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The Tale of the Tape

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Aerial photos. Geographic Information Systems (GIS) Determining Surface Area ... need to buy to treat. the affected area if the. application rate is 3ppm ... – PowerPoint PPT presentation

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Title: The Tale of the Tape


1
The Tale of the Tape
  • Measuring Pond Surface Area and Volume for
    Stocking and Chemical ApplicationsBilly
    Higginbotham
  • Professor and Extension Wildlife and Fisheries
    Specialist
  • Texas Cooperative Extension

2
How Big is Your Pond?
  • Its a 2,000 yard pond.
  • My ponds pretty small.
  • Its about an acre, I guess.
  • My ponds real big.

3
Why Measure?
  • Surface area
  • Fish stocking
  • Carrying capacity
  • A few chemical applications
  • Volume - most chemical applications

4
What Do I Measure?
  • Surface area in acres
  • Volume in acre-feet

5
So What is an Acre?
  • 1 surface acre 43,560 square feetEquivalent
    to a square 209 x 209 a circle 235
    across

6
How Do I Measure Surface Area?
  • Pace it off
  • Tape measure
  • Range finders
  • Aerial photos
  • Geographic Information Systems (GIS)

7
Determining Surface Area
  • Three basic pond shapes
  • Square or rectangular
  • Triangular
  • Circular
  • (or a combination of 2 of the 3)

8
Area of a Square or Rectangle
Length
Width
9
An Acre-foot of Water is
  • 1 surface acre 1 foot deep
  • 43,560 cubic feet
  • 326,000 gallons

10
Determining Pond Volume
  • Pond Volume surface area (acres) x
  • average depth (feet)

11
How Do I Measure Depth?
  • Guess!
  • Depth finder
  • Calibrated rope and anchor
  • Calibrated pole

12
Measuring Pond Depth
  • Take at least 2 perpendicular transects
  • Begin at one bank with zero and end with zero
  • The more transects and depth soundings taken, the
    better your depth estimate becomes
  • Average depth is always LESS than you suspected
    BM (Before Measuring)!

13
Measuring Depth

x
x
x
x
x
x x x x x x x x x x
x x x x x x x x x x x x x x x x x
x
x
x
x
x
x
x

14
Determining Average Depth
  • Average depth sum of soundings
  • (feet) ? number of soundings
  • Transect 1 - 0,2,3,6,6,8,7,5,3,1,0
  • Transect 2 - 0,1,1,1,3,4,8,6,6,4,1,0
  • 76 feet ? 23 3.3 feet

15
Determining Average Depth
  • If you do not include zeros
  • Transect 1 - 2,3,6,6,8,7,5,3,1
  • Transect 2 - 1,1,3,4,8,6,6,4,1
  • 76 feet ? 19 4.0 feet

16
Determining Surface Area in Acres
  • Square or Rectangular Pond
  • Length (ft.) x Width (ft.) ? 43,560Acres

17
Determining Surface Area in Acres
  • Square or Rectangular Pond
  • Length (ft.) x Width (ft.) ? 43,560Acres
  • Example Pond is 200 x 350 70,000 square
    feet
  • 70,000 ? 43,560 1.6 surface acres

18
Determining Volume in Acre-Feet
  • Square or Rectangular Pond
  • Example pond is 200 x 350 70,000 square
    feet
  • 70,000 ? 43,560 1.6 acres
  • Average depth 3.2 feet
  • 1.6 acres x 3.2 feet 5.1 acre-feet of water

19
Determining Surface Area in Acres
  • Triangular Pond1/2 base (ft.) x height (ft.) ?
    43,560 acres

20
Area of a Triangle
Base
Height
21
Determining Surface Area in Acres
  • Triangular Pond1/2 base (ft.) x height (ft.) ?
    43,560 acres
  • Example pond is 200 along the dam x 500
    to upper end
  • 1/2 (200 x 500) ? 43,560 1.1
    surface acres

22
Measuring Depth
x
x x x x x x x x x
x
x x x x x x
x x
x
23
Determining Volume in Acre-Feet
  • Triangular Pond
  • Example pond averages 4.2 feet deep and is 200
    along the dam x 500 to upper end
  • 1/2 (200 x 500) 50,000 ? 43,560
  • 1.1 surface acres
  • 1.1 surface acres x 4.2 feet
  • 4.6 acre-feet of water

24
Determining Surface Area in Acres
  • Circular Pond ? x (radius)2 ? 43,560 acres
    ? is the ratio of the pond circumference to the
    pond diameter and approximates 3.14The pond
    radius is 1/2 of the pond diameter

