6,000
  • There might be more than one answer for i in a
    non-
  • conventional cash flow.

7
Check for Multiple Answers
  • To see whether a non-conventional cash flow has
  • more than one answer or not we perform the
  • following tests
  • 1- Descartes Rule of Signs
  • The total number of real-number roots is always
  • less than or equal to the number of sign changes
  • in the cash flow.
  • Year Cash Flow Year Cash Flow
  • 0 -10,000 3 5000
  • 1 20,000 4 -2000
  • 2 30,000 5 3000

8
Cumulative Cash Flow Sign Test
  • Norstroms criterion If only one sign change
  • occurs in the cumulative cash flow, then there is
  • one answer for the i. The cash flow should start
  • negatively.
  • Year Cash Flow Year Cumulative Cash Flow
  • 0 -2,000 0 -2,000
  • 1 6,000 1 4,000
  • 2 -2,000 2 2,000
  • 3 1,000 3 3,000
  • 4 -2,000 4 1,000
  • 5 3,000 5 4,000
  • of sign change5 of sign change1

9
Example
  • Arc-bot Technologies, manufacturer of six-axis,
  • electric servo-driven robots, has experienced the
  • cash flows below in a shipping department. (a)
  • Determine the number of possible rate of return
  • values. (b) Find all i values between 0 and
  • 100.
  • Year Expenses, Savings,
  • 0 - 33,000 0
  • 1 - 22,000 19,000
  • 2 - 30,000 97,000
  • 3 - 40,000 25,000
  • 4 - 20,000 29,000

10
Solution
  • Year Expenses, Savings, Net Cash Flow,
  • 0 - 33,000 0
    -33,000
  • 1 - 22,000 19,000 -3,000
  • 2 - 30,000 97,000 67,000
  • 3 - 40,000 25,000 -15,000
  • 4 - 20,000 29,000 9,000
  • There is three sign change in the net cash flow.
  • Therefore, there is three possible answers for i.

11
Solution
  • Net Cash Flow, Cumulative Cash Flow,
  • 0 -33,000 -33,000
  • 1 -3,000 -36,000
  • 2 67,000 31,000
  • 3 -15,000 16,000
  • 4 9,000 25,000
  • There is one sign change in cumulative cash
  • flow. Therefore, there is only one answer for i.

12
Solution
  • NPW (i) 0
  • NPW (i) -33000 -3,000 (P/F, i,1) 67,000
    (P/F, i,2)
  • - 15,000 (P/F, i,3) 9,000 (P/F,
    i,4) 0
  • Solve with trial and error
  • i20
  • NPW - 33,000 -3,000 (P/F, 20,1) 67,000(P/F,
    20, 2) -
  • - 15,000 (P/F, 20,3) 9,000 (P/F,
    20,4)
  • NPW -33,000 -3,000 (0.8333) 67,000 (0.6944) -
  • 15000 (0.5787) 9000 (.4823)
  • NPW 6685.1

13
Solution
  • i30
  • NPW - 33,000 -3,000 (P/F, 30,1) 67,000 (P/F,
    30, 2)
  • 15,000 (P/F, 30,3) 9,000 (P/F,
    30,4)
  • NPW -33,000 -3,000 (0.7692) 67,000 (0.5917) -
  • 15000 (0.4552) 9000 (0.3501)
  • NPW 590.08
  • i35
  • NPW - 33,000 -3,000 (P/F, 35,1) 67,000 (P/F,
    35, 2)
  • 15,000 (P/F, 35,3) 9,000 (P/F,
    35,4)
  • NPW -33,000 -3,000 (0.7407) 67,000 (0.5487) -
  • 15000 (0.4064) 9000 (0.3011)
  • NPW - 1845.3

14
Solution
  • i30 ? NPW 590.08
  • i ??? ? NPW 0
  • i35 ? NPW -1845.3
  • 5 (increase in i) 590.08 (- 1845.3)
    decrease
  • ---------------------- --------------------------
    -----------
  • X 590.08 - 0
  • X 0.012
  • 1.2
  • i 30 1.2
  • 31.2

15
Example
  • For the net cash flows shown below, the maximum
    number of
  • possible rate of return solutions is
  • Year Net Cash Flows,
  • 0 -60,000
  • 1 -20,000
  • 2 22,000
  • 3 15,000
  • 4 35,000
  • 5 13,000
  • 6 -2,000
  • (a) 0
  • (b) 1
  • (c) 2
  • (d) 3

16
Example
  • A bulk materials hauler purchased a used
  • dump truck for 40,000.The operating cost
  • was 5000 per month, with revenues of 7500
  • per month. After 2 years, the truck was sold
  • for 12,000. The rate of return was closest to
  • (a) 4.6 per year
  • (b) 4.6 per month
  • (c) 8.2 per year
  • (d) 8.2 per month

17
Solution
  • NPW (i) 0
  • -40,000 (7,500 5,000) (P/A, i, 24) 12,000
    (P/F, i, 24) 0
  • -40,000 2,500 (P/A, i, 24) 12,000 (P/F, i,
    24) 0
  • Solve with trial- and-error
  • i5
  • NPW40,000 2,500 (P/A, 5, 24) 12,000 (P/F,
    5, 24)
  • NPW - 40,000 2,500(13.7986) 12,000
  • (0.3101)
  • -1782.3

18
Solution
  • i10
  • NPW40,000 2,500 (P/A, 10, 24)
  • 12,000 (P/F, 10, 24)
  • NPW - 40,000 2,500(8.9847) 12,000
  • (0.1015)
  • -16,320.25
  • i4
  • NPW40,000 2,500 (P/A, 4, 24)
  • 12,000 (P/F, 4, 24)
  • NPW - 40,000 2,500(15.240) 12,000
  • (0.3901)
  • 2781.2

19
Solution
  • NPW (4) 2781.2
  • NPW (i) 0
  • NPW (5) -1782.3
  • 1 (increase in i) 2781.2 (- 1782.3)
  • ---------------------- --------------------------
  • X 2781.2 0
  • X 0.006
  • i 4 0.6
  • i 4.6
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