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EOC Practice

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16. 17. EOC Practice 18. 19. EOC Practice Continues You need to get the variables on one side of the equation. It does not matter which variable you move. – PowerPoint PPT presentation

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Title: EOC Practice


1
16.
17.
EOC Practice
2
18.
19.
EOC Practice Continues
3
Topic Equations with Variables on Both Sides Name
Topic Equations with Variables on Both Sides Date
Chapter , Section 2 4 Period
Essential Question How can the solution of an
equation with
variables on both sides be found?
  • You need to get the variables on one side of the
    equation. It does not matter which variable you
    move. Try to move the one that will keep your
    variable positive.

1) Solve 3x 2 4x - 1
Steps to solving 2-step equations 1. Draw the
river 2. Subtract 3x from both sides 3.
Simplify 4. Add 1 to both sides 5. Simplify
4
2) Solve 8y - 9 -3y 2
What is my goal?
Could I use any previously taught strategies to
solve this equation?
Can I combine like terms that are on opposite
sides? If so, is there an additional strategy I
must apply?
5
What is the value of x if 3 - 4x 18 x?
  1. -3
  2. 3

6
3) Solve 4 2x 13x - 3x
7
4) Solve -7(x - 3) -7
8
What is the value of x if 3(x 4) 2(x - 1)?
  1. -14
  2. -13
  3. 13
  4. 14

9
5) Two times a number plus three equals one
half of the number plus 12. What is the number?
10
Special Case 1
6) 2x 5 2x - 3
This is never true! No solutions
11
Special Case 2
7) 3(x 1) - 5 3x - 2
This is always true! Infinite solutions or
identity
HINT It looks exactly the same on both sides
12
What is the value of x if
-3 12x 12x - 3?
  1. 0
  2. 4
  3. No solutions
  4. Infinite solutions

13
Practice
To solve equations with variables on both sides
of the equal sign 1- Distribute. 2- Combine like
terms. 3- Move all the variables to the same
side. 4- Solve the two step equation. Subtract or
add Divide. Every step isnt needed in every
equation.
  • 3(d 8) 3d
  • 4(p 3) 36
  • 2(w 1) 4 4(w 1)
  • 6(2 2y) 5(2y 2)
  • 5(p 3) 9 3(9 2) 6

14
Word Problem Practice
Christine can buy a new snowboard for 136.50.
She will still need to rent boots for 8.50 a
day. She can rent a snowboard and boots for
18.25 a day. How many days would Christine need
to rent both the snowboard and the boots to pay
as much as she would if she buys the snowboard
and rents only the boots for the season?
15
Let d represent the number of days.
18.25d 136.5 8.5d
Subtract 8.5d from both sides.
8.5d 8.5d
Simplify.
9.75d 136.5
9.75
9.75
Divide both sides by 9.75.
d 14
Christine would need to rent both the snowboard
and the boots for 14 days to pay as much as she
would have if she had bought the snowboard and
rented only the boots.
16
More Word Problem Practice
A local telephone company charges 40 per month
for services plus a fee of 0.10 a minute for
long distance calls. Another company charges
75.00 a month for unlimited service. How many
minutes does it take for a person who subscribes
to the first plan to pay as much as a person who
subscribes to the unlimited plan?
17
Let m represent the number of minutes.
75 40 0.10m
Subtract 40 from both sides.
40 40
Simplify.
35 0.10m
Divide both sides by 0.10.
0.10
0.10
350 m
If you are going to use more than 350 minutes,
it will be cheaper to subscribe to the unlimited
plan.
18
Challenge! What is the value of x if -8(x 1)
3(x - 2) -3x 2?
  1. -8
  2. -2
  3. 2
  4. 8

19
Additional Practice
  • Page 105 - 108
  • (10, 12, 14, 18, 22, 23, 26, 43, 57)

20
Wrap-up
  • Summary
  • Remember to answer the Essential Question
  • Important Information Assessment 2
  • Periods 1, 3, 5 10/8/12
  • Periods 2, 4, 8 10/9/12
  • HLA7 Page 105 (1-5)
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