TOPIC 2 THE ATMOSPHERE AND ITS RELATION TO THE CRUST AND HYDROSPHERE PowerPoint PPT Presentation

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Title: TOPIC 2 THE ATMOSPHERE AND ITS RELATION TO THE CRUST AND HYDROSPHERE


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TOPIC 2THE ATMOSPHERE AND ITS RELATION TO THE
CRUST AND HYDROSPHERE
  • Required reading All of Chapter 2 in Andrews et
    al. (1996) (1st ed.) or Chapter 3 of Andrews et
    al. (2004) (2nd. ed.) all of Chapters 9 and 23
    in Faure (1998).

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FORMATION OF CRUST AND ATMOSPHERE
  • Planets of solar system probably formed from
    remnants of supernovas, i.e., disc-shaped clouds
    of hot gases.
  • Condensing vapors formed solids that coalesced to
    form planetesimals (small bodies).
  • Accretion of planetesimals lead to formation of
    inner planets (Mercury-Venus-Earth-Mars).
  • Large outer planets condensed from gases at much
    lower temperatures.

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ACCRETION OF EARTH
  • As accretion built up the Earth to its present
    mass, it heated up owing to
  • radioactive decay of unstable isotopes
  • kinetic energy from impacts
  • Heating melted Fe and Ni which sank to the center
    forming the core.
  • Subsequent cooling permitted solidification of
    remainder to form mantle of roughly
    Mg-Fe-silicate composition.
  • Crust, hydrosphere and atmosphere formed from
    upper mantle during the early history of Earth.

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THE CRUST
  • Crust is shell of volume lt0.0001 of total Earth
    volume a small but important part (to us).
  • Crust evolved through time as incompatible
    elements were removed from mantle by partial
    melting.
  • Relative elemental abundances O gt Si gt Al gt Fe gt
    Ca gt Na gt Mg.

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Andrews et al. (1996)
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THE ATMOSPHERE
  • Volatile elements escaped from mantle during
    crust formation (e.g., volcanic degassing). Some
    were retained to form atmosphere.
  • Primitive atmosphere, probably CO2 N2 with
    minor H2 and H2O(vapor). Modern atmosphere had to
    await evolution of life.

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THE HYDROSPHERE
  • Bulk of water at Earths surface is in oceans
    (gt97) and in polar ice-caps and glaciers.
  • lt1 is continental fresh water, most stored as
    groundwater.
  • Source of water not well known
  • water bound as OH (bound in silicates) in
    meteorites?
  • water-rich comets?
  • As Earths surface cooled to 100C, water could
    condense. From existence of old sedimentary
    rocks, we know the ocean existed by 3.8 B.Y.

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Andrews et al. (1996)
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ORIGIN OF LIFE
  • Synthesis of biologically important molecules
    probably took place in restricted, specialized
    environments, such as surfaces of clay minerals,
    or near submarine hydrothermal vents.
  • Life probably began in oceans 4.2-3.8 B.Y. ago,
    but no fossils exist. Earliest fossil bacteria
    3.5 B.Y. old.
  • Earliest reactions to synthesize organic material
    probably based on S from hydrothermal vents
  • CO2(g) 2H2S(g) ? CH2O 2S(s) H2O(l)

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DEVELOPMENT OF PHOTOSYNTHESIS
  • H2O(l) CO2(g) ? CH2O(s) O2(g)
  • This reaction had great effect on Earth. First,
    O2 was consumed by oxidizing surface compounds
    and minerals. Eventually, the rate of supply
    exceeded consumption and O2 built up.
  • Life adapted to use O2 produced, which is
    otherwise toxic.
  • O2 underwent reactions to form O3 (ozone), which
    protects the surface from UV radiation.

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THE ATMOSPHERE
  • The smallest of Earths geological reservoirs
    particularly susceptible to pollution.
  • Mixing time very short, so contamination very
    quickly spreads throughout the globe, but is also
    diluted rapidly.
  • Bulk composition of atmosphere very similar world
    wide.
  • Lower atmosphere (troposphere) is well mixed by
    convection.

