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Math 2 Geometry Based on Elementary Geometry, 3rd ed, by Alexander & Koeberlein 3.2 Corresponding Parts of Congruent Triangles CPCTC Corresponding parts of congruent ... – PowerPoint PPT presentation

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Title: Math 2 Geometry Based on Elementary Geometry, 3rd ed, by Alexander


1
Math 2 GeometryBased on Elementary Geometry,
3rd ed, by Alexander Koeberlein
  • 3.2
  • Corresponding Parts of Congruent Triangles

2
CPCTC
  • Corresponding parts of congruent triangles are
    congruent.
  • We first need to prove two triangles are ?
  • Could possibly use SSS, SAS, ASA, AAS

3
Example 1
  • Given
  • Ray WZ bisects ?TWV
  • Seg WT ? Seg WV
  • Prove
  • Seg TZ ? Seg VZ

4
Example 1a
  • Given
  • Ray WZ bisects ?TWV
  • Seg WT ? Seg WV
  • Prove
  • Seg WZ bisects Seg TV

5
Three types of ? conclusions
  • Proving triangles congruent
  • Proving the congruence of corresponding parts of
    triangles. First need to prove the triangles are
    congruent.
  • Establishing further relationships like in
    previous example. Need to first establish two
    triangles are congruent.

6
Example 2
  • Given
  • Seg ZW ? Seg YX
  • Seg ZY ? Seg WX
  • Prove
  • Seg ZY Seg WX

7
Right Triangles
Hypotenuse
Leg
Leg
8
HL (Hypotenuse-Leg)Theorem 3.2.1
  • Method for Proving Triangles Congruent
  • If the hypotenuse and a leg of one right triangle
    are congruent to the hypotenuse and leg of a
    second triangle, then the triangles are congruent.

9
Example
  1. SegAB ? SegEC and SegAC ? Seg ED
  2. ?A ? ?E and C is midpoint of SegBD
  3. SegBC ? SegCD and ?1 ? ?2
  4. SegAB ? SegEC and SegEC bisects SegBD

10
Example
  1. SegAB ? SegEC and SegAC ? Seg ED
  2. ?A ? ?E and C is midpoint of SegBD
  3. SegBC ? SegCD and ?1 ? ?2
  4. SegAB ? SegEC and SegEC bisects SegBD

11
ExampleCite reason why rt ?ABC ? rt ?ECD
  1. SegAB ? SegEC and SegAC ? Seg ED

12
Example
  1. SegAB ? SegEC and SegAC ? Seg ED
  2. ?A ? ?E and C is midpoint of SegBD

13
Example
  1. SegAB ? SegEC and SegAC ? Seg ED
  2. ?A ? ?E and C is midpoint of SegBD
  3. SegBC ? SegCD and ?1 ? ?2

14
Example
  1. SegAB ? SegEC and SegAC ? Seg ED
  2. ?A ? ?E and C is midpoint of SegBD
  3. SegBC ? SegCD and ?1 ? ?2
  4. SegAB ? SegEC and SegEC bisects SegBD

15
Pythagorean Theorem
  • The square of the length (c) of the hypotenuse
    of a right triangle equals the sum of the square
    of the lengths (a and b) of the legs of the
    triangle

16
Square Roots Property
  • Let x represent the length of a line segment,
    and let p represent a positive number. Then,
  • Note Different from Square Roots Property in
    Algebra

17
ExampleFind the length of the third side of the ?
  1. Find c if a 6 and b 8.

18
ExampleFind the length of the third side of the ?
  1. Find c if a 6 and b 8.
  2. Find b if a 7 and c 10
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