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Adv Physics

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Adv Physics Chapter 23 Section 3 Chapter 25 Section 1 Lenses Lens equation 1/f = 1/d0 + 1/di Magnification equation m = -di / do Convex Concave f + - do + + di ... – PowerPoint PPT presentation

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Title: Adv Physics


1
Adv Physics
  • Chapter 23 Section 3
  • Chapter 25 Section 1

2
Lenses
  • Lens equation
  • 1/f 1/d0 1/di
  • Magnification equation
  • m -di / do

3
Convex Concave
f -
do
di real - virtual - virtual
m upright - inverted upright
4
Sample Problem
  • A 2 cm tall object is placed 7.5 cm to the left
    of a convex lens whose focal length is 11.8 cm.
    Find the image distance and determine whether the
    image is real or virtual. Determine the
    magnification and the image height.

5
Sample Problem
  • An object is placed 7.1 cm to the left of a
    diverging lens whose focal length is 5.08 cm.
    Find the image distance and determine whether the
    image is real or virtual. Obtain the
    magnification.

6
The Eye
  • Air to cornea (n1.38)
  • Cornea to aqueous humor (n1.34)
  • Aqueous humor to lens (n1.42)
  • Lens to vitreous humor (n1.34)
  • Light strikes the retina where image is formed

7
Accomodation
  • Process of adjusting the shape of the lens to
    focus on different objects
  • - accomplished using the ciliary muscles
  • - muscles are relaxed to make the lens flatter
    to see distant objects
  • - muscles are tightened to make the lens more
    curved to see close objects

8
Normal Vision
  • Near point closest point that can be seen as a
    clear image
  • - usually at about 25 cm from the eye
  • Far point farthest object that can be seen as a
    clear image
  • -so far away we call it infinity

9
Myopia
  • Nearsighted
  • Defect in the eye in which the eye is unable to
    see clearly distant objects
  • Image formed by eye is in front of retina

10
Myopia
  • Corrected using a concave lens
  • Image is now formed at the far point
  • Using a concave lens alters the near point!

11
Sample Problem
  • Find the optical power necessary to correct an
    eye with a far point of 50 cm. Neglect the
    distance from the lens to the cornea.
  • Hint Optical power 1/f
  • If the eyes near point was 10 cm, what is the
    eyes corrected near point?

12
Hyperopia
  • Farsighted
  • Defect of the eye in which the eye is unable to
    see close objects
  • Image is formed behind the retina

13
Hyperopia
  • Corrected using a convex lens
  • Image is now formed at the near point
  • Using a convex lens alters the far point!

14
Sample Problem
  • Find the power of a lens designed for reading
    purposes to correct an eye with a near point of
    75 cm. Assume a standard reading distance of 25
    cm. Neglect the distance from the cornea to the
    corrective lens.

15
Blind Spot
  • Region of retina where there are no
    photosensitive receptors and the optic nerve
    leaves
  • Approx 1.5 mm in diameter
  • when image is formed on this spot it is lost

16
Fovea
  • Most sensitive part of retina
  • Near its center
  • Approx 0.4 mm in diameter
  • Image formed here is most clearly seen
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