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  • At 15-25 km, the atmosphere is heated by
    absorption of UV by O2 and O3. Stabilizes upper
    atmosphere (stratosphere) against mixing. This is
    where ozone layer occurs.
  • Above 120 km, mixing is so weak that gas
    molecules can separate gravitationally - H2 and
    He are enriched at the top, O2 and N2 at bottom.
  • Definitions
  • Heterosphere where gravitational separation
    occurs
  • Homosphere well-mixed part of atmosphere
  • Turbopause separates heterosphere and homosphere

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Andrews et al. (1996)
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ASIDE PARTIAL PRESSURE(BOX 2.3 ANDREWS -
1996BOX 3.1 ANDREWS - 2004)
  • The total pressure of a mixture of gases is the
    sum of the pressures of the individual
    components. For example, in the atmosphere
  • Ptotal PO2 PN2 PCO2 PH2 PAr
  • Daltons Law

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IDEAL GAS LAW
  • PV nRT
  • P pressure, V volume, n moles of gas, T
    absolute temperature (K), R gas constant
    8.314 J mol-1 K-1 1.987 cal mol-1 K-1
    0.0820575 atm L mol-1 K-1
  • An ideal gas is one whose component molecules
    occupy no measurable volume and exert no forces
    of attraction or repulsion on one another.
  • Real gases approach ideality at low pressure and
    high temperatures.

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GASEOUS MIXTURES
  • P1V n1RT P2V n2RT P3V n3RT
  • and
  • (P1 P2 P3)V PTV (n1 n2 n3)RT
  • so
  • P1 x1PT P2 x2PT P3 x3PT
  • The partial pressure of a gas is equal to the
    total pressure multiplied by the mole fraction of
    that gas.

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BAROMETRIC LAW
  • PZ P0exp(-z/H)
  • PZ - pressure at altitude z, P0 pressure at
    ground level, H - scale height ? 8.4 km.
  • The barometric law gives the pressure of a gas as
    a function of altitude.
  • Daltons law implies
  • nZ n0exp(-z/H)
  • (partial pressures and number of moles are
    related)

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CHARACTERISTICS OF THE ATMOSPHERE
  • Air pressure drops exponentially with height.
  • 90 of atmospheric gas molecules are in
    troposphere.
  • The remainder are in the stratosphere ? low mass
    of upper atmosphere ? high sensitivity to
    contaminants.
  • Pollutants in upper atmosphere will be held in
    layers, hindering dispersal and dilution.

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COMPOSITION OF THE ATMOSPHERE
  • Water and CO2 are somewhat variable in abundance.
  • Most gases are relatively constant in abundance.
  • Most attention is focused on reactive trace gases.

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Andrews et al. (1996)
Same as Table 3.1 in Andrews et al. (2004)
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ASIDE CHEMICAL EQUILIBRIUM (BOX 2.4 - ANDREWS ET
AL., 1996 SECTIONS 9.1 and 9.2 - FAURE, 1998)
  • Consider the reaction
  • A B ? C D
  • At equilibrium it must be true that

Where aA ?ACA aB ?BCB etc. (In general ai
?iCi) In dilute solutions ?i ? 1, so ai ? ci.
Box 3.2 in Andrews et al. (2004)
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LAW OF MASS ACTION
  • Le Chatliers Principle If a system at
    equilibrium is perturbed, the system will react
    in such a way to minimize the change.
  • Example Hydrolysis of urea
  • NH2CONH2(aq) H2O(l) ? 2NH3(g) CO2(g)

aNH2CONH2 ?NH2CONH2cNH2CONH2 aH2O ? 1 (usually)
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  • For gases we have
  • aNH3 ?NH3PNH3 aCO2 ?CO2PCO2
  • In dilute solutions ?i ? 1, and at low pressures,
    where gases behave ideally, ?i ? 1, so

