Triaxial State of Stress at any Critical Point in a Loaded PowerPoint PPT Presentation

presentation player overlay
1 / 12
About This Presentation
Transcript and Presenter's Notes

Title: Triaxial State of Stress at any Critical Point in a Loaded


1
(No Transcript)
2
Triaxial State of Stress at any Critical Point in
a Loaded Body
  • Cartesian stress components are found first in
    selected x-y-z coordinate axes (Fig. 4.1)
  • Three mutually perpendicular principal planes are
    found at unique orientations
  • NO Shear stresses on these planes
  • Principal Normal Stresses ?1, ?3, ?2, one of
    which is maximum normal stress at the point
  • Three mutually perpendicular Principal Shearing
    Planes (Planes of max. shear)
  • Principal Shearing Stresses ?1, ?2, ?3, one of
    which is the maximum shear stress at the point
  • Normal stresses are NOT zero, NOT principal
    stresses and depend on the type of loading

3
3-D Stress Transformations Equations
  • Relate Known Cartesian Stress Components at Any
    Point with Unknown Stress Components on Any Other
    Plane through the SAME Point
  • From equilibrium conditions of infinitesimal
    pyramid
  • Important for the Unique Orientations of the
    Principal Normal and Shearing Planes
  • Stress Cubic Equation- three real roots are the
    Principal Normal Stresses, ?1, ?2, ?3.
  • Principal Shearing Stresses can be calculated
    from the Principal Normal Stresses as follows

4
Mohrs Circle Analogy for Stress Graphical
Transformation of 2-D Stress State
  • Principal stress solution of stress cube eq. for
    stresses in the x-y plane (Fig. 4.12)
  • Analogy with the equation of a circle plotted in
    the ?-? plane leads to Mohrs circle for biaxial
    stress
  • Sign convention for plotting the Mohrs circle
    (normal stress is positive for tension, shear is
    positive for clockwise (CW) couple)
  • Two additional Mohrs circle for triaxial stress
    states
  • Find orientation of principal axes from the
    Mohrs circle

5
(No Transcript)
6
Strain Cubic Equation and Principal Strains
  • STRAIN a measure of loading severity, defining
    the intensity and direction of deformation at a
    point, w.r.t. specified planes through that
    point.
  • Strain state at a point is completely defined by
  • Three normal and three shearing strain components
    in the selected x-y-z coordinate system, OR
  • Three PRINCIPAL strains and their directions from
    Strain Cubic Equation (similar to Stress Cubic
    Equation, where ?s are replaced by ?s, and
    shear stresses, ?s, are replaced by one-half of
    ?s.)

7
Summary of Example Problems
  • Example 4.8 Principal Stresses in Beam
  • Hollow cylindrical member subjected to transverse
    forces (four-point bending), axial force and
    torque
  • Sketch state of stress at critical point (bottom
    edge)
  • Use stress cubic equation to find principal
    stresses from calculated Cartesian stresses at
    critical point
  • Find principal shear stresses from principal
    normal ones
  • Example 4.9 Mohrs Circle for Stress
  • Semi-graphical analysis of biaxial stress state
    at critical point of previous example ?cube is
    replaced by 2-D sketch in x-y plane
  • Principal normal and shear stresses are found
    graphically from the basic and the two additional
    Mohr circles, respectively

8
(No Transcript)
9
(No Transcript)
10
(No Transcript)
11
Summary of Textbook Problems Problem 4.31,
Principal Stresses
  • Identify critical points for each of the three
    types of loading applied on the bar
  • Locations where stresses are amplified by
    superposition of effects from different loads
    top end of vertical diameter and left end of
    horizontal one
  • Sketch infinitesimal cube elements for the states
    of stress at critical points
  • Calculate stresses at critical points, in the
    given system of Cartesian coordinates
  • Use stress cubic equation to find the principal
    stresses at each of the two critical points
  • Top edge ?126,047 psi, ?20, ?3-7683 psi
  • Left edge ?131,124 psi, ?20, ?3-31,124 psi
  • Calculate the maximum shearing stress at each
    point
  • Top edge ?max 16,865 psi, while at the left
    edge ?max 31,124 psi

12
(No Transcript)
Write a Comment
User Comments (0)
About PowerShow.com