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Using standard electrode potentials to calculate electrochemical cell voltages

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Shows the relative ability for a substance to be reduced (gain electrons) ... Page 11 of our data booklet. Eonet= Eooxidation Eoreduction ... – PowerPoint PPT presentation

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Title: Using standard electrode potentials to calculate electrochemical cell voltages


1
Using standard electrode potentials to calculate
electrochemical cell voltages
  • Chapter 19 Pages 768-773

2
  • An electrochemical (voltaic) cell consists of an
    oxidation reaction and a reduction reaction to
    produce a voltage for the cell.
  • Ex Batteries
  • Need to know which electrode is the cathode,
    which is the anode, and whether the chemical
    reaction is spontaneous.

3
  • Anode negative electrode where oxidation
    occurs
  • Cathode positive electrode where reduction
    occurs
  • Electrons travel from the anode to the cathode,
    along a conductive wire voltage electricity.

4
Anode
Cathode
5
When choosing your anode and cathode follow this
rule
  • Look at the reduction potential for the ions, the
    cathode will be the more positive reduction
    potential (p.11)
  • Reason higher reduction potential means more
    easily reduced, therefore reduction takes place
    there, therefore the cathode

6
Tableof standard reduction potentials
  • Shows the relative ability for a substance to be
    reduced (gain electrons). It expresses this
    potential to gain electrons by assigning a
    voltage for each reduction half reaction in the
    table.
  • Page 11 of our data booklet

7
Eonet Eooxidation Eoreduction
  • Eonet total net voltage of the cell (electric
    potential energy of the cell)
  • Must be greater than zero for the reaction to be
    spontaneous
  • If less than zero, than non-spontaneous reaction
    and no electricity produced.

8
Eonet Eooxidation Eoreduction
  • Eooxidation oxidation half reaction taking
    place in the cell
  • Oxidation half reactions are the reverse reaction
    from the table on p.11, so their sign changes!
    If the reduction potential of Ag 0.80V, then
    the oxidation potential of Ag(s) - 0.80V

9
Eonet Eooxidation Eoreduction
  • Eoreduction reduction half reaction taking
    place in the cell
  • The larger the reduction potential (the more
    positive), the greater the tendency for the
    reaction to occur.
  • The smaller the reduction potential (the most
    negative), the least likely for a reaction to
    occur.

10
Example Problem 1
  • Design an electrochemical cell that uses the
    reactions of the metals Zn and Ag, and solutions
    of their ions, Zn2 and Ag.
  • Identify the anode and cathode
  • Write the oxidation and reduction half reactions
  • Calculate the cell voltage

11
Solution
  • a), b) Zn2 2e- ? Zn(s) -0.76V
  • Ag1 1e- ? Ag(s) 0.80V
  • Ag more easily reduced, therefore Ag(s) is the
    cathode, so oxidation takes place at the anode
    (Zn) and the oxidation potential half reaction
    is
  • Zn(s) ? Zn2 2e- 0.76V
  • c) Eonet Eooxidation Eoreduction
  • (0.76V) ( 0.80V)
  • 1.56V

12
  • http//www.chem.iastate.edu/group/Greenbowe/sectio
    ns/projectfolder/flashfiles/electroChem/volticCell
    .html
  • Look at this electrochemical cell demonstration.
    Do the same as our example with Zinc and Silver

13
Exercise
  • An electrochemical cell was designed using the
    metals Mg and Al and solutions containing Mg2
    and Al3.
  • Identify the anode and cathode
  • Write the oxidation and reduction half reactions
  • Calculate the cell voltage
  • An electrochemical cell was designed using the
    metals Zn and Pb and solutions containing the
    positive ions of these metals, Zn2 and Pb2.
  • Identify the anode and cathode
  • Write the oxidation and reduction half reactions
  • Calculate the cell voltage
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