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Stoichiometry

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Stoichiometry. What if you have 40 graham crackers, 30 chocolate squares, and 20 marshmallows? ... Stoichiometry. Solving Limiting Reagent Problems ... Stoichiometry ... – PowerPoint PPT presentation

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Title: Stoichiometry


1
Stoichiometry
  • Unit 7

2
Stoichiometry
  • To make a smore, you need 2 graham crackers, 3
    squares of chocolate, and 1 marshmallow.
  • If you have 20 graham crackers, 30 chocolate
    squares, and 10 marshmallows, how many smores can
    you make?

3
Stoichiometry
  • What if you have 40 graham crackers, 30 chocolate
    squares, and 20 marshmallows?
  • What if you have 18 graham crackers, 30 chocolate
    squares, and 10 marshmallows?

4
Stoichiometry
  • Limiting Reagent
  • Limits (determines) the amount of product that
    you can get
  • Excess Reagent
  • Reagent that there is more than enough of
  • There is extra leftover when the reaction is
    complete

5
Stoichiometry
  • Just like the smores, the same thing happens in
    chemical reactions.
  • Example
  • 2 H2 O2 ? 2H2O

H2 is L.R.
O2 is E.R.
4 molecules H2
3 molecules O2
6
Stoichiometry
  • Solving Limiting Reagent Problems
  • If 18.1 g NH3 is reacted with 90.4 g of CuO,
    which is the limiting reagent and how many grams
    of solid copper will be produced?

7
Stoichiometry
  • Balance the equation.
  • 2 NH3 3 CuO ? N2 3 Cu 3 H2O
  • 2. Pick 1 of the reactants and 1 of the products.
    (Pick the product you are being asked about.)
    Using the given amount of reactant, figure out
    how much product you get. (3 steps)

8
Stoichiometry
1 mol NH3
63.55 g Cu
3 mol Cu
18.1 g NH3
2 mol NH3
1 mol Cu
17.04 g NH3

101 g Cu
9
Stoichiometry
  • 3. Now take the other reactant, and repeat Step 2
    with the same product you used before. (3 steps)

1 mol CuO
63.55 g Cu
3 mol Cu
90.4 g CuO
3 mol CuO
1 mol Cu
79.55 g CuO

72.2 g Cu
10
Stoichiometry
  • 4. Which reactant gave you less product?
  • CuO
  • 5. Thats the one that will run out first, so
    that is your limiting reactant.
  • 6. Now, using your LIMITING REACTANT, go back and
    answer the original question.
  • 72.2 g Cu

11
Stoichiometry
  • Examples
  • 2 H2 O2 ? 2 H2O
  • Determine the limiting reactant in each case.

12
Stoichiometry
  • a. 4.0 g H2 reacts with 3.0 g O2

1 mol H2
18.02 g H2O
2 mol H2O
4.0 g H2
2 mol H2
1 mol H2O
2.02 g H2

36 g H2O
1 mol O2
18.02 g H2O
2 mol H2O
3.0 g O2
1 mol O2
1 mol H2O
32.00 g O2

O2 is L.R.
3.4 g H2O
13
Stoichiometry
  • b. 10.0 g H2 reacts with 10.0 g O2

1 mol H2
18.02 g H2O
2 mol H2O
10.0 g H2
2 mol H2
1 mol H2O
2.02 g H2

89.2 g H2O
1 mol O2
18.02 g H2O
2 mol H2O
10.0 g O2
1 mol O2
1 mol H2O
32.00 g O2
11.3 g H2O

O2 is L.R.
14
Stoichiometry
  • c. 15.0 g H2 reacts with 10.0 g O2

1 mol H2
18.02 g H2O
2 mol H2O
15.0 g H2
2 mol H2
1 mol H2O
2.02 g H2

134 g H2O
1 mol O2
18.02 g H2O
2 mol H2O
10.0 g O2
1 mol O2
1 mol H2O
32.00 g O2

11.3 g H2O
O2 is L.R.
15
Stoichiometry
  • d. 5.0 g H2 reacts with 30.0 g O2

1 mol H2
18.02 g H2O
2 mol H2O
5.0 g H2
2 mol H2
1 mol H2O
2.02 g H2

45 g H2O
1 mol O2
18.02 g H2O
2 mol H2O
30.0 g O2
1 mol O2
1 mol H2O
32.00 g O2

33.8 g H2O
O2 is L.R.
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