A more general form aA bB ? cC dD
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STEADY STATE OR EQUILIBRIUM HOW MUCH METHANE
SHOULD BE IN THE ATMOSPHERE?
  • How much CH4 should be present in the atmosphere
    if this trace gas is in equilibrium with the more
    abundant gases?
  • CH4(g) 2O2(g) ? CO2(g) 2H2O(g)

This suggests that CH4 pressure should be very
low, but exactly how low?
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Andrews et al. (1996)
Same as Table 3.1 in Andrews et al. (2004)
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  • PO2 ? 0.21 atm PCO2 ? 3.6x10-4 atm PH2O ? 0.01
    atm

PCH4 8x10-147 atm But the partial pressure of
methane actually measured is 1.7x10-6 atm, much
larger than that expected at equilibrium. Whats
wrong? Clearly, trace gases in the atmosphere may
not be in chemical equilibrium with other
components in the atmosphere.
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STEADY STATE
  • A steady state is a situation in which the
    sources and sinks of a component in the
    atmosphere are just in balance, so the
    concentration remains approximately constant.
  • Appropriate analogy is a leaky bucket.

F ? flux of component in or out mass/time A ?
total amount of component in atmosphere ? ?
residence time in the atmosphere
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STEADY STATE CALCULATIONS FOR METHANE
  • Fin (CH4) 500 Tg/yr note Tera 1012
  • Total mass of atmosphere 5.2x1018 kg
  • Total mass of CH4 (1.7 mol/106
    mol)(5.2x1018)(16/29)
  • 4.8 x 1015 g A

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WHAT IS THE MEANING OF RESIDENCE TIME (?)?
  • The residence time is a measure of the average
    length of time an individual molecule stays in
    the atmosphere (assuming atmosphere is well
    mixed).
  • Very important characteristic describing steady
    state systems.
  • In general, compounds with high ? tend to build
    up to relatively high concentrations. However,
    even though compounds with low ? are removed
    rapidly, this high reactivity may itself be a
    cause for concern.

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Also, low ? implies insufficient time for mixing,
so the composition of species with low ? should
be quite variable.
Andrews et al. (1996)
Same as Figure 3.3 in Andrews et al. (2004)
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Andrews et al. (1996)
Same as Table 3.3 in Andrews et al. (2004)
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ATMOSPHERIC BOX MODEL
Reservoir (atmosphere)
Sink
Source
The main goal is to identify sources and sinks of
components in the atmosphere, as well as
reactions among components in the atmosphere.
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GEOCHEMICAL SOURCES
  • I. Wind-blown dusts and sea sprays (probably most
    important).
  • Dusts not very reactive, so have little effect on
    atmospheric chemistry.
  • Sea spray has greater effect NaCl is hygroscopic
    ? tiny NaCl particles attract water and form an
    aerosol.
  • The aerosol droplets can be important sites for
    chemical reactions. Example
  • H2SO4(aer) NaCl(aer) ? HCl(g) NaHSO4(aer)

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GEOCHEMICAL SOURCES (CONTINUED)
  • II. Ablation from meteorites. Most important for
    metals. Small source but important in low-density
    upper atmosphere.
  • III. Volcanoes
  • Large sources of dust and gases.
  • Dust can block sunlight.
  • Gases SO2, CO2, HCl, HF
  • Acid rain a serious problem on the flanks of
    some volcanoes in Hawaii.
  • Volcanic sources are very discontinuous.

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ASIDE ACIDS AND BASES(BOX 2.5 - ANDREWS ET AL.,
1996 SECTION 9.3 - FAURE, 1998 BOX 3.3 -
ANDREWS ET AL., 2004)
  • Bronsted definition
  • Acid any substance that can donate a proton
  • Base any substance that can accept a proton
  • HCl(aq) ? H Cl-
  • NaOH(aq) H ? Na H2O(l)
  • Lewis definition
  • Acid any substance that can accept electrons
  • Base any substance that can donate electrons
  • H3BO3(aq) OH- ? B(OH)4-
  • H2O(l) ? H OH-
  • H3BO3(aq) H2O(l) ? B(OH)4- H

