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Colligative Properties

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Title: Colligative Properties


1
Colligative Properties
  • Kausar Ahmad
  • Kulliyyah of Pharmacy

2
Introduction
  • Solutions, especially liquid solutions, generally
    have markedly different properties than either
    the pure solvent or the solute.
  • For example, a solution of sugar in water is
    neither crystalline like sugar nor tasteless like
    water. Some of the properties unique to solutions
    depend only on the number of dissolved particles
    and not their identity.
  • Such properties are called colligative
    properties.
  • Colligative Properties are those properties of a
    liquid that may be altered by the presence of a
    solute.

3
Definition
  • Colligative property
  • A property that depends only on the amount of
    solute in a solution
  • and not the identity of the solute
  • Non-colligative properties
  • depend on the identity of the dissolved solute
    and the solvent

4
Colligative vs Non-colligative
  • compare the properties of a 1.0 M aqueous sugar
    solution to a 0.5 M solution of table salt (NaCl)
    in water.
  • Despite the concentrations, both solutions have
    precisely the same number of dissolved particles
    because each sodium chloride unit creates two
    particles upon dissolution - a sodium ion, Na,
    and a chloride ion, Cl-.
  • Therefore, any difference in the properties of
    those two solutions is due to a non-colligative
    property.
  • Both solutions have the same freezing point,
    boiling point, vapor pressure, and osmotic
    pressure because those colligative properties of
    a solution only depend on the number of dissolved
    particles.

5
Non-Colligative Properties
  • The sugar solution is sweet and the salt solution
    tastes salty.
  • Therefore, the taste of the solution is not a
    colligative property.
  • Another non-colligative property is the color of
    a solution.
  • A 0.5 M solution of CuSO4 is bright blue in
    contrast to the colorless salt and sugar
    solutions. Other non-colligative properties
    include viscosity, surface tension, and
    solubility.

6
Examples of Colligative Properties
  • vapor pressure,
  • freezing point depression (melting)
  • boiling point elevation,
  • osmotic pressure.
  • All of these properties ultimately relate to the
    vapor pressure.

7
Effect of Solute on Vapour Pressure
  • When a nonvolatile solute is dissolved in a
    solvent, the vapor pressure of the resulting
    solution is lower than that of the pure solvent.
  • The amount of the vapor pressure lowering is
    proportional to the amount of solute and not its
    identity.
  • Therefore, vapor pressure lowering is a
    colligative property.
  • The equation that describes that phenomenon is
    called Raoult's law.

8
The Vapor Pressure of a Solution is Lower than
that of the Pure Solvent On the surface of the
pure solvent (shown on the left) there are more
solvent molecules at the surface than in the
right-hand solution flask. Therefore, it is more
likely that solvent molecules escape into the gas
phase on the left than on the right. Therefore,
the solution should have a lower vapor pressure
than the pure solvent.
9
Boiling point
  • Boiling point elevation is a colligative property
    related to vapor pressure lowering.
  • The boiling point is defined as the temperature
    at which the vapor pressure of a liquid equals
    the atmospheric pressure.
  • Due to vapor pressure lowering, a solution will
    require a higher temperature to reach its boiling
    point than the pure solvent.

10
Freezing Point
  • Every liquid has a freezing point - the
    temperature at which a liquid undergoes a phase
    change from liquid to solid.
  • When solutes are added to a liquid, forming a
    solution, the solute molecules disrupt the
    formation of crystals of the solvent.
  • That disruption in the freezing process results
    in a depression of the freezing point for the
    solution relative to the pure solvent.

11
Osmotic Pressure
  • When a solution is separated from a volume of
    pure solvent by a semi-permeable membrane that
    allows only the passage of solvent molecules, the
    height of the solution begins to rise.
  • The value of the height difference between the
    two compartments reflects a property called the
    osmotic pressure of a solution.

