VII3 Introduction into Wave Optics - PowerPoint PPT Presentation

About This Presentation
Title:

VII3 Introduction into Wave Optics

Description:

The picture on a screen behind are not two bright lines but rather a series of them. ... Methods based on X-ray diffraction are important for characterization of ... – PowerPoint PPT presentation

Number of Views:49
Avg rating:3.0/5.0
Slides: 42
Provided by: buph
Learn more at: http://buphy.bu.edu
Category:

less

Transcript and Presenter's Notes

Title: VII3 Introduction into Wave Optics


1
VII3 Introduction into Wave Optics
2
Main Topics
  • Huygens Principle and Coherence.
  • Interference
  • Double Slit
  • Thin Film
  • Diffraction
  • Single Slit
  • Gratings
  • X-Rays, Bragg Equation.
  • Wave Limits of Geometrical Optics.

3
Huygens Principle I
  • Up to now, we have have treated situations, where
    many of wave properties could be neglected. In
    our rays model, we actually needed only their
    straight propagation.
  • Now, we shall concentrate to typically wave
    properties of light which are generally valid for
    all electromagnetic (and other) waves.

4
Huygens Principle II
  • The basis for studying wave effects is Huygens
    (Christian 1629-1695 Dutch) principle of wave
    propagation. It states
  • Every point reached by a wave can be
    considered as a new source of tiny wavelets that
    spread out (in the forward direction) at the
    speed of the wave itself. The new wave front is
    the envelope of all the wavelets that is the
    tangent to all of them.

5
Huygens Principle III
  • If light is traveling through homogeneous
    isotropic media without obstacles Huygens
    principle gives us the same results as
    geometrical optics including effects as
    reflection and refraction.
  • However, when there is e.g. an obstacle then wave
    fronts will be not only distorted but new effects
    will appear. There will be e.g. bright or light
    or colored regions.

6
Coherence I
  • Typical wave properties are based on the
    principle of superposition. If several waves meet
    in one spot their common effect is the sum of all
    of them. But since waves are periodic, extremes
    may happen e.g. they are in phase and they will
    constructively interfere or they may be out of
    phase and they will interfere destructively.

7
Coherence II
  • Since the frequency of light is very high this
    adding of waves may have some stable result only
    if the interfering waves are coherent i.e. have
    constant phase difference. In the case of e.g.
    radio waves we can, in principle build two same
    oscillators and synchronize them. But there are
    no oscillator for visible light. It can be
    generated only by transitions in atoms.

8
Coherence III
  • So ideally coherent light waves should stem from
    the same transition of the same atom.
  • But also a partial coherence exists under much
    less strict conditions. Diffraction can be for
    instance obtained from a Sun light when it passes
    through a very small aperture.

9
Double-Slit Interference I
  • This experiment was the first convincing evidence
    of wave properties of light done in 1801 by
    Englishman Thomas Young (1773-1829).
  • If a plane monochromatic light wave passes
    through two thin, closely spaced slits. The
    picture on a screen behind are not two bright
    lines but rather a series of them.

10
Double-Slit Interference II
  • According to the Huygens principle the slits are
    sources of new wavelets but now in every point of
    screen only two of these wavelets add, instead of
    infinity, what would be the case without slits.
  • Lets suppose that the distance of the slits is
    negligible to that of the screen so two rays
    entering one point of it are almost parallel.

11
Double-Slit Interference III
  • If two waves leave the slits under some angle ?
    their path difference is
  • ?d d sin?
  • Clearly if ?d is an integral multiple of the
    wavelength the waves constructively interfere.
    The exact condition for this is
  • d sin? m?
  • m 0, 1 order of the interference fringe.

12
Double-Slit Interference IV
  • If, however, ?d is odd multiple of ?/2 the waves
    will be completely out of phase and they will
    interfere destructively. The exact condition for
    this is
  • d sin? (2m1)?/2 (m1/2)?
  • Again m 0, 1

13
Double-Slit Interference V
  • We have found the positions of the maxima and
    minima but there are also apparent changes in
    intensities which we have to explain.
  • The treatment of these more subtle details is
    similar to that we used in AC circuits. We can
    employ the mathematics of phasors.

14
Double-Slit Interference VI
  • The intensity of light is proportional to the
    square of their electric field I E2 so we
    shall find the total electric field produced by
    both waves at some angle ?, which is a sum of
    fields
  • E? E1 E2
  • The fields will be phase shifted
  • E1 E10sin?t and E2 E20sin(?t?)

15
Double-Slit Interference VII
  • The phase shift ? can be easily related to the
    path difference. From
  • ?/2? d sin?/? ?
  • ? 2?/? d sin?
  • If we expect that our point on the screen is
    equally illuminated by both slits we find
  • E? 2E0 cos(?/2)sin(?t ?/2)

16
Double-Slit Interference VIII
  • The same result can be found from the phasor
    diagram. The phase shift of E? is clearly ?/2.
  • We omit the fast changing term and relate the
    intensity to the one in the middle, where both
    waves are in phase
  • I?/I0 E2?0 /(2E0)2 cos2(?/2)

17
Double-Slit Interference IX
  • Finally we substitute for the phase difference ?
  • I? I0cos2(?/2) I0cos2(?dsin?/?)
  • Again the same conditions for the positions of
    the maxima and minima are present in this formula
    but we have also obtained the information on
    intensities.

18
Interference in Thin Films I
  • Two waves reflected on the upper and lower
    surfaces of a thin film can interfere either
    constructively if the path difference in the film
    is equal to integer number of wavelengths or
    destructively if it is an odd number of half
    wavelengths.
  • We have to consider the wavelength in the
    particular material of the film.