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ACIDS AND BASES(CONTINUED)
  • Acids and bases react together to form salts and
    water
  • 2KOH(aq) H2SO4(aq) ? K2SO4(aq) H2O(l)
  • The strength of an acid or base is defined as the
    degree to which it dissociates.
  • Strong acids and bases
  • HCl(aq) ? H Cl-
  • NaOH(aq) ? Na OH-

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ACIDS AND BASES(CONTINUED)
  • Weak acids and bases
  • HF(aq) ? H F-
  • B(OH)4- ? B(OH)3(aq) OH-

It is sometimes convenient to use the notation
pKX pKX -log KX pKA -log KA pKB -log
KB A small pKA ? strong acid large pKA ? weak
acid.
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GEOCHEMICAL SOURCES(CONTINUED)
  • IV. Radioactive decay of elements in rocks can
    release gases
  • 40K ? 40Ar(g) ?
  • 226Ra ? 222Rn(g) ?
  • 238U ? 234Th ? (? 4He)
  • 222Rn is a radioactive gas with a half-life of
    3.8 days. It is extremely dangerous compared to
    other radioactive elements because it is a gas.

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BIOLOGICAL SOURCES
  • I. Not a significant, direct source of particles.
  • II. Living forests
  • A. O2 and CO2 involved in respiration and
    photosynthesis
  • B. terpenes (pinene, limonene) - odor of forests
  • C. organic acids, aldehydes, etc. (see Box 2.7)

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BIOLOGICAL SOURCES(CONTINUED)
  • III. Micro-organisms
  • A. Most important in creating trace gases
  • B. Methane (CH4) generated by anaerobic systems
  • Damps soils, marshes, rice paddies
  • Digestive tracts of cattle
  • C. Soils rich in N-compounds contribute N-gases
  • NH2CONH2(aq) H2O(l) ? 2NH3(aq) CO2(g)

ammonia released under alkaline conditions, fixed
as NH4 under acidic conditions NH3(aq) H ?
NH4
urea (animal urine)
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BIOLOGICAL SOURCES(CONTINUED)
  • D. Some micro-organisms (nitrosomonas) oxidize
    NH3 during respiration
  • 2NH3(g) 2O2(g) ? N2O(g) 3H2O(l)
  • N2O(g) is an important and stable trace gas.
  • E. Micro-organisms in ocean are great sources of
    trace gases.
  • Seawater is rich in SO42-, Cl- (F-, Br-, I-).
    Marine organisms metabolize these elements to
    produce S- and halogen-containing gases.
  • Seawater is not a significant source of N-bearing
    gases.

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BIOLOGICAL SOURCES(CONTINUED)
  • Dimethyl sulfide (DMS)
  • Produced by marine phytoplankton (Phaeocystis
    pouchetti) in upper layers of ocean.
  • (CH3)2SCH2CH2COO-(aq) ? (CH3)2S(g)
    CH2CHOOH(aq)
  • beta-dimethylsulfoniopropionate DMS
    acrylic acid
  • (DMSP)
  • Carbonyl sulfide
  • CS2(g) H2O(g) ? OCS(g) H2S(g)
  • carbon disulfide carbonyl sulfide
  • Flux of OCS to atmosphere is less than DMS, but
    OCS is more stable, so attains higher
    concentrations. Both gases are insoluble in water.

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ASIDE GAS SOLUBILITY(Box 2.8 Andrews 1996 Box
3.4 - Andrews 2004)
  • Solubility of gases usually treated as an
    equilibrium process
  • CO2(g) ? CO2(aq)
  • Henrys law constant KH cCO2/PCO2 (mol L-1
    atm-1)
  • The larger KH, the more soluble the gas.
  • Some gases react with H2O, increasing their
    solubility
  • HCHO(g) ? HCHO(aq)
  • formaldehyde
  • HCHO(aq) H2O ? H2C(OH)2(aq)
  • methylene glycol

