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Chapter 17: Oxidation and Reduction

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Foods like glucose, C6H12O6, a simple sugar are a reduced form of matter. ... that generates electric current is called a voltaic cell or a galvanic cell. ... – PowerPoint PPT presentation

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Title: Chapter 17: Oxidation and Reduction


1
  • Chapter 17 Oxidation and Reduction

2
Foods and fuels are high in energy.
  • Foods like glucose, C6H12O6, a simple sugar are a
    reduced form of matter. Glucose is oxidized when
    it reacts with oxygen by combustion or
    metabolism
  • C6H12O6 6O2 6CO2 6H2O energy
  • Note that this reaction is exothermic.
  • CO2 and H2O are oxidized forms of matter.
  • They are low in energy.

3
Photosynthesis
  • The reverse of the reaction on the previous slide
    is a reduction
  • 6CO2 6H2O energy C6H12O6 6O2
  • It is an endothermic reaction.
  • Energy is added by sunlight.

4
Oxidation Numbers(review)
  • Oxidation Number-Ion charges and apparent
    charges assigned to atoms within compounds.
  • Also called Oxidation State.
  • Bookkeeping system for keeping track of
    electrons.
  • Transition Elements may have several different
    oxidation numbers.

5
Rules for Assigning Oxidation Numbers
  • Uncombined elements have an oxidation number of
    zero K, Fe, H2, O2.
  • For a compound, the sum of oxidation numbers is
    zero.
  • For a polyatomic ion, the sum of oxidation
    numbers is equal to the charge on the ion.
  • For a monatomic ion, the charge is the oxidation
    number Na is 1, O2- is -2.

6
Oxidation Number Rules (continued)
  • When oxygen is present in a compound or
    polyatomic ion, it is assigned an oxidation
    number of -2 (except for peroxides like H2O2,
    where it is -1).
  • Hydrogen usually has an oxidation number of 1,
    except in metal hydrides like LiAlH4.

7
Steps in Determining Oxidation Numbers
  • Write down the known oxidation numbers in the
    formula. Set the missing Oxidation number to x.
  • Multiply the oxidation number by the subscript.
  • Write an equation where the sum of the oxidation
    numbers equal zero for a compound or the charge
    for a polyatomic ion.
  • Solve for the missing oxidation number.

8
Example Problems
  • Determine the oxidation number of the elements
    in H2SO4.
  • The oxidation number of H is 1 since it is
    combined with non-metals.
  • The oxidation number of O is -2 since this is not
    a peroxide.
  • The sum of the oxidation numbers is 0
  • Solving for x
  • 0 2(1) x 4(-2) 0 -6 x x 6

9
Cr2O72-
  • Determine the oxidation number of Cr in Cr2O72-.
  • The oxidation number of O is -2. The sum of the
    oxidation numbers is -2.
  • Set up an equation, let x be the oxidation number
    of Cr.
  • -2 2x 7(-2) 2x - 14
  • 2x -2 14, 2x 12 x 12/2 6

10
REDOX
  • Many reactions are oxidation-reduction reactions.
    These are sometimes termed REDOX reactions.
  • Most of the time, oxidation and reduction occur
    in the same reaction. One of the reactants is
    oxidized, the other is reduced.
  • REDOX reactions involve the transfer of electrons
    from one reactant to another.
  • There are several definitions of oxidation and
    reduction.

11
Oxidation
  • The term oxidation may be defined several
    different ways
  • 1. Gain of oxygen
  • 2. Loss of hydrogen
  • 3. Loss of electrons
  • 4. Increase in oxidation number.

12
Example Oxidation Reactions
  • Combustion
  • C O2 CO2
  • CH4 2O2 CO2 H2O heat
  • Corrosion (rusting)
  • 4Fe 3O2 2Fe2O3
  • Loss of hydrogen
  • CH3OH CH2O H2
  • Loss of electrons (increase in oxidation number)
  • Mg Cl2 Mg2 2Cl-

Cu
13
Reduction
  • The term reduction is also defined in several
    ways
  • 1. Loss of oxygen
  • 2. Gain of hydrogen
  • 3. Gain of electrons
  • 4. Decrease in Oxidation Number

14
Reduction Reactions
  • Reduction of metal oxides
  • CuO H2 Cu H2O
  • Loss of oxygen
  • 2KClO3 2KCl 3O2
  • Gain of hydrogen
  • CO 2H2 CH3OH
  • Gain of electrons
  • Cu2 2e- Cu

heat
15
A REDOX Reaction
  • CuO H2 Cu H2O
  • In this reaction CuO is reduced (the oxidation
    number of Cu goes from 2 to O).
  • H2 causes the reduction and is called the
    reducing agent.
  • H2 is oxidized (The oxidation number goes from 0
    to 2).
  • CuO caused the oxidation and is called the
    oxidizing agent.

16
Definitions
  • Oxidizing Agent The reactant in a chemical
    reaction which causes another reactant to be
    oxidized, and is itself reduced.
  • Reducing Agent The reactant in a chemical
    reaction which causes another reactant to be
    reduced, and is itself oxidized.

17
Oxidation/Reduction Definitions
Insert figure 17.5
18
Oxidizing Agents
  • Oxygen, O2
  • 4CH4 3O2 2C2H2 6H2O
  • Permanganate ion, MnO4-
  • MnO4- 2Fe2 8H Mn2 5Fe3 4H2O
  • Dichromate ion, Cr2O72-
  • 8HCr2O72-3C2H5OH 2Cr33C2H4O7H2O
  • Chlorine, Cl2
  • Mg Cl2 Mg2 2Cl-

19
Example REDOX Reaction
  • Consider the reaction
  • Cu(s) 4H(aq) 2NO3-(aq) Cu2(aq)
    2H2O(l) NO2(g)
  • Assign oxidation numbers to each element in the
    reactants and products. Which elements are
    oxidized? Which elements are reduced? What is
    the oxidizing agent? What is the reducing agent?