19
Interference in Thin Films II
  • It can be shown that the waves have the same
    frequency in all materials
  • f c/? v/?n ? c/v n ?/?n ? ?n ?/n
  • If we use white light the conditions for maximum
    at a certain angle will be valid always for some
    color color interference.

20
Interference in Thin Films III
  • Experiments show important property of
    reflection If a wave reflects on a surface with
    optically denser media it changes its phase by ?.
    If the second medium is less optically dense
    there is no phase change.

21
Interference in Thin Films IV
  • An important application of thin-film
    interference is a non-reflective coating of
    optical elements.
  • In the case of destructive interference more
    light gets through 99.
  • A single layer works well for one wavelength,
    usually 550 nm.
  • Actually whole field of layer reflective optics
    exists.

22
Diffraction I
  • Wave theory predicts that waves can be diffracted
    around edges of obstacles and interfere in the
    shadow behind them.
  • Only after diffraction of light was observed the
    wave nature of it was fully accepted.
  • The main ideas are again based on the Huygens
    principle.

23
Diffraction II
  • Lets consider a diffraction pattern produced by
    a single narrow slit of the width a.
  • Every point in the slit is a source of forward
    wavelets which add on some screen behind.
  • Lets find conditions for constructive and
    destructive interferences

24
Diffraction III
  • The condition for the first minimum is
  • sin ? ?/a
  • A wave from a point in the middle of the slit has
    a path difference of ?/2 from the point on the
    lower edge. These waves are out of phase and
    thereby cancel themselves. Similarly, if we
    proceed up, all waves will cancel in-pairs so we
    get a minimum.

25
Diffraction IV
  • The condition for the first maximum is
  • sin ? 3/2 ?/a
  • If we consider points in the two adjacent thirds
    of the slit, their waves will also cancel
    in-pairs but the waves from points in the last
    third will not, so we have a maximum intensity.
  • Higher orders can be found similarly.

26
Diffraction V
  • The conditions are opposite from those for
    two-slit interference.
  • Calculation of intensities can be again performed
    using phasors.
  • We can divide the slit to equivalent strips ?y
    and find the phase difference of the waves from
    adjacent strips
  • ?? 2?/? ?ysin? .

27
Diffraction VI
  • We are interested what will be the resulting
    phasor of total field built from these small
    phasors.
  • In the case of minima the phasors complete a
    whole circle so the total is zero.

28
Diffraction Grating I
  • Its in principle multiple parallel slits. At
    present gratings can be made very precisely with
    very high densities of slits of the order of 104
    lines per centimeter. Gratings can be made both
    for transmission and reflection.
  • The condition for principal maxima is the same as
    with the double slits
  • sin? m?/d here d is the adjacent spacing

29
Diffraction Grating II
  • The main difference between the double-slit and
    multi-slit pattern is that the maxima in the
    latter case are much sharper and narrower.
  • For maximum we need that waves even from far
    slits are exactly in-phase. If there is even a
    slight difference waves will cancel in pairs with
    some those from distant slits.

30
Diffraction Grating III
  • Gratings can be used to decompose light.
    Spectrometers using gratings are actually better
    than those using dispersive elements. The
    resolution of gratings is higher and the response
    is linear.
  • This has a great impact in spectroscopy.

31
X-Ray Diffraction I
  • If we use X-rays which are EMW with the
    wavelengths of the order of 10-10 m then actually
    crystal planes can serve as gratings with single
    atoms as single slits.
  • The refractive index for these wavelengths is
    almost 1 so the condition for maxima can be
    described by a simple Braggs equation
  • 2dsin? m?

32
X-Ray Diffraction II
  • Beside positions of maxima, there is also much
    information in intensities which are interpreted
    by more complicated dynamical theory.
  • Methods based on X-ray diffraction are important
    for characterization of structures of materials.
    Different methods exist for monocrystals, powders
    or solutions.

33
Polarization I
  • In unpolarized light the electric vectors have
    random position in the plane perpendicular to the
    propagation of the wave.
  • It is however possible to polarize light i.e. to
    select electric vectors only in a certain plane.
    This is done by polaroids but polarization is
    produced even by reflection.

34
Polarization II
  • If we cross two polaroids, ideally, no light gets
    through.
  • Some materials with assymetric molecules are
    capable to turn the polarization plane.
  • In polarographs we can measure e.g. concentration
    of these.

35
Scattering I
  • Actually any atom interacts with light. Its
    electrons become roughly sources of new wavelets.
    We can compare it to Huygens principle which is
    valid even in vacuum.
  • Since atoms are different there will be some
    interaction due to superposition of waves even
    for less ordered structures. But it will be seen
    only in the vicinity of the 0-order maximum.

36
Scattering II
  • Scattering again contains important structural
    information.
  • In atmosphere scattering behaves as 1/?4.
  • The sky is blue since blue light scatters most
  • The sunset is red since blue waves are scattered
    and just the red ones remain.

37
Wave Limits to Geometrical Optics I
  • An image done by e.g. a lens, is in fact a
    superposition of diffraction patterns. We would
    find this if we display just little point. Its
    image is not a point but rather diffraction
    circles.
  • This matters only when the magnification is high.

38
Wave Limits to Geometrical Optics II
  • A resolution of some optical device is roughly a
    distance of two points which we are still able to
    distinguish.
  • If we think about the diffraction patterns the
    point can be distinguished when the main maximum
    of one falls into the first minimum of the second.

39
Homework
  • No more homework from physics!

40
Things to read and learn
  • Chapters 35, 36
  • Try to understand all the details of the scalar
    and vector product of two vectors!
  • Try to understand the physical background and
    ideas. Physics is not just inserting numbers into
    formulas!

41
Maxwells Equations I
  • .

Write a Comment
User Comments (0)
About PowerShow.com