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GAS SOLUBILITY (CONTINUED)
  • Another important example
  • CO2 H2O ? H2CO3(aq)
  • carbonic acid
  • PROBLEM 1 What is the concentration of carbon
    monoxide in a drop of rain in equilibrium with
    the atmosphere?
  • From Table 2.3 we obtain PCO 100x10-9 atm, and
    from Table 1 we have KH 0.001 mol L-1 atm-1.
  • KH cCO/PCO
  • cCO KHPCO (100x10-9 atm)(0.001 mol L-1 atm-1)
  • 10-10 mol L-1

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TABLE 1 SOME HENRYS LAW CONSTANTS AT 15C
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GAS SOLUBILITY(CONTINUED)
  • PROBLEM 2 What is the partial pressure of H2O2
    (hydrogen peroxide) in an atmosphere in
    equilibrium with a lake water containing 10-6 mol
    L-1 H2O2?
  • KH 2x105 mol L-1 atm-1
  • PH2O2 CH2O2/KH (10-6 mol L-1)/(2x105 mol L-1
    atm-1)
  • 5x10-12 atm 0.005 ppbv

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REACTIVITY OF TRACE GASES
  • Gases with short ? are those that are easily
    removed. Some are removed by absorption by
    plants, solids, or water (physical removal). Most
    are removed by chemical reactions.
  • The most reactive entity (moiety) in the
    atmosphere is the hydroxyl (OH) radical.
  • Radical a reactive molecular fragment (moiety),
    usually possessing an unpaired electron.
  • Formed by photochemical reactions
  • O3(g) h? ? O2(g) O(g)
  • O(g) H2O(g) ? 2 OH(g)

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REACTIVITY OF TRACE GASES(CONTINUED)
  • The OH radical reacts very quickly with many
    atmospheric components and therefore has a very
    short ?.
  • It is an important contributor to acid rain
  • NO2(g) OH(g) ? HNO3(g)
  • from auto emissions
  • Some gases have limited reactivity with OH OCS,
    N2O, CH4 and CFCs (chlorofluorocarbons
    refrigerants and aerosol repellents).

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REACTIVITY OF TRACE GASES(CONTINUED)
  • Gases with low reactivity to OH can build up and
    reach the stratosphere, where they react with O,
    and therefore interfere with ozone production
  • O O2(g) ? O3(g)
  • Anything that reacts with O will affect ozone
    production.
  • CFCs cause damage to atmospheric ozone.
  • N compounds from SSTs were a concern, but now
    N2O produced at ground level is more important.
    This gas is produced by combustion processes,
    ironically in automobile engines with catalytic
    converters.

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OZONE(Box 2.9 Andrews 1996 Section 3.10 Andrews
2004)
  • O2(g) h? ? 2 O(g)
  • (? lt 242 nm)
  • O2(g) O(g) ? O3(g)
  • These ozone production reactions are balanced
    with ozone destruction reactions to maintain a
    steady state.
  • O3(g) h? ? O2(g) O(g)
  • O3(g) O(g) ? 2O2(g)

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ADDITIONAL OZONE DESTROYING REACTIONS
  • NO(g) O3(g) ? O2(g) NO2(g)
  • NO2(g) O(g) ? NO(g) O2(g)
  • O3(g) O(g) ? 2O2(g)
  • OH(g) O3(g) ? O2(g) HO2(g)
  • HO2(g) O(g) ? OH(g) O2(g)
  • O3(g) O(g) ? 2O2(g)
  • Chlorine from CFCs gives rise to
  • Cl(g) O3(g) ? O2(g) ClO(g)
  • ClO(g) O(g) ? Cl(g) O2(g)
  • O3(g) O(g) ? 2O2(g)

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OZONE(CONTINUED)
  • According to the previous reactions, OH, Cl,
    and NO all act as catalysts.
  • Catalyst a chemical species which increases the
    rate of a reaction, but is not itself produced or
    consumed overall.
  • This is what makes the loss of the ozone layer
    such a difficult problem a single pollutant
    molecule can be responsible for the destruction
    of a large number of O3 molecules.

