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Markov Processes

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Title: Markov Processes


1
Markov Processes
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2
Markov processes
  • Stochastic process is Markov process ? prob. of
    future state depends only on present state.
  • Formally X(t), tgt 0 is a MP if for any set of
  • n1 times t1 lt lt tn1, any set of states,
    x1,xn1,
  • Note BD process, Bernoulli process, Poisson
    process are Markov processes

3
Markov Chains
  • Discrete-state Markov process is a Markov chain
    (MC)
  • Consider first discrete-time MC Xn, n0,1,
  • Pij P(Xn1 j Xn, i), i,j 0,1, n gt 0
  • Define transition probability matrix
    P Pij. No. of states finite or countably
    infinite.

4
  • Q what is state after n transitions?
  • A define
  • Note that

5
  • For n,m gt 1,

6
Markov Chains
  • Define n-th step transition probability matrix
  • We have
  • These are the Chapman Kolmogorov equations
  • We conclude
  • Q what happens as n ??? does converge to
    something?

7
Equilibrium Behavior of MCs
  • Need to study behavior of MC a more carefully
  • j reachable from i if for some n
  • if i also reachable from j, then i and j
    communicate,
  • (i ? j). Note that ? is an equivalence
    relation
  • if i,j communicate, they are in the same class.
  • MC divides into one or more (equivalence)
    classes.

8
Equilibrium Behavior of MCs
  • a MC is irreducible if there exists exactly one
    class.
  • i has period d if
  • d is largest such integer

9
Transience and Recurrence
  • - prob. return to i for first time at time
    n
  • -
  • -
  • prob ever return to
    i
  • -- if fi 1, then i is recurrent ,
  • -- if fi lt 1, then i is transient
  • Note i is recurrent in finite state MC iff for
    every state j such that i reaches j, then i ? j.

10
Recurrence
  • mi - mean time to return,
  • -
  • if mi lt ?, then i is positive recurrent
  • if mi ?, then i is null recurrent
  • Note all recurrent states in a finite state MC
    are positive recurrent

11
Ergodicity
  • Thm Let Xn be an irreducible MC. Then exactly
    one of following holds
  • all states are positive recurrent
  • all states are null recurrent
  • all states are transient
  • Note any irreducible finite state MC is positive
    recurrent
  • Defn. If a MC is irreducible, aperiodic, and
    positive recurrent, then it is ergodic.
  • Thm An ergodic MC has a unique limiting state
    probability distribution, namely ?j , j 0,1,
  • ?j also known as stationary prob. distr.,
    steady-state prob. distr., equilibrium prob.
    distr.

12
Ergodicity
  • Let ? (?0, ?1, ), then it satisfies
  • ? ? P,
  • ? 1 1
  • where 1 (1, )T

13
Example Statistical Multiplexer
  • discrete time system
  • An, n 0,1, - iid sequence where An no.
    of packets arriving in time interval (n,n 1)
  • let A be rv such that A d An
  • one packet transmitted in (n,n1) if there are
    waiting packets at time n

14
  • Xn - no. of packets in system at time n
  • where (x) 0 if x lt 0, and x otherwise

15
Statistical Multiplexer
  • Q is Xn Markov?
  • assumption that An is iid implies that An is
    independent of Xn , n 0,1,
  • consider Xn 0

16
  • consider Xn i gt 0
  • It follows that, ? i
  • P( Xn1 j X0 i0,... , Xn i)
  • P(Xn1 j Xn i)

17
Statistical Multiplexer
  • Q what is P
  • From proof that system is Markovian
  • P looks like

18
Statistical Multiplexer
  • Q When is MC ergodic?
  • EA gt 1 all states are transient
  • EA lt 1 two cases
  • - a0 a1 1, states 0,1 are positive
    recurrent, all other are transient
  • - a0 a1 lt 1, all states positive recurrent

19
  • EA 1, two cases
  • - a1 1 state 1 is positive recurrent other
    states transient
  • - otherwise, all states null recurrent
  • Interesting case is EA lt 1, a0 a1 lt 1 in
    which case stationary distribution ? exists and
    can be obtained as described earlier.

20
Finite Capacity Statistical Multiplexer
  • Q what if no more than K packets can be in
    multiplexer at one time?
  • system is Markovian
  • throughput, Tput 1 - ?0

21
Finite Capacity Statistical Multiplexer
  • probability packet arrives to a full system and
    is lost, Pf,
  • tricky to compute
  • here is indirect approach
  • Pf 1 Tput /EA
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