12
Phase Diagrams and the effect of solutes on
freezing and boiling points
13
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14
Factors that affect the magnitude of the changes
in melting point and boiling point.
  • Concentration
  • Effect of ionic compounds

15
Raoult's Law
  • The French chemist Francois Raoult discovered the
    law that mathematically describes the vapor
    pressure lowering phenomenon.
  • Raoult's law states that the vapor pressure of a
    solution, P1, equals the mole fraction of the
    solvent, X1 , multiplied by the vapor pressure of
    the pure solvent, Po.
  • P1 P1o x X1

16
Total Vapour Pressure
  • In an ideal solution made up of two volatile
    components
  • P p1 p2
  • In an ideal solution made up of one volatile
    component
  • P p1

17
A Visual Demonstration of Raoult's Law
  • Description The intensity of color of bromine
    vapor is reduced by placing a colorless volatile
    liquid into the same container.
  • Source Journal of Chemical Education - Vol. 67
  • Year or vol 1990 page 598

18
Deviations from Raoult's law
  • the "law" is approximately obeyed by most
    solutions, some show deviations from the expected
    behavior.
  • Deviations from Raoult's law can either be
    positive or negative.
  • A positive deviation means that there is a higher
    than expected vapor pressure above the solution
  • P1 gt P1o x X1
  • A negative deviation means that we find a lower
    than expected vapor pressure for the solution
  • P1 lt P1o x X1

19
Reason for the deviation
  • consideration of the vapor pressure lowering
    event - we assumed that the solute did not
    interact with the solvent at all.
  • If the solute is strongly held by the solvent,
    the solution will show a negative deviation from
    Raoult's law, because the solvent will find it
    more difficult to escape from solution.
  • If the solute and solvent are not as tightly
    bound to each other as they are to themselves,
    then the solution will show a positive deviation
    from Raoult's law because the solvent molecules
    will find it easier to escape from solution into
    the gas phase.

20
Ideal Solutions
  • Solutions that obey Raoult's law are called ideal
    solutions because they behave exactly as we would
    predict.
  • Solutions that show a deviation from Raoult's law
    are called non-ideal solutions or real solutions
    because they deviate from the expected behavior.
  • Very few solutions actually approach ideality,
    but Raoult's law for the ideal solution is a good
    enough approximation for the non- ideal solutions
    that we will continue to use Raoult's law.

21
Deviation from Raoults Law end of lecture
1/3
22
Vapor Pressure of a Mixture Raoult's Law
  • The measurement of pressure exerted by a vapour
    is demonstrated using barometers.
  • Vapor pressure varies with the strength of the
    intermolecular forces in the liquid.
  • We can calculate the vapor pressure of a mixture
    using Raoult's law.

23
Example Consider a solution that contains 0.6
mole fraction of decane and 0.4 mole fraction of
diethyl ether.
We can calculate the vapor pressure of a mixture
using Raoult's law P P1o x X1 P2o x X2
(5 x 0.6) (460 x 0.4) 187
24
Change in Boiling Point
  • One consequence of Raoult's law is that the
    boiling point of a solution made of a liquid
    solvent with a nonvolatile solute is greater than
    the boiling point of the pure solvent.
  • For a solution, the vapor pressure of the solvent
    is lower at any given temperature.
  • Therefore, a higher temperature is required to
    boil the solution than the pure solvent.
  • The change in boiling point is

25
  • m is molality, because molality is temperature
    independent.
  • Kb is a boiling point elevation constant that
    depends on the particular solvent used.
  • i is the van't Hoff factor and represents the
    number of dissociated moles of particles per mole
    of solute.
  • The van't Hoff factor is 1 for all
    non-electrolyte solutes and equals the total
    number of ions released for electrolytes.
  • Therefore, the value of i for Na2SO4 is 3 because
    that salt releases three moles of ions per mole
    of the salt.

26
Change in Freezing Point
  • In order for a liquid to freeze it must achieve a
    very ordered state that results in the formation
    of a crystal.
  • If there are impurities in the liquid, i.e.
    solutes, the liquid is inherently less ordered.
  • Therefore, a solution is more difficult to freeze
    than the pure solvent so a lower temperature is
    required to freeze the liquid.
  • The change in freezing point is
  • Note that the sign of the change in freezing
    point is negative because the freezing point of
    the solution is less than that of the pure
    solvent.