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Dobson units denote thickness of ozone layer at
sea-level P and T. Each unit 0.01mm.
Mean October levels of ozone above Halley Bay
Antarctica
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URBAN ATMOSPHERE
  • Primary pollutant a pollutant compound directly
    released to the atmosphere (e.g., smoke, CO, CO2,
    etc.).
  • Secondary pollutant a pollutant compound formed
    as a product of chemical reactions in the
    atmosphere.

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LONDON SMOGPRIMARY POLLUTION
  • Urban air pollution was primarily the product of
    combustion of fuels.
  • The rapid development of pollution coincided with
    the transition to fossil fuel burning.
  • Normal, complete fuel combustion is described by
  • 4CH 5O2(g) ? 4CO2(g) 2H2O(g)
  • Neither CO2 nor H2O are particularly toxic.
    However, during incomplete combustion we get CO
  • 4CH 3O2(g) ? 4CO(g) 2H2O(g)

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LONDON SMOG(CONTINUED)
  • And also smoke particles
  • 4CH O2(g) ? 4C(s) 2H2O(g)
  • At low temperatures, we might also get PAHs
    (polycyclic aromatic hydrocarbons) such as
    benzo(?)pyrene, which are carcinogenic.

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LONDON SMOG(CONTINUED)
  • Fuel contaminants may also be a problem
  • 4FeS2(s) 11O2(g) ? 8SO2(g) 2Fe2O3(s)
  • Sulfur is highest in coals and fuel oils.
  • Smoke and SO2 are primary pollutants.
  • SMOG combination of smoke and fog (water
    droplets).
  • SO2(g) H2O(l) ? H HSO3-
  • 2HSO3- O2(aq) ? 2H 2SO42-
  • Fog droplets containing H2SO4 caused respiratory
    diseases.

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LOS ANGELES SMOGSECONDARY POLLUTION
  • Use of greater volatility liquid fuels in motor
    vehicles caused a new type of air pollution.
  • The major pollutants are not themselves emitted
    by motor vehicles, but are formed by reactions
    involving primary pollutants.
  • Photochemical smog smog whose formation is
    catalyzed by sunlight.
  • Fuel is burned in air, not pure O2, which has
    important consequences.

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LOS ANGELES SMOG (CONTINUED)
  • O(g) N2(g) ? NO(g) N(g)
  • N(g) O2(g) ? NO(g) O(g)
  • N2(g) O2(g) ? 2NO(g)
  • Next, NO is oxidized in smog to give NO2(g) (see
    Box 2.11 in Andrews 1996 or Box 3.6 in Andrews
    2004 for details). NO2 is a brownish gas that
    absorbs light.
  • NO2(g) h? ? NO(g) O(g)
  • O(g) O2(g) ? O3(g)
  • Thus, ozone (a respiratory irritant) is produced
    as a secondary pollutant.

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VOLATILE ORGANIC COMPOUNDS (VOCs)
  • VOCs may also be released from fuel combustion.
  • VOCs cause two problems
  • They aid in NO2 production.
  • CH4(g) 2O2(g) 2NO(g) h? ? H2O HCHO(g)
    2NO2(g)
  • They lead to formation of aldehydes (eye
    irritants and carcinogens)
  • PAN peroxyacetylnitrate - important eye irritant
    in photochemical smog.

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LEADED VS. UNDLEADED GASOLINE
  • Leaded gasoline contained tetraethyl lead -
    Pb(C2H5)4 which resulted in Pb pollution of air,
    soils and waters.
  • Some unleaded gasoline contains benzene, which is
    a carcinogen and contributor to photochemical
    SMOG.
  • Some gasoline contains MTBE (methyl tertiary
    butyl ether) which was added to improve air
    quality as a fuel oxygenate, but now has
    contaminated water supplies where gasoline has
    leaked or spilled.

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EFFECTS OF AIR POLLUTION
  • H2SO4 formed in smog can be an important agent of
    corrosion
  • H2SO4(aq) CaCO3(s) H2O(l) ? CO2(g)
    CaSO42H2O(s)
  • Gypsum causes two problems
  • 1) It dissolves in rain.
  • 2) Increased volume leads to mechanical stress.
  • Ozone attacks rubber, plastics, pigments and dyes.

