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Object Recognition Using Genetic Algorithms

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Genetic Algorithms (GAs) Review. What is a GA? ... Inspired by the biological mechanisms of natural selection and reproduction. ... – PowerPoint PPT presentation

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Title: Object Recognition Using Genetic Algorithms


1
Object Recognition UsingGenetic Algorithms
  • CS773C Advanced Machine Intelligence Applications
  • Spring 2008 Object Recognition

2
2D Case
  • Recover the geometric transformation that aligns
    the model(s) with the scene.

(affine transformation)
3
Image-Space Approaches
  • Identify a set of features from the unknown scene
    which approximately match a set of features from
    a model object.
  • Recover the geometric transformation that the
    model object has undergone.
  • Examples
  • Interpretation tree (Grimson Lozano-Perez,
    1987)
  • Alignment (Huttenlocher and Ullman, 1990)
  • Geometric hashing (Lamdan et al., 1990)

4
Transformation-Space Approaches
  • Search the transformation space.
  • Find a transformation which aligns a large number
    of model features with the scene.
  • Examples
  • Hough-transform based methods (Ballard, 1981).
  • Pose clustering techniques (Cass, 1988)

5
Why Using GAs for Object Recognition?
  • Genetic algorithms were designed to efficiently
    search large solution spaces.
  • Both the image and transformation spaces are very
    large!
  • Image space M3S3 possible alignments
  • Transformation space much larger!

G. Bebis. S. Louis, Y. Varol, and A. Yfantis,
"Genetic Object Recognition Using Combinations
of Views", IEEE Transactions on Evolutionary
Computation, vol 6, no. 2, pp. 132-146, April
2002.
6
Genetic Algorithms (GAs) Review
  • What is a GA?
  • An optimization technique for searching very
    large spaces.
  • Inspired by the biological mechanisms of natural
    selection and reproduction.
  • What are the main characteristics of a GA?
  • Global optimization technique.
  • Uses objective function information, not
    derivatives.
  • Searches probabilistically using a population of
    structures (i.e., candidate solutions using some
    encoding).
  • Structures are modified at each iteration using
    selection, crossover, and mutation.

7
Structure of GA
  • 10010110 10010110
  • 01100010 01100010
  • 10100100... 10100100
  • 10010010 01111001
  • 01111101 10011101

Evaluation and Selection
Crossover
Mutation
Current Generation
Next Genaration
8
Encoding and Fitness Evaluation
  • Encoding scheme
  • Transforms solutions in parameter space into
    finite length strings (chromosomes) over some
    finite set of symbols.
  • Fitness function
  • Evaluates the goodness of a solution.

9
Selection Operator
  • Probabilistically filters out solutions that
    perform poorly, choosing high performance
    solutions to exploit.
  • Chromosomes with high fitness are copied over to
    the next generation.

fitness
10
Crossover and Mutation Operators
  • Generate new solutions for exploration.
  • Crossover
  • Allows information exchange between points.
  • Mutation
  • Its role is to restore lost genetic material.

Mutated bit
11
Object Recognition Using GasTwo Approaches
  • Genetic search in the image space (GA-IS)
  • Genetic search in the transformation space
    (GA-TS)
  • Important issues
  • How to encode solutions?
  • How to modify solutions ?
  • How to evaluate solutions?

12
GA-IS Encoding
  • At least three model-scene point matches are need
    to compute the affine transformation.
  • Chromosome contains the binary encoded identities
    of the three pairs of points.
  • Model points 19 (5 bits)
  • Scene points 19 - 45 (6 bits)
  • Chromosome length 3 x 5 3 x 6 33 bits

13
GA-IS Decoding
  • Some encoded solutions might be invalid
  • 5 bits can encode at most 32 values.
  • 0, 31 was linearlymapped to 0, 18
  • 6 bits can encode at most 64 values.
  • 0, 63 was linearly mapped to 0, 44

14
GA-IS Fitness Evaluation
  • Compute affine transformation.
  • Apply the transformation on all the model points.
  • Compute the back-projection error (BE) between
    the model and scene.
  • (dj min distance between the j-th model
    point and the scene)

15
GA-TS Encoding
  • Need to estimate the range of values that the
    parameters of affine transformation can assume.

16
GA-TS Encoding (contd)
  • Each chromosome contains six fields.
  • Only the range of each coefficient needs to be
    represented.
  • e.g., a11 assumes values in -0.408, 0.408
  • Its range is 0.408 - (-0.408) 0.816
  • 2 decimal digit accuracy 82 values must be
    encoded.
  • 7 bits are needed to encode 82 values.
  • Chromosome length 6 x 7 42 bits

17
GA-TS Decoding
  • Some encoded solutions might be invalid
  • 7 bits can encode at most 128 values.
  • 0, 127 should be mapped to 0, 81

18
GA-TS Fitness Evaluation
  • Same as before
  • Less expensive to compute in this case

19
Experiments
  • Three scenes (S1, S2, S3) of increasing
    complexity.
  • S2, S3 are shown below (S1 was the same as
    model).
  • 10 trials per scene tried to find model1 each
    time

20
Experiments (contd)
  • We searched for the model below in a number of
    scenes.

21
GA Parameters
  • Two-point crossover (prcoss 0.95).
  • Point mutation (pmut 0.05).
  • Cross generational selection strategy.
  • Fitness scaling (scaling factor 1.2).

22
Results Scene 1
  • Correct solutions were found in all 10 trials.

23
Results Scene 2
  • Correct solutions were found in all 10 trials.

24
Results Scene 3
  • Correct solution was missed once!

25
Efficiency GA-IS
26
Efficiency GA-TS
27
3D case GA-TS
  • Apply Genetic Search in the space of the AFoVs
    parameters.
  • We used 2 views per model

28
Experiments
  • Four scenes (S1, S2, S3,S4) of increasing
    complexity.
  • S1 was the same as model
  • 10 trials per scene

29
Experiments (contd)
  • We searched for the model below in a number of
    scenes.

30
GA Parameters
  • Two-point crossover (prcoss 0.95).
  • Point mutation (pmut 0.05).
  • Cross generational selection strategy.
  • Fitness scaling (scaling factor 1.2).
  • Population size 200
  • Number of generations 150

31
Results - Scene 1
  • Correct solutions were found in all 10 trials.

32
Results Scene 2
  • Correct solutions were found in all 10 trials.

33
Results Scene 3
  • Correct solutions were found in all 10 trials.

34
Results Scene 4
  • Correct solutions were found in all 10 trials.

35
Efficiency GA-TS
2 x 1015
36
More Challenging Scene
  • GAs can find near-exact matches.
  • Could be used as input to more sophisticated
    recognition
  • algorithms.
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