27
Awan Q Why can adding salt to ice water make the
ice melt slower? Adding salt to the ice/water
mix causes a temperature drop that slows the
melting rate and increases the freezing rate 3.
The net result is that the ice melts more and
more slowly after the initial addition of salt.
Why does salt melt ice? In pure water, at 0C,
ice melts just as fast as water freezes. You
won't see any of the ice melt as long as the
freezing rate and melting rates are exactly equal
1. Adding salt (or any foreign substance) to
the water upsets the delicate balance between
freezing and melting. Fewer water molecules reach
the surface of the ice in a given time, so water
freezes more slowly. The melting rate isn't
changed by the salt, so melting "wins" 2.
Does adding salt to ice and water cause a
temperature drop? Yes. This is how old-fashioned
ice cream makers lowered the temperature of the
ice cream below water's ordinary freezing point.
A mixture of rock salt, ice, and water packed in
the bucket around the ice cream mix can bring the
temperature down as low as -21C. Why does the
temperature drop? Energy is required to snap the
hydrogen bonds that hold the ice together. The
melting ice draws that energy from the
surrounding solution as heat. See these
previous questions for more "Why does salt melt
ice?" (includes a Flash simulation of freezing
point depression) Author Fred Senese
senese_at_antoine.frostburg.edu http//antoine.frostb
urg.edu/chem/senese/101/solutions/faq/why-salt-coo
ls-icewater.shtml
28
Molal Boiling Point Elevation and Freezing Point
Depression Constants at 1 Atm pressure
Thus the boiling point of water would increase
0.52 oC for a one molal solution, while the
freezing point of this solution would decrease by
1.86 oC.
29
Effect of ionic compounds
  • A tenth of a mole of sugar or a tenth of a mole
    of glycerine dissolved in water will have exactly
    the same effect on the boiling and freezing
    points even though sugar is a much bigger
    molecule.
  • However, a tenth of a mole of an ionic compound
    such as NaCl,, has an effect on the melting and
    boiling points that is almost twice what we would
    observe for sugar.
  • The simple reason for this effect is that salt
    ionizes into Na and Cl- ions in water
  • these ions act as independent particles on the
    vapor pressure of water.
  • Thus, to a first approximation, we may simply
    multiply the concentration of the salt by the
    number of ions it will form when dissolved in
    water.
  • Thus NaCl, NaNO3, and CaCO3 would have
    multipliers of two, while Na2SO4, and CaCl2 would
    have multipliers of three.

30
Vant Hoff factor
  • In dilute solutions, ionic compounds have simple
    multiple effects, but as the solution
    concentration increases the multiplier effect
    diminishes.
  • This phenomenon was first discovered by van't
    Hoff and is generally called the van't Hoff
    factor.
  • As concentration increases, some of the ions
    floating in solution find one another and form
    ion pairs, in which two oppositely charged ions
    briefly stick together and act as a single
    particle.
  • the higher the concentration, the more likely it
    is that two ions will find one another.

31
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32
Osmotic Pressure
  • When a solution and the pure solvent used in
    making that solution are placed on either side of
    a semipermeable membrane, more solvent molecules
    flow out of the pure solvent side of the membrane
    than solvent flows into the pure solvent from the
    solution side of the membrane.
  • That flow of solvent from the pure solvent side
    makes the volume of the solution rise.
  • When the height difference between the two sides
    becomes large enough, the net flow through the
    membrane ceases due to the extra pressure exerted
    by the excess height of the solution chamber.
  • Converting that height of solvent into units of
    pressure gives a measure of the osmotic pressure
    exerted on the solution by the pure solvent.
  • P rgh
  • P stands for pressure, r is the density of the
    solution, and h is the height of the solution.