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REMOVAL PROCESSES
  • Wet deposition removal of soluble components in
    rain or snow.
  • Oxidation is an important acid-forming process.
  • Organic compounds ? carboxylic acids (acetic,
    formic)
  • Sulfur compounds ? H2SO4
  • Organosulfur compounds ? MSA (methanesulfonic
    acid or CH3SO3H
  • Nitrogen compounds ? HNO3
  • Rain is usually acidic due to presence of
    dissolved CO2 (pH 5.6). These acids can lower
    pH further.
  • Dry deposition Direct removal of gaseous or
    particulate pollutants onto surface of the Earth.

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ACID-BASE SPECIATION CALCULATIONS
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MONOPROTIC ACIDS
  • What are the pH and concentrations of all species
    in a 0.1 mol L-1 HF solution?
  • 1) Write out important species H, OH-, HF0, F-.
  • 2) Write out all independent reactions and their
    equilibrium constants
  • HF0 ? H F-
  • H2O(l) ? H OH-

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  • 3) Write out mass-balance expressions
  • 0.1 mol L-1 ?F F- HF0
  • 4) Write out the charge-balance expression
  • H F- OH-
  • 5) Make reasonable assumptions
  • HF is an acid, so H gtgt OH- the
    charge-balance becomes
  • H ? F- X
  • and the mass-balance becomes
  • HF0 0.1 - X

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  • 6) Solve quadratic equation

a -1 b -10-3.2 -6.31x10-4 c 10-4.2
6.31x10-5
X1 -0.00825 X2 0.00765 H F-
7.65x10-3 mol L-1 pH -log H 2.12 HF0
0.1 - 0.00765 0.0924 mol L-1
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  • 7) Check assumption 1.318x10-12 ltlt 7.65x10-3, so
    OH- ltlt H.
  • What if we assumed HF0 gtgt F-, i.e., HF0 ?
    0.1? This might be valid because HF is a weak
    acid.
  • 10-3.2 X2/0.1
  • X2 10-4.2
  • X 10-2.1 0.00794
  • H F- 7.94x10-3 mol L-1 pH 2.10
  • HF0 0.1 - 0.00794 0.092 mol L-1
  • The above answer is only 8 different from 0.1.
    It seems in any case where KA lt 10-3.2, the above
    assumption should be good!

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POLYPROTIC ACID
  • What is the pH and concentration of all species
    in a 0.1 mol L-1 solution of H3PO4?
  • 1) Species H, OH-, H3PO40, H2PO4-, HPO42-,
    PO43-
  • 2) Mass action expressions
  • H3PO40 ? H2PO4- H
  • H2PO4- ? HPO42- H
  • HPO42- ? PO43- H

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  • H2O(l) ? H OH-
  • 3) Mass-balance
  • 0.1 mol L-1 H3PO40 H2PO4- HPO42-
    PO43-
  • 4) Charge-balance
  • H H2PO4- 2HPO42- 3PO43- OH-
  • 5) Assumptions
  • a) Because H3PO40 is an acid H gtgt OH-
  • b) Because H2PO4- and HPO42- are very weak acids
    and H3PO40 is only moderately weak
  • H3PO40 gt H2PO4- gtgt HPO42- gtgt PO43-
  • so, 0.1 H3PO40 H2PO4-
  • and H H2PO4- X.

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  • 10-3.1 - 10-2.1X - X2 0

X1 0.0245 X2 -0.0324 H H2PO4-
0.0245 mol L-1 pH 1.61 H3PO40 0.1 - 0.0245
0.0755 mol L-1
So HPO42- 10-7.0 mol L-1
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  • PO43- 10-17.79 1.62x10-18 mol L-1
  • OH- 10-14/10-1.61 10-12.39 4.07x10-13 mol
    L-1

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THE pH OF NORMAL RAINWATER
  • The pH of normal, unpolluted rainwater is
    controlled by carbonic acid equilibrium
  • CO2(g) ? CO2(aq) ? H2CO30
  • What is the pH of rainwater in equilibrium with
    atmospheric CO2 (PCO2 10-3.5 atm)?
  • 1) Species CO2(g), H2CO30, HCO3-, CO32-, H,
    OH-.
  • 2) Mass action
  • CO2(g) H2O(l) ? H2CO30

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  • H2CO30? HCO3- H
  • HCO3- ? CO32- H
  • H2O(l) ? H OH-
  • 3) Instead of a mass-balance we have PCO2
    10-3.5 atm
  • 4) Charge balance
  • H HCO3- 2CO32- OH-
  • 5) Assumptions
  • a) H2CO30 is an acid so H gtgt OH-
  • b) HCO3- is a weak acid so HCO3- gtgt CO32-
  • Therefore, H HCO3- X

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H2CO30 (10-1.5)(10-3.5) 10-5 mol L-1
X2 (10-6.3)(10-5.0) 10-11.3 X H
HCO3- 10-5.65 2.24x10-6 mol L-1 pH
5.65 So the pH of pure, normal rainwater is
acidic! Check assumption OH- 10-14/10-5.65
4.47x10-9 so H gtgt OH-
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pH OF RAIN ACIDIFIED WITH SO2
  • The concentration of SO2 in the atmosphere is
    usually less than that of CO2, but SO2 is more
    soluble in water and forms a stronger acid.
  • What is the pH of a rain droplet in equilibrium
    with an atmosphere with PSO2 5x10-9 atm?
  • We proceed as in previous example, but we assume
    that the effect of CO2 can be neglected because
    SO2 produces a stronger acid.
  • 1) Species SO2(g), H2SO30, HSO3-, SO32-, H, OH-

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  • 2) Mass action
  • SO2(g) H2O(l) ? H2SO30
  • H2SO30 ? HSO3- H
  • HSO3- ? SO32- H
  • H2O(l) ? H OH-
  • 3) Instead of mass-balance PSO2 5x10-9 atm
  • 4) Charge-balance H HSO3- 2SO32-
    OH-

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  • 5) Assumptions
  • a) Because H2SO30 is an acid H gtgt OH-
  • b) HSO3- is a weak acid so HSO3- gtgt SO32-
  • Therefore, H HSO3- X
  • H2SO30 KHPSO2 2.0 x 5x10-9 10-8 mol L-1
  • K1 2x10-2 X2/10-8
  • X2 2x10-10
  • X H HSO3- 1.414x10-5 mol L-1 pH
    4.85
  • OH- 10-14/10-4.85 7.07x10-10 mol L-1
  • Note that only a very small amount of SO2 in the
    atmosphere can result in significant
    acidification of rain!

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EFFECT OF OXIDATION OF SO2
  • What would the pH of a droplet of rain be if all
    the SO2 in the atmosphere were oxidized to H2SO4?
  • Assume that 1 m3 of atmosphere contains 0.001 dm3
    of liquid water and the temperature is 15C.
  • Because H2SO4 is a strong acid, we can assume
    that it is totally dissociated. Thus, we can
    solve this problem simply by calculating the
    concentration of SO2 in moles L-1.
  • If PSO2 5x10-9 atm, then 1 m3 of atmosphere
    contains 5x10-9 m3 of SO2. To convert to moles,
    we must know how much volume a mole of gas
    occupies at 15 C and 1 atm.

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USE IDEAL GAS LAW
  • PV nRT
  • P 1 atm n 1 mol R 0. 0820575 atm L
    moles-1 K-1 T 288.15 K
  • V
  • (1 mol)(0.0820575 atm L moles-1 K-1)(288.15 K)/1
    atm
  • 23.65 L 23.65x103 cm3 (1 m/100 cm)3 0.02365
    m3
  • Thus, 1 m3 of air would contain 5x10-9/0.0237
    2.11x10-7 moles of SO2. If all this SO2 is
    oxidized and removed into a droplet of H2O of
    volume 0.001 dm3, this would result in 2.11x10-4
    mol L-1 of H2SO4. This yields 4.22x10-4 mol L-1
    H or pH 3.37.

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