20
Answer
  • Cu(s) 4H(aq) 2NO3-(aq) Cu2(aq)
    2H2O(l) NO2(g)
  • Oxidation Numbers
  • Reactants Products Process Agent
  • Cu 0 Cu2 2 ox reducing
    agent
  • H 1 H 1 nc
  • O -2 O -2 nc
  • N -1 N 3(-2) N 0 N 2(-2)
  • N 5 N 4 red
  • NO3- oxidizing agent

21
Reducing Agents
  • Carbon, C
  • SnO2 C Sn CO2
  • Hydrogen, H2
  • WO3 3H2 W 3H2O
  • Carbon monoxide, CO
  • FeO CO Fe CO2

22
Half Reactions
  • REDOX reactions can be divided into two parts
    reduction half-reaction and oxidation
    half-reaction.
  • Dividing equations into half reactions is useful
    in balancing REDOX reaction equation.

23
Balance the following equation
  • MnO4- Fe2 Fe3 Mn2
  • Split the equation into two half reactions
  • MnO4- Mn2
  • Fe2 Fe3
  • Balance atoms using coefficients (done)
  • Balance O using H2O
  • MnO4- Mn2 4H2O
  • (continued)

24
Balance the following equation(continued)
  • MnO4- Fe2 Fe3 Mn2
  • Balance the hydrogens with H
  • 8H MnO4- Mn2 4H2O
  • Balance electrons with e-
  • Fe2 Fe3 e-
  • 5e- 8H MnO4- Mn2 4H2O
  • Multiply by whole numbers to get equal electrons
  • 5Fe2 5Fe3 5e-
  • (continued)

25
Balance the following equation(continued)
  • MnO4- Fe2 Fe3 Mn2
  • Add equations together
  • 5e- 8H MnO4- Mn2 4H2O
  • 5Fe2 5Fe3 5e-

5e- MnO4- 5Fe2 8H Mn2
5Fe3 4H2O 5e-
Cancel Electrons and others which are on both
sides.
MnO4- 5Fe2 8H Mn2 5Fe3
4H2O
Check to make sure all atoms and charges are
balanced.
26
Electrolytic Cells
  • Electricity (DC current) can be used to cause
    REDOX reactions to occur. This process is called
    electrolysis.
  • Molten NaCl can be separated into it elements
  • 2NaCl(l) 2Na(l) Cl2(g)
  • reduction Na e- Na (cathode)
  • oxidation 2Cl- Cl2 2e- (anode)

27
Electrolytic Cells
Insert figures 17.7 and 17.8
28
Electroplating
  • A metal can be plated onto a cathode from a
    solution of the ions of the metal.
  • The ions are replaced by oxidation at the anode
  • cathode reaction Ag(aq) e- Ag(s)
  • anode reaction Ag(s) Ag(aq)

29
Electroplating
Insert figure 17.9
30
Electrochemical Cells
  • A chemical system that uses an electric current
    to produce a chemical reaction or that generates
    electricity as a result of a chemical reaction is
    called an electrochemical cell.
  • Electrochemical cells that use electricity to
    make a chemical reaction occur are called
    electrolytic cells.

31
Voltaic Cells
  • Chemical reactions can produce electricity.
  • A chemical system that generates electric current
    is called a voltaic cell or a galvanic cell.
  • An example of a chemical reaction that can
    generate electricity is the reaction of zinc
    metal with copper (II) ions
  • Zn(s) Cu2(aq) Zn2(aq) Cu(s)

32
Zn(s) Cu2(aq) Zn2(aq) Cu(s)
  • When zinc metal is placed in a Cu2 solution, the
    zinc dissolves to form Zn2 ions, an the copper
    metal plates out on the surface of the zinc.
  • The reaction is a REDOX reaction
  • Oxidation Zn(s) Zn2(aq) 2e-
  • Reduction Cu2 2e- Cu(s)
  • These are called half reactions.

33
Zn(s) Cu2(aq) Zn2(aq) Cu(s)
  • The two half reactions
  • Oxidation Zn(s) Zn2(aq) 2e-
  • Reduction Cu2 2e- Cu(s)
  • The generate an electrical voltage two half cells
    are constructed
  • Zinc metal in a solution of Zn2 ions
  • Copper metal in a solution of Cu2 ions
  • The metals are connected by a wire through which
    the electric current can flow.
  • The two solutions are separated by a porous
    barrier or connected by a salt bridge.

34
Insert figure 17.10, 17.11
Voltaic Cells
35
Half cell reactions
  • In the solution containing the zinc, oxidation
    occurs
  • Zn(s) Zn2(aq) 2e-
  • The zinc is called the anode.
  • In the solution containing the copper, reduction
    occurs
  • Reduction Cu2 2e- Cu(s)
  • The copper is called the cathode.
  • Electrons flow through the wire from the anode to
    the cathode.
  • Charges in the solutions are balanced by ion
    migration through the salt bridge or porous
    barrier.

36
Voltaic cells
  • Commercial batteries operate on a principle
    similar the the Cu/Zn cell.
  • There are many electrochemical cells available
    today.
  • Two examples are the electric flashlight battery
    or dry cell and the lead/acid storage battery
    used in motor vehicles.
  • The corrosion of metals is another example of en
    electrochemical cell. Metal ions are oxidized
    and oxygen is reduced.
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