Title: The probability of an event A is a measure of the likelihood of the event. Probabilities have the fo
1The probability of an event A is a measure of the
likelihood of the event. Probabilities have the
following properties
2If A1, A2, A3, , is a sequence of mutually
exclusive events, then
P(A1 or A2 or A3 or ) P(A1) P(A2) P(A3)
3It is certain (probability 1) that any event
either will or wont happen.
P(A U not(A)) P(A) P(not(A))
(complements are mutually exclusive)
1
P(not(A)) 1 P(A)
4Example Suppose a fair 6-sided die is rolled.
What is the probability that an even number will
result?
S 1, 2, 3, 4, 5, 6 A 2, 4, 6
x P(X) 1 1/6 2 1/6 3 1/6 4 1/6 5 1/6 6 1/6
5If an experiment can result in any one of N
different equally likely outcomes, and if exactly
n of these outcomes correspond to event A, then
the probability of event A is
6Example If 5 cards are dealt from a standard
deck of cards, what is the probability of have
all five cards being of the same suit?
A Five cards of the same suit S All five card
hands Operation 1 Choose a suit (n1) Operation
2 5 cards of same suit (n2)
7If A and B are two events, then
P(A or B) P(A) P(B) P(A and B)
8P(A or B or C) P(A) P(B) P(C) P(A and B)
P(A and C) P(B and C) P(A and B and C)
9Venn Diagram Population Obstructive Lung Disease
A Chronic bronchitis B Emphysema C Asthma
10Venn Diagram Population Obstructive Lung Disease
A Chronic bronchitis B Emphysema C Asthma
P(A) 0.07 0.09 0.13 0.15 0.44
11Venn Diagram Population Obstructive Lung Disease
A Chronic bronchitis B Emphysema C Asthma
P(B) 0.09 0.08 0.15 0.14 0.46
12Venn Diagram Population Obstructive Lung Disease
A Chronic bronchitis B Emphysema C Asthma
P(A B) 0.09 0.15 0.24
13Venn Diagram Population Obstructive Lung Disease
A Chronic bronchitis B Emphysema C Asthma
P(A or B) 0.070.090.080.130.150.14
0.66
14Venn Diagram Population Obstructive Lung Disease
A Chronic bronchitis B Emphysema C Asthma
P(not(B)) 0.07 0.13 0.11 0.23
0.54
15The conditional probability of B given A, denoted
by P(B A) is defined by
provided that P(A) gt 0
Note If P(A) 0 then event A is impossible
therefore it cannot be given to have happened.
16Venn Diagram Population Obstructive Lung Disease
A Chronic bronchitis B Emphysema C Asthma
P(AB) P(A B) / P(B) (0.090.15)/(0.090.15
0.080.14) 0.52174
17If in an experiment events A and B can occur, then
18Two events are independent if and only if
It is always true that P(A B)
P(A)P(BA) Under the special condition of
independence, P(A B) P(A)P(B) therefore, two
events are A and B independent if P(BA)
P(B) Interpretation of independence A and B are
independent if knowing whether A occurred or not
does not change the likelihood (probability) of B
19A B are mutually exclusive since P(A B) 0
Are A B independent? In order to be
independent P(B) P(BA) P(B) p2 P(BA) P(A
B)/P(A) 0/p1 0 Since p2 gt 0 then A and B
cannot be independent.
It is IMPOSSIBLE for events to be both mutually
exclusive and independent.
20An electrical system consists of four independent
components shown below along with the probability
that each component will operate properly. What
is the probability that the system will work?
0.95 (0.98) (0.75 0.70 0.75(0.70))
0.861175
21If the system does not work, what is the
probability that component B is not working?
Let Z system broken
Ways for system to not work when B component is
also not working
ABCD 0.95(0.02)(0.75)(0.70) 0.009975 ABCD
0.05(0.02)(0.75)(0.70) 0.000525 ABCD
0.95(0.02)(0.25)(0.70) 0.003325 ABCD
0.05(0.02)(0.25)(0.70) 0.000175 ABCD
0.95(0.02)(0.75)(0.30) 0.004275 ABCD
0.05(0.02)(0.75)(0.30) 0.000225 ABCD
0.95(0.02)(0.25)(0.30) 0.001425 ABCD
0.05(0.02)(0.25)(0.30) 0.000075
22If the system is working then what is the
probability that component C is also working?
Let Z system works
Calculating the probability of event (C and
Z) ABCD P(A and B and C and D)
0.95(0.98)(0.75)(0.70) 0.488775 ABCD P(A and B
and C and not(D)) 0.95(0.98)(0.75)(1-0.70)
0.209475 P(C and Z) 0.69825
23Homework 3 Pages 73 74 106, 112, 116, 120