25
Determining Surface Area in Acres
  • Circular Pond ? x (radius)2 ? 43,560 acres
  • Example Pond is 150 across the middle
    (diameter)
  • ? 3.14 and radius 75, so
  • 3.14 x (75)2 ? 43,560 0.41 acres

26
Area of a Circle
Radius
27
Area of a Circle
Diameter
28
Measuring Depth

x
x x
x x x x x x x x x x x x x x x
x
x x
x x
x
29
Determining Volume in Acre-Feet
  • Circular Pond
  • Example pond averages 3.9 feet deep and is 150
    across the middle (diameter)
  • 3.14 x (75)2 ? 43,560
  • 17,662.5 ? 43,560 0.41 acres
  • 0.41 acres x 3.9 feet 1.6 acre-feet of water

30
Pond Math
  • My pond is 0.5 surface acres and averages 4 feet
    deep. How much powdered 5 Rotenone do I need to
    apply at the recommended rate of 10 pounds per
    acre-foot of water to kill my fish so I can
    re-stock?

31
Pond Math
  • My pond is 0.5 surface acres and averages 4 feet
    deep. How much powdered 5 Rotenone do I need to
    apply at the recommended rate of 10 pounds per
    acre-foot of water to kill my fish so I can
    re-stock?
  • 0.5 surface acres x 4 feet deep 2 acre-feet
  • 2 acre-feet of water x 10 lbs Rotenone per
    acre-foot 20 lbs of Rotenone needed

32
Pond Math
  • Information from Texas Cooperative Extension
    states that I can stock 1,000 catfish per surface
    acre if I feed 5-7 days per week from April
    through October. How many catfish should I order
    for my triangle-shaped pond that is 125 feet
    across at the dam and 200 feet long from the dam
    to the upper end?

33
Pond Math
  • Information from Texas Cooperative Extension
    states that I can stock 1,000 catfish per surface
    acre if I feed 5-7 days per week from April
    through October. How many catfish should I order
    for my triangle-shaped pond that is 125 feet
    across at the dam and 200 feet long from the dam
    to the upper end?
  • 1/2 b x h 1/2 (125 x 200)
  • 12,500 ? 43,560 0.29 surface acres
  • 1,000 fingerlings per acre x 0.29 acres 290
    fingerlings

34
Pond Math
  • I have a pond that is a rectangle on one side
    connected by a culvert under my driveway to a
    triangular shaped upper end. The rectangle side
    is 100 feet by 150 feet and the average depth is
    6.2 feet. The triangle is 100 feet along the
    driveway and runs up into a neck 75 feet from the
    driveway and average depth is only 3.0 feet. How
    much copper sulfate do I need to apply at 2
    pounds per acre-foot of water to kill the
    filamentous algae covering the entire pond?

35
Rectangular Side
  • 100 x 150 15,000
  • 15,000 ? 43,560 0.34 acres
  • 0.34 x 6.2 2.1 acre-feet of water
  • 2 lbs of copper sulfate per acre-foot x 2.1
    acre-feet 4.2 lbs of copper sulfate

36
Triangular Side
  • 1/2 (100 x 75) 3750
  • 3750 ? 43,560 0.09 acres
  • 0.09 acres x 3 feet 0.27 acre-feet of water
  • 2 lbs of copper sulfate per acre-foot x 0.27
    acre-feet 0.54 lbs of copper sulfate

37
Spot Treatments
  • When fish are important pond resources
  • When vegetation covers more than 50 of thepond
  • When treatment is required in the summer months
  • To spot-treat, applyherbicide to no morethan
    20 of the totalpond surface at weeklyintervals

38
Spot Treatment
  • I have bushy pondweed growing from the pond
    edge to about 20 feet out around 250 feet of
    shoreline. The water where the weeds are growing
    averages
  • 2 feet in depth. How much
  • Aquathol Super K do I
  • need to buy to treat
  • the affected area if the
  • application rate is 3ppm
  • (13.2 pounds per acre-foot
  • of water)?

39
Spot Treatment
  • 250 x 20 5,000 square feet of area to be
    treated
  • 5,000 ? 43,560 0.11 surface acres
  • 0.11 acres x 2 feet average depth 0.22
    acre-feet
  • 0.22 acre-feet x 13.2 pounds of Aquathol Super K
    per acre-foot
  • 2.9 pounds of Aquathol Super K

40
Restricted Use Pesticides for Aquatic Applications
  • Rotenone
  • 2,4-D products

41
(No Transcript)
42
The End
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