Title: Topic 7: Equilibrium SL Le Chatelier
1Topic 7 Equilibrium SLLe Chateliers Principle
- 7.2.3 Apply Le Chateliers principle to predict
qualitative effects of changes of temperature,
pressure and concentration on the position of
equilibrium and on the value of the equilibrium
constant. - 7.2.4 State and explain the effect of a catalyst
on an equilibrium reaction. - 7.2.5 Apply the concepts of kinetics and
equilibrium to industrial process - Suitable examples include the Haber and Contact
processes.
2LeChateliers Principle
- When a system at equilibrium is placed under
stress, the system will undergo a change in such
a way as to relieve that stress.
3Le Chatelier Translated
- When you take something away from a system at
equilibrium, the system shifts in such a way as
to replace what youve taken away. - When you add something to a system at
equilibrium, the system shifts in such a way as
to use up what youve added.
4Le Chatelier Example 1
A closed container of ice and water at
equilibrium. The temperature is raised.
Ice Energy lt-- gt Water
The equilibrium of the system shifts to the
_______ to use up the added energy.
right
5Le Chatelier Example 2
A closed container of N2O4 and NO2 at
equilibrium. NO2 is added to the container.
N2O4 (g) Energy lt - - gt 2 NO2 (g)
The equilibrium of the system shifts to the
_______ to use up the added NO2.
left
6Le Chatelier Example 3
A closed container of water and its vapor at
equilibrium. Vapor is removed from the system.
water Energy ? vapor
The equilibrium of the system shifts to the
_______ to replace the vapor.
right
7Le Chatelier Example 4
A closed container of N2O4 and NO2 at
equilibrium. The pressure is increased.
N2O4 (g) Energy lt - - gt 2 NO2 (g)
The equilibrium of the system shifts to the
_______ to lower the pressure, because there are
fewer moles of gas on that side of the equation.
left
8Pressure Changes to system
- If the volume decreases, the concentration
increases, and there will be a shift to the side
with the less amount of moles. - If the volume increases, the concentration
decreases, and there will be a shift to the side
with the more amount of moles.
9Example
- If I increase the pressure, where is the shift?
- (right)
- If I decrease the pressure, where is the shift?
(left) - 2SO2 O2 lt--gt 2SO3
- (3moles) (2moles)
10Effect of Concentration
- If you add more reactant, it shifts to the right
increasing the formation of product, using up the
reactants. - If you add product, it shifts to the left
- If you remove product, it shifts to the right,
increasing the formation of product. - If you remove reactant, it shifts to the left
11Effect of temperature
- Energy is treated as a reactant if endothermic
equation, and as a product if exothermic
equation. - If cooling a system, then it shifts so more heat
is produced. - If heating a system, then it shifts so extra heat
is used up.
12Example for temp. changes for Endothermic Reaction
- Heating the below reaction causes the system to
shift to the right more products, because you
treat energy like a reactant. - 2NaCl H2SO4 energy lt -- gt 2HCl Na2SO4
- Cooling the above reaction causes the system to
shift to the left less reactants, so need to
make up more
13Effect of temp change on exothermic reactions
- Heating the below reaction causes the system to
shift to the left, to use up the extra heat. - 2SO2 O2 lt--gt 2SO3 energy
- Cooling the above reaction causes the system to
shift to the right, to make up for the lost heat.
14The effect of a catalyst on equilibrium
- Adding a catalyst speeds up a reaction by
providing an alternative mechanism with a lower
activation energy, thus speeding up both the
forward and backward reaction rate. - It shortens the time needed to attain equilibrium
concentrations - It has no effect on the position of equilibrium,
however equilibrium will be attained more quickly.
15Haber Process
- N2(g) 3H2(g) lt - - gt 2NH3(g) ?H -92 kJ/mol
- Mixtures volume is compressed and passed over a
heated iron catalyst. - Conditions for his equilibrium is critical.
- High pressure is favourable due to 4 moles on
left and 2 moles on right. Increased pressure
causes a shift to the left, favouring product
formation. - This is expensive to due and most production
plants will resist compressing gases in terms of
operating costs. Compromise will be met.
16Compromise
- This is an exothermic reaction, so low
temperatures would be favourable to produce
product. - Low temps mean low reaction rates, so we may get
a higher yield but it will take a long time to
get it. Not good for business. - A compromise temp, as well as the use of a
catalyst will aid in speeding up the reaction to
a more acceptable standard.
17Typical conditions
- Pressure between 20-100 MPa (200-1000 atm)
- Temperatures around 700 K
- The reaction is not allowed to reach equilibrium,
because reaction rate decreases as we approach
equilibrium, and typically only 20 of N2 and H2
is converted. - The gases are cooled and NH3 is condensed and
removed, leaving unused N2 and H2 available for
further production.
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19http//www.absorblearning.com/media/item.action?qu
ick128
- Animation of Haber process
20Ammonias Uses
- Manufacture of fertilizers (ammonia salts and
urea) - Manufacturing nitrogen used in polymers for the
fabrication of nylon - Used in the production of explosives (TNT,
dynamite)
21Contact Process
- Production of sulfuric acid by the oxidation of
sulfur. - Sulfur is burnt in air to form sulfur dioxide
- S(s) O2(g) lt - - gt SO2(g)
- Sulfur dioxide is mixed with air and passed over
vanadium(V)oxide catalyst to produce sulfur
trioxide. - 2SO2(g) O2(g) lt - - gt 2SO3(g) ?H -196 kJ/mol
- Sulfur trioxide is reacted with water to produce
sulfuric acid. - SO3(g) H2O(l) ? H2SO4(l)
22More money, more SO3
- High pressure would favour the formation of SO3
in the 2nd step, however its too expensive. - Reactants are compressed to 2 atm to achieve the
desired flow rate in the reactor. - Pure O2 would drive the equilibrium to the right,
however its an unnecessary expense. - Low temperatures, because its exothermic, would
be best, but it slows the rate too much.
23Compromised conditions
- Temp between 700-800 K (fast initial reaction
rate) - The use of a finely divided V2O5 catalyst
- Oxidation is done in converters at lower
temperatures (slows reaction rate) - Overall conversion is 90 to SO3
24http//www.absorblearning.com/media/item.action?qu
ick12b
- Contact process animation
25Uses of H2SO4
- Fertilizers (converting insoluble phosphate rock
into soluble phosphates) - Polymers
- Detergents
- Paints
- Pigments
- Petrochemical industry
- Processing of metals
- Electrolyte in car batteries
26- Le Chateliers principle is a memory aid, it
doesnt explain why these changes occur. - Listen carefully and read over text pages to help
you develop further understanding of explanation. - http//www.mhhe.com/physsci/chemistry/essentialche
mistry/flash/lechv17.swf
27- Haber process notes
- http//www.chemguide.co.uk/physical/equilibria/hab
er.html