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On k-Edge-magic Cubic Graphs

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On k-Edge-magic Cubic Graphs Sin-Min Lee, San Jose State University Hsin-hao Su*, Stonehill College Yung-Chin Wang, Tzu-Hui Institute of Technology – PowerPoint PPT presentation

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Title: On k-Edge-magic Cubic Graphs


1
On k-Edge-magic Cubic Graphs
Sin-Min Lee, San Jose State University Hsin-hao
Su, Stonehill College Yung-Chin Wang, Tzu-Hui
Institute of Technology 24th MCCCC At Illinois
State University September 11, 2010
2
Supermagic Graphs
  • For a (p,q)-graph, in 1966, Stewart defined that
    a graph labeling is supermagic iff the edges are
    labeled 1, 2, 3, , q so that the vertex sums are
    a constant.

3
k-Edge-Magic Graphs
  • A (p,q)-graph G is called k-edge-magic (in short
    k-EM) if there is an edge labeling l E(G) ? k,
    k1, , kq-1 such that for each vertex v, the
    sum of the labels of the edges incident with v
    are all equal to the same constant modulo p
    i.e., l(v) c for some fixed c in Zp.
  • If k 1, then G is said to be edge-magic.

4
Examples 1-Edge-Magic
  • The following maximal outerplanar graphs with 6
    vertices are 1-EM.

5
Examples 1-Edge-Magic
  • In general, G may admits more than one labeling
    to become a k-edge-magic graph with different
    vertex sums.

6
Examples k-Edge-Magic
  • In general, G may admits more than one labeling
    to become a k-edge-magic graph.

7
Necessary Condition
  • A necessary condition for a (p,q)-graph G to be
    k-edge-magic is
  • Proof
  • The sum of all edges is
  • Every edge is counted twice in the vertex sums.

8
k-Edge-Magic is periodic
  • Theorem If a (p,q)-graph G is k-edge-magic then
    it is ptk-edge-magic for all t 0 .

9
Cubic Graphs
  • Definition 3-regular (p,q)-graph is called a
    cubic graph.
  • The relationship between p and q is
  • Since q is an integer, p must be even.

10
One for All
  • Theorem If a cubic graph is k-edge-magic, then
    it is k-edge-magic for all k.
  • Proof
  • Since every vertex is of degree 3, by adding or
    subtracting 1 to each adjacent edge, the vertex
    sum remains the same.

11
Examples Complete Bipartite
  • The complete bipartite graph K3,3 is k-edge-magic
    for all k.

12
Not Order 4s
  • Theorem A cubic graph with order 4s is not
    k-edge-magic for all k.
  • Proof
  • The number of edges is 6s.
  • The necessary condition implies
  • It is impossible for all k.

13
Möbius Ladders
  • The concept of Möbius ladder was introduced by
    Guy and Harry in 1967.
  • It is a cubic circulant graph with an even number
    n of vertices, formed from an n-cycle by adding
    edges (called rungs) connecting opposite pairs
    of vertices in the cycle.

14
Möbius Ladders
  • A möbius ladder ML(2n) with the vertices denoted
    by a1, a2, , a2n. The edges are then a1, a2,
    a2, a3, a2n, a1, a1, an1, a2, an2,
    , an, a2n.

15
Labeling Idea
  • Splits all edges into two subsets. The first
    subset contains all the edges of C2n. The second
    set contains all middle edges, which forms a
    perfect matching.
  • Construct a graceful labeling for the first
    subset, i.e., an arithmetic progression. The rest
    numbers also form an arithmetic progression.

16
Labeling Method 1
  • Divides the numbers into three subsets 0, 1, 2,
    3, , 2k n-1, 2n, 2n1, 2n2, 2n3, , 2n2k
    3n-1, n, n1, n2, n3, , n2k 2n-1.
  • Use the first two subsets to label C2n by the
    following sequence k1, 1, k2, 2, k3, 3, ,
    2k, k, 0, k1, 1, k2, 2, k3, 3, , 2k, k, 0.

17
Example of Method 1
18
Labeling Method 2
  • We label the edges by 1, 1, 2, 2, 3, 3, , k1,
    k1, nk2, k2, nk3, k3, , 2n, 2k1.
  • Label the rest numbers, k2, k3, , nk1 to the
    edges in the middle.

19
Example of Method 2
20
Cylinder Graphs
  • Theorem (Lee, Pigg, Cox 1994) The cylinder
    graph CnxP2 is a 1-edge-magic graph if n is odd.

21
Cylinder Graphs Examples
22
Generalized Petersen Graphs
  • The generalized Petersen graphs P(n,k) were first
    studied by Bannai and Coxeter.
  • P(n,k) is the graph with vertices vi, ui 0 i
    n-1 and edges vivi1, viui, uiuik, where
    subscripts modulo n and k.
  • Theorem The generalized Petersen graph P(n,t) is
    a k-edge-magic graph for all k if n is odd.

23
Gen. Petersen Graph Ex.
24
Order 6
  • Theorem A cubic graph with order 6 is
    k-edge-magic for all k.

25
Order 10
26
Order 14 Transformation
27
Order 14 Transformation
28
Conjecture
  • Conjecture A cubic graph with order 4s2 is
    k-edge-magic for all k.
  • With the previous examples, this is a reasonable
    extension of a conjecture by Lee, Pigg, Cox in
    1994.

29
Mod(m)-Edge-Magic Graphs
  • A (p,q)-graph G is called Mod(m)-edge-magic (in
    short Mod(m)-EM) if there is an edge labeling l
    E(G) ? 1,2,,q such that for each vertex v, the
    sum of the labels of the edges incident with v
    are all equal to the same constant modulo m
    i.e., l(v) c for some fixed c in Zm.

30
Relationship between EM
  • Theorem For a graph with order p, if it is
    1-edge-magic, then it is mod(m)-edge-magic for m
    to be a factor of p.
  • Proof
  • Since m is a factor of p, the constant sum in Zp
    remains constant in Zm.

31
Counterexample
32
Proof
  • Since it is mod(5)-edge-magic, we have relations
    as followings
  • a b l m, (1)
  • b c k l, (2)
  • h i f e, (3)
  • From relations (1) and (2), we have
  • a k c m. (4)

33
Proof (continued)
  • Therefore we have g d. Then we have a new
    relation
  • h f i e. (5)
  • From relations (3) and (5), we have
  • i f.
  • Then we have
  • h e, and
  • g j d.

34
Proof (continued)
  • Without losing generality, we say d 0, e 1
    and f 4.
  • From relation (4), we have a 1, k 4, c 2, m
    3 or a 1, k 4, c 3, m 2 or a 2, k
    3, c 1, m 4 or a 2, k 3, c 4, m 1.
  • Here, we already run out of 1 and 4 and only 2
    and 3 left in the set.

35
Proof (continued)
  • For the case a 1, we have b 2 and n 2. If
    forces that o 3 and l 3. But m 3 or 2 cant
    make the sum on v9 equal to 0. This is a
    contradiction.
  • With the same argument, we can show that all the
    possibilities cant be true.
  • Therefore it is not mod(5)-edge-magic.

36
Future Problems
  • Do we have just a few counterexamples?
  • Any better necessary condition?
  • Possible sufficient conditions?
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