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TELECOMMUNICATIONS

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All of these variations can be represented by a general oscillator circuit. The equivalent circuit on the right-hand side of the figure is used to model ... – PowerPoint PPT presentation

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Title: TELECOMMUNICATIONS


1
TELECOMMUNICATIONS
  • Dr. Hugh Blanton
  • ENTC 4307/ENTC 5307

2
RADIO FREQUENCY OSCILLATORS
  • In the most general sense, an oscillator is a non
    linear circuit that converts DC power to an AC
    waveform.
  • Most oscillators used in wireless systems provide
    sinusoidal outputs, thereby minimizing undesired
    harmonics and noise sidebands.

3
  • The basic conceptual operation of a sinusoidal
    oscillator can be described with the linear
    feedback circuit.

Vo(w)
Vi (w)
4
  • An amplifier with voltage gain A has an output
    voltage Vo.
  • This voltage passes through a feedback network
    with a frequency dependent transfer function H(w)
    and is added to the input Vi of the circuit.
  • Thus the output voltage can be expressed as

5
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6
  • If the denominator of the previous equation
    becomes zero at a particular frequency, it is
    possible to achieve a nonzero output voltage for
    a zero input voltage, thus forming an oscillator.
  • This is known as the Barkhausen criterion.
  • In contrast to the design of an amplifier, where
    we design to achieve maximum stability,
    oscillator design depends on an unstable circuit.

7
General Analysis
  • There are a large number of possible RF
    oscillator circuits using bipolar or field-effect
    transistors in either common emitter/source,
    base/gate, or collector/drain configurations.
  • Various types of feedback networks lead to the
    well-known oscillator circuits
  • Hartley,
  • Colpitts,
  • Clapp, and
  • Pierce

8
  • All of these variations can be represented by a
    general oscillator circuit.

9
  • The equivalent circuit on the right-hand side of
    the figure is used to model either a bipolar or a
    field-effect transistor.
  • We can simplify the analysis by assuming real
    input and output admittances of the transistor,
    defined as Gi and Go, respectively, with a
    transistor transconductance gm.
  • The feedback network on the left side of the
    circuit is formed from three admittances in a
    bridged-T configuration.
  • These components are usually reactive elements
    (capacitors or inductors) in order to provide a
    frequency selective transfer function with high
    Q.

10
  • A common emitter/source configuration can be
    obtained by setting V2 0, while common
    base/gate or common collector/drain
    configurations can be modeled by setting either
    V1 0 or V4 0, respectively.

11
  • The feedback path is achieved by connecting node
    V3 to node V4.
  • Writing Kirchoffs current law for the four
    voltage nodes of the circuit gives the following
    matrix equation

12
  • Recall from circuit analysis that if the ith node
    of the circuit is grounded, so that V 0, the
    matrix will be modified by eliminating the ith
    row and column, reducing the order of the matrix
    by one.
  • Additionally, if two nodes are connected
    together, the matrix is modified by adding the
    corresponding rows and columns.

13
Oscillators Using a Common Emitter BJT
  • Consider an oscillator using a bipolar junction
    transistor in a common emitter configuration.
  • V2 0, with feedback provided from the
    collector, so that V3 V4.
  • In addition, the output admittance of the
    transistor is negligible, so we set Go 0.

14
  • These conditions serve to reduce the matrix to
    the following
  • where V V3 V4

15
  • If the circuit is to operate as an oscillator,
    then the new determinant must be satisfied for
    nonzero values of V1 and V, so the determinant of
    the matrix must be zero.
  • If the feedback network consists only of lossless
    capacitors and inductors, then Y1,Y2, and Y3 must
    be imaginary, so we let Y1 jB1, Y2 jB2. and
    Y3 jB3.
  • Also, recall that the transconductance, gm , and
    transistor input conductance are Gi, are real.

16
  • Then the determinant simplifies to

17
  • Since gm and Gi are positive, X1 and X2 must have
    the same sign, and therefore are either both
    capacitors or both inductors.
  • Since X1 and X2 have the same sign, X3 must be
    opposite in sign from X1 and X2, and therefore
    the opposite type of component.
  • This conclusion leads to two of the most commonly
    used oscillator circuits.

18
Colpitts Oscillator
  • If X1 and X2 are capacitors and X3 is an
    inductor, we have a Colpitts oscillator.

19
Hartley Oscillator
  • If we choose X1 and X2 to be inductors, and X3 to
    be a capacitor, we have a Hartley oscillator.

20
Lab 5
  • Implement the following Colpitts oscillator using
    PSpice.

21
  • Determine the frequency of the tank circuitwhich
    sets the oscillation frequency.
  • When we display the output waveform (from 0 to 10
    ms), there is no signal!
  • The problem is one of insufficient spark.
  • One solution is to pre-charge one of the tank
    capacitors.
  • Using either CT1 or CT2, initialize either
    capacitor with a small voltage (such as .1 v).

22
  • Again, display the output waveform from 0 to 10
    ms.
  • This time the signal existsbut clearly, it has
    not reached steady-state conditions by 10 ms.
  • Using the No-Print Delay option, display the
    waveform from 200 to 210 ms.
  • Measure the resonant frequency and compare it to
    the calculated value.
  • Are they similar?

23
  • Add a plot of Vf (the feedback signal shown in
    the figure).
  • Is Vf 180? out of phase with Vout?
  • Generate a frequency spectrum for the Colpitts
    oscillator.
  • Is there a DC component?
  • Does the fundamental frequency approximately
    equal measured the time-domain frequency?
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