33
Setup for Measuring the Osmotic Pressure of a
Solution
34
Effect of concentration on osmotic pressure
  • PV inRT
  • Since n / V gives the concentration of the solute
    in units of molarity, M.
  • P iMRT

End of lecture 2/3
35
Application of Raoults LawDistillation
36
DISTILLATION
37
Distillation of Binary MixtureIdeal Solution
  • When a liquid and its vapour are in equilibrium,
    vapour is richer in the more volatile component
    compared to liquid mixture
  • At equilibrium, liquid and vapour phase can be
    separated and analysed

38
Binary Mixtures Obeying Raoults Law Ideal
Solution
  • Attractive forces between molecules of different
    component equal those of the same component.A-B
    A-A B-B
  • Without a maximum or minimum at intermediate
    compositions.
  • No change in properties of components (except
    dilution to form solution).
  • Vapour pressure, refractive index, surface
    tension and viscosity of solution are averages of
    properties of pure individual constituents.
  • No heat evolved or absorbed during mixing
    process.
  • No change in solution temperature.
  • Final properties of solution are additive
    properties of individual constituents.
  • No shrinkage or expansion.
  • E.g. methyl alcohol-water, benzene-toluene,
    methanol-ethanol.

39
Definition - Azeotropic Mixture
  • Describes a mixture of miscible liquids which
    boils at a constant composition and thus the
    composition cannot be changed by simple
    distillation
  • Composition of vapour similar to that of liquid
  • The composition as well as the boiling point of
    an azeotropic mixture changes with pressure
  • If a liquid mixture represented by a composition
    X1 is distilled, the vapour has composition X2
    and condenses to form a liquid of that
    composition.
  • Distillation starting at composition X1 produces
    an azeotropic mixture Z as the distillate, and
    the residue tends towards pure B
  • Similarly, a mixture of composition Y1, yields an
    azeotropic mixture as distillate, and pure A as a
    residue

40
Positive Deviation from Raoults Law
  • Vapour pressure greater than expected from
    Raoults law.
  • The two components differ in properties e.g.
    polarity
  • Attractive forces A-B lt A-A or B-B
  • Escaping tendency higher
  • The extent of deviation is expressed
    quantitatively as activity coefficient (f) of the
    component.
  • A max is found in vapour pressure-composition
    curve
  • Heat is absorbed during the mixing process
  • Solution temperature decreases
  • Final volume of solution increases
  • Expansion
  • Presence of azeotropic mixtures lead to min
    boiling point
  • Examples 1. ethyl, isopropyl, n-propyl alcohol
    - water,2. volatile drug (methyl amphetamine)
    chloroform - ethanol

41
Positively deviated solution mixturewith a
minimum boiling point
  • The mixture shows positive deviation from
    Raoults law
  • A minimum boiling point is obtained
  • The solution has an azeotropic mixture whose
    vapour pressure is the highest and boiling point
    is the lowest
  • example of a positive azeotrope is 95.6 ethanol
    and 4.4 water (by weight). Ethanol boils at
    78.4C, water boils at 100C, but the azeotrope
    boils at 78.1C

42
Distillation of positive azeotrope 95.6 ethanol
and 4.4 water
  • distillation of any mixture will result in the
    distillate being closer in composition to the
    azeotrope than the starting mixture.
  • E.g. if a 50/50 mixture of ethanol and water is
    distilled once, the distillate will be 80
    ethanol and 20 water i.e. closer to the
    azeotropic mixture than the original.
  • Distilling the 80/20 mixture produces a
    distillate that is 87 ethanol and 13 water.
  • Further repeated distillations will produce
    mixtures that are progressively closer to the
    azeotropic ratio of 95.5/4.5.
  • increasing distillations will not give distillate
    that exceeds the azeotropic ratio.

