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Physics 2211: Lecture 36 Todays Agenda

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Kinetic energy of a rotating system. Moment of inertia ... Physics 2211: Lecture 36, Pg 2. A 3 kg object moving in the x direction has a one-dimensional ... – PowerPoint PPT presentation

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Title: Physics 2211: Lecture 36 Todays Agenda


1
Physics 2211 Lecture 36Todays Agenda
  • Kinetic energy of a rotating system
  • Moment of inertia
  • Discrete particles
  • Continuous solid objects
  • Parallel axis theorem

2
A 3 kg object moving in the x direction has a
one-dimensional elastic collision with a 5.0 kg
object initially at rest. After the collision,
the 5.0 kg object has a velocity of 6.0 m/s in
the x direction. What was the initial speed of
the 3.0 kg object? (1) 6.0 m/s (2) 4.5 m/s
(3) 7.0 m/s (4) 3.5 m/s (5) 9.5 m/s (6) 8.0
m/s
17308
3
A 0.4 kg softball has a velocity of 15 m/s, at an
angle of q50 degrees as shown, just before
making contact with a bat. The ball leaves the
bat 0.2 s later moving horizontally with a speed
of 20 m/s. What is the magnitude of the average
resultant force on the ball while in contact
with the bat? (1) 320 N (2) 82 N (3) 31
N (4) 77 N (5) 65 N (6) 59 N
50 degrees
17163
4
A 12 m uniform board of mass 50 kg rests on a
horizontal frictionless surface. Both the board
and a person standing on one end are initially at
rest. When the person walks to the opposite end
of the plank and stops, the plank moves 7 m
relative to the surface. What is the mass of
the person? (1) 70 kg (2) 86 kg (3) 62
kg (4) 93 kg (5) 55 kg (6) 78 kg
17515
5
Rotation Kinetic Energy
  • Consider the simple rotating system shown below.
    (Assume the masses are attached to the rotation
    axis by massless rigid rods).
  • The kinetic energy of this system will be the sum
    of the kinetic energy of each piece

6
Rotation Kinetic Energy...
  • So but vi ?ri

I has units of kg m2.
7
Rotation Kinetic Energy...
  • The kinetic energy of a rotating system looks
    similar to that of a point particle Point
    Particle Rotating System

v is linear velocity m is the mass.
? is angular velocity I is the moment of
inertia about the rotation axis.
8
Moment of Inertia
  • So where
  • Notice that the moment of inertia I depends on
    the distribution of mass in the system.
  • The further the mass is from the rotation axis,
    the bigger the moment of inertia.
  • For a given object, the moment of inertia will
    depend on where we choose the rotation axis
    (unlike the center of mass).
  • We will see that in rotational dynamics, the
    moment of inertia I appears in the same way that
    mass m does when we study linear dynamics!

9
Calculating Moment of Inertia
  • We have shown that for N discrete point masses
    distributed about a fixed axis, the moment of
    inertia is

where r is the distance from the mass to the
axis of rotation.
Example Calculate the moment of inertia of four
point masses (m) on the corners of a square whose
sides have length L, about a perpendicular axis
through the center of the square
m
m
L
m
m
10
Calculating Moment of Inertia...
  • The squared distance from each point mass to the
    axis is

Using the Pythagorean Theorem
so
L/2
m
m
r
L
m
m
11
Calculating Moment of Inertia...
  • Now calculate I for the same object about an axis
    through the center, parallel to the plane (as
    shown)

r
L
12
Calculating Moment of Inertia...
  • Finally, calculate I for the same object about an
    axis along one side (as shown)

r
m
m
L
m
m
13
Calculating Moment of Inertia...
  • For a single object, I clearly depends on the
    rotation axis!!

I 2mL2
I mL2
I 2mL2
m
m
L
m
m
14
Moment of Inertia
  • A triangular shape is made from identical balls
    and identical rigid, massless rods as shown. The
    moment of inertia about the a, b, and c axes is
    Ia, Ib, and Ic respectively.
  • Which of the following is correct

(1) Ia gt Ib gt Ic (2) Ia gt Ic gt Ib (3)
Ib gt Ia gt Ic
a
b
c
15
Moment of Inertia
  • Label masses and lengths

m
a
L
b
So (2) is correct Ia gt Ic gt Ib
L
c
m
m
16
Calculating Moment of Inertia...
  • For a discrete collection of point masses we
    found
  • For a continuous solid object we have to add up
    the mr2 contribution for every infinitesimal mass
    element dm.
  • We have to do anintegral to find I

17
Moments of Inertia
  • Some examples of I for solid objects

Thin hoop (or cylinder) of mass M and radius R,
about an axis through its center, perpendicular
to the plane of the hoop.
R
18
Moments of Inertia...
Sphere and disk
  • Some examples of I for solid objects

Solid sphere of mass M and radius R, about an
axis through its center.
R
19
Moment of Inertia
  • Two spheres have the same radius and equal
    masses. One is made of solid aluminum, and the
    other is made from a hollow shell of gold.
  • Which one has the biggest moment of inertia about
    an axis through its center?

(1) solid aluminum (2) hollow gold (3) same
hollow
solid
same mass radius
20
Moment of Inertia
  • Moment of inertia depends on mass (same for both)
    and distance from axis squared, which is bigger
    for the shell since its mass is located farther
    from the center.
  • The spherical shell (gold) will have a bigger
    moment of inertia.

ISOLID lt ISHELL
hollow
solid
same mass radius
21
Moments of Inertia...
  • Some examples of I for solid objects

Thin rod of mass M and length L, about a
perpendicular axis through its center.
L
22
Parallel Axis Theorem
  • Suppose the moment of inertia of a solid object
    of mass M about an axis through the center of
    mass, ICM, is known.
  • The moment of inertia about an axis parallel to
    this axis but a distance D away is given by
  • IPARALLEL ICM MD2
  • So if we know ICM , it is easy to calculate the
    moment of inertia about a parallel axis.

23
Parallel Axis Theorem Example
  • Consider a thin uniform rod of mass M and length
    D. Figure out the moment of inertia about an axis
    through the end of the rod.
  • IPARALLEL ICM MD2

DL/2
M
CM
x
L
ICM
IEND
24
Recap of todays lecture
  • Kinetic energy of a rotating system
  • Moment of inertia
  • Discrete particles
  • Continuous solid objects
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