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## Specific Heat Capacity

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### Specific Heat Capacity Or the amount of energy needed to heat substances up Specific Heat Capacity can be thought of as a measure of how much heat energy is needed to ... – PowerPoint PPT presentation

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Title: Specific Heat Capacity

1
Specific Heat Capacity
• Or the amount of energy needed to heat substances
up

2
• Specific Heat Capacity can be thought of as a
measure of how much heat energy is needed to warm
the substance up.
• You will possibly have noticed that it is easier
to warm up a saucepan full of oil than it is to
warm up one full of water.

3
• Specific Heat Capacity (C) of a substance is the
amount of heat required to raise the temperature
of 1g of the substance by 1oC (or by 1 K).
• The units of specific heat capacity are J oC-1
g-1 or J K-1 g-1. Sometimes the mass is expressed
in kg so the units could also be J oC-1 g-1 or
• J K-1 kg-1

4
• The next table shows how much energy it takes to
heat up some different substances.
• The small values show that not a lot of energy is
needed to produce a temperature change, whereas
the large values indicate a lot more energy is
needed.

5
• Approximate values in J / kg K of the Specific
Heat Capacities of some substances are
• Aluminium 900 Mercury 14
• Asbestos 840 Nylon 1700
• Brass 400 Paraffin 2100
• Brick 750 Platinum 135
• Concrete 3300 Polythene 2200
• Cork 2000 Polystyrene 1300
• Glass 600 Rubber 1600
• Gold 130 Silver 235
• Ice 2100 Steel 450
• Iron 500 Water 4200

6
The equation
• The amount of heat energy (q) gained or lost by a
substance mass of substance (m) X specific heat
capacity (C) X change in temperature (?T)
• q m x C x ?T

7
An example of a calculation using the specific
heat capacity equation
• How much energy would be needed to heat 450
grams of copper metal from a temperature of
25.0C to a temperature of 75.0C?
• (The specific heat of copper at 25.0C is 0.385
J/g C.)

8
• Explanation
• The change in temperature (?T) is
• 75C - 25C 50C
• Given mass, two temperatures, and a specific heat
capacity, you have enough values to plug into the
specific heat equation
• q m x C x ?T .
• and plugging in your values you get
• q (450 g) x (0.385 J/g C) x (50.0C)
• 8700 J

9
Some good websites
• http//www.s-cool.co.uk/gcse/physics/energy-transf
ers/types-of-energy-transfers.htmltypes-of-energy