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Formal Semantics of Programming Languages

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Title: Formal Semantics of Programming Languages


1
Formal Semantics of Programming Languages
Topic 3 Principles of Induction
??? yhq_at_ecust.edu.cn
2
Induction
  • Proving of program properties often uses
    mathematical induction.
  • Prove properties of a programming language by
    proving a small finite set of claims.
  • If a property is violated then there is a small
    finite set in which it is violated.
  • Examples
  • lta, ?gt ? m lta, ?gt ? n ? m n
  • Euclid terminates
  • ltc, ?gt ? ? ltc, ?gt ? ? ?

3
Forms of induction
  • Mathematical induction
  • Structural induction
  • Well-founded induction
  • Induction on derivations
  • Rule induction

4
Mathematical induction
  • Principle Mathematical induction includes a
    basis and a induction step.
  • (P(0) (?m??. P(m) ? P(m1)))? ? n??. P(n)
  • Example Show that

5
Course-of-value induction
  • Principle
  • (?m??. (?kltm . P(k)) ? P(k))? ? n??. P(n)
  • Example Show that

6
Structural Induction
  • Principle The induction is based on the
    structure of the elements. First, show that the
    property holds for all atomic elements. Second,
    show that the formulation rules to build
    non-atomic elements preserve the property.
  • Example To show that a property P holds for all
    arithmetic expressions, it is sufficient to show
    that
  • (? m ??.P(m))?
  • (? X?Loc.P(X))?
  • (? a0 , a1 ?Aexp. P(a0) ? P(a1) ? P(a0 a1 ))?
  • (? a0 , a1 ?Aexp. P(a0) ? P(a1) ? P(a0 a1 ))?
  • (? a0 , a1 ?Aexp. P(a0) ? P(a1) ? P(a0 ? a1 ))

7
Structural Induction (Cont)
  • Example Show that the evaluation of arithmetic
    expression is deterministic, i.e.
  • lta, ?gt ? m lta, ?gt ? m ? m m
  • Bad example
  • ltc, ?gt ?? ltc, ?gt ? ?? ? ?

8
Well-Founded Induction
  • A well-founded relation lt on a set A if
  • there are no infinite decreasing chains
  • ?lt ai lt lt a2 lt a1
  • a lt b
  • a is a predecessor of b
  • Proposition A binary relation on A lt is
    well-founded iffany nonempty subset Q of
    A has a minimal element, i.e. an element m such
    that
  • m?Q ?b lt m. b ? Q .

9
The Principle of Well Founded Induction
  • lt is a well founded relation on A
  • P is property
  • Then
  • ?a ? A P(a)
  • Iff
  • ?a ? A (?b lt a. P(b) ? P(a))

10
The Principle of Well Founded Induction (Cont)
  • An alternative approach To show that a property
    P holds for all element of a well-founded set A,
    it is equivalent to show that the subset F of A
    for which P does not hold is empty.
  • To prove that F is empty, it is sufficient to
    show that F cannot have a minimal element.
  • And to show that F cannot have a minimal element,
    we construct a contradiction from the assumption
    that F has a minimal element.
  • Example Using the no counterexample approach,
    prove that

11
Applications of the well founded induction
principle
  • Mathematical induction
  • Course-of-values induction
  • Structural induction

12
Induction on Derivations
  • A set of rule instances R consists pairs X/y
    where X is a finite set and y is an element
  • X/y rule instance
  • X premises
  • y conclusion
  • d - R y d is an R-derivation of y
  • (?/y) - R y if (?/y) ? R
  • (d1, , dn/y) - R y if (x1, , xn/y) ? R
    andd1 - R x1 dn - R xn
  • - R y for some d d - R y
  • Sub-derivation d lt1 d if d?(D/y) with d ? D
  • lt lt1
  • lt is well-founded

13
Examples
1. For all states ? ?(M) ? 1 ?(N) ?1 ? ??
ltEuclid, ?gt? ?
2. For all states ?,?, ? ltc, ?gt ? ? ltc,
?gt ? ? ? ? ?
3. For all states ?,? ltwhile true do skip, ?gt ?
?
14
Rule induction
  • A special induction
  • Define a set by rules
  • IRx - R x
  • Examples
  • lta, ?, ngt of Aexp ? ? ? N such that lta, ?gt ? n
  • ltb, ?, tgt of Bexp ? ? ? T such that ltb, ?gt ? t
  • ltc, ?, ?gt of Com ? ? ? ? such that ltc, ?gt ? ?
  • Show that