43
Negative Deviation from Raoults Law
  • Vapour pressure of solution less than that
    expected from Raoults law
  • Attractive forces A-B gt A-A or B-B
  • Escaping tendency lower
  • Heat is evolved during the mixing process
  • Solution temperature increases
  • Final volume of solution decreases
  • Shrinkage
  • A min is found in vapour pressure composition
    curve
  • Presence of azeotropic mixtures lead to max
    boiling point
  • E.g. pyridine-acetic acid, chloroform-acetone
    (formation of loose compounds from hydrogen
    bonding), formation of hydrates, nitric
    acid-water, sulfuric acid-water.

44
Negatively deviated solutionwith maximum boiling
point
  • Mixtures showing negative deviation from Raoults
    law
  • A maximum boiling point is obtained
  • The solution has an azeotropic mixture whose
    vapour pressure is the lowest and the boiling
    point is the highest
  • example of a negative azeotrope is 20.2 hydrogen
    chloride and 79.8 water (by weight). Hydrogen
    chloride boils at 84C and water at 100C, but
    the azeotrope boils at 110C

45
Distillation of negative azeotrope 20.2
hydrogen chloride and 79.8 water
  • distillation of any mixture of those constituents
    will result in the residue being closer in
    composition to the azeotrope than the original
    mixture.
  • E.g. hydrochloric acid solution contains less
    than 20.2 hydrogen chloride,
  • boiling the mixture will give a solution that is
    richer in hydrogen chloride than the original.
  • If the solution initially contains more than
    20.2 hydrogen chloride, boiling will give a
    solution that is poorer in hydrogen chloride than
    the original.
  • Boiling of any hydrochloric acid solution long
    enough will cause the solution left behind to
    approach the azeotropic ratio.

46
Application of Raoults Law in Aerosol Formulation
  • Vapour pressure of propellant control the spray
  • As pressure increases, spray rate increases -gt
    fine spray, propellant gas vapourises fast
  • As pressure decreases, spray rate decreases -gt
    coarse spray, propellant gas vapourises slowly -gt
    wet
  • Thus, improvise by using appropriate mixture of
    propellant
  • Examples of components
  • HFA-125 pentafluoroethane CHCF5
  • HFC-134a tetrafluoroethane CHCHF4
  • HFA-152 difluoroethane CH3CHF2
  • HFA-227 heptafluoropropane CHFCF3CF3

47
Exercise Application of Raoults Law in Aerosol
Formulation
  • The vapour pressure of pure propellant 11 (MW
    137.4) at 21oC is P110 13.4 psi
  • The vapour pressure of pure propellant 12 (MW
    120.9) at 21oC is P120 84.9 psi
  • A total of 100 g propellants consisting of 5050
    mixture by gram weight was used.
  • n11 50/137.4 0.364 mole
  • n12 50/120.9 0.414 mole
  • n11 n12 0.778 mole
  • P11 P110X11 P110(n11/(n11 n12) 13.4 x
    0.364/0.778 6.27 psi
  • P12 P120X12 P120(n12/(n11 n12) 84.9 x
    0.414/0.778 45.2 psi
  • P P11 P12 51.5 psi
  • Conversion psi to psig (Subtract atmospheric
    pressure of 14.7 psi)
  • Thus, P 51.5 14.7 36.8 psig

48
Variation of Vapour Pressure with Temperature
49
Clausius-Clapeyron Equation
  • The variation of vapour pressure with temperature
    in terms of molar enthalpy of the liquid, ?Hvap
  • ?V is the difference in molar volume of the two
    phases
  • Since molar volume of vapour is very much greater
    than the molar volume of liquid, ??V approaches
    volume of vapour, Vv
  • Assuming that the vapour obeys ideal gas
    behaviour,
  • PV RT
  • V RT/P
  • Thus, Vv RT/P
  • The equation becomes
  • Assuming ?Hvap to be constant

50
Application of Clausius-Clapeyron Equation
  • To estimate vapour pressure at any temperature.
  • To calculate enthalpy of vaporisation based on
    the slope of plot
  • To study phase transition important to
    determine the extent of weight loss during
    processing or testing.
  • End lecture 3/3

51
References
  • Please click below
  • Vapor Pressure of a Mixture - Raoult's Law
  • In addition to required/recommended texts
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