Step Function PowerPoint PPT Presentation

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Title: Step Function


1
Step Function
  • Previous solution was limited to a steady-state
    approach. However, the changes in a defined space
    need to be examined on a dynamic basis.
  • So, lets consider a design space in which a
    steady state is eventually achieved.
  • What happens to concentrations in this transition
    with time, as steady state is approached?

2
Conc.
Time
Initiation of activity
3
Step Function
  • Assume V, Flows and sources are defined and the
    space is well mixed
  • (dC/dt)V FiCi FoCo rxV
  • (dC/dt)V FiCi FC KCV
  • We know the steady state
    (i.e., dC/dt 0) solution gives
  • C Css FiCi/(Fo KV)
  • Css (S)/(F KV), where S source flux

4
Css
Heres the steady-state concentration
Conc.
Css (S)/(F KV)
Time
Initiation of activity
5
What does the conc. do in transition?
Css
Conc.
Time
Initiation of activity
6
Step function
  • Examine (C)t as Css is approached
  • (dC/dt)V S FC KCV
  • dC/dt S/V - FC/V KC
  • S/V S(F/V K)/(V)(F/V K)
  • S/V Css (F/V K) therefore
  • dC/dt -(F/V K) (C - Css)

7
Step function
  • Now, assume y C-Css dC/dt dy/dt
  • y y0 exp -(KF/V), therefore
  • Ct Css (C0- Css) exp (KF/V)(t)
  • Css steady state conc.
  • C0 initial background conc.

8
SmokeyBar Givens
  • Room volume 500 m3
  • People 50 smokers 50 non-smokers
  • Cig. Emissions
  • 1.4 x 50 x 2 140 mg/hr of HCHO _at_ t0
  • HCHO oxidation
  • rx -k HCHO, w/ K 0.4 hr-1

9
SmokeyBar Required
  • Transient concentration of HCHO in ambient air,
    as steady state is approached, under dynamic
    conditions.

10
SmokyBar as step function
  • Earlier, Css 0.117 mg/m3 for HCHO
  • Lets assume C0 zero and the time-step of
    interest is 1 hour
  • Ct Css (C0- Css) exp (KF/V)(t)
  • Ct1hr 0.117 (1 exp 0.4 1000/500)1)
    0.106 mg/m3
  • 0.045 _at_ 0.2hr 0.06_at_ 0.3 hr 0.082_at_0.5hr

11
Conc. profile is then an exponential increase
that is virtually at ss within 2 hours
0.117




Conc., mg/m3


2
1
Time,hr
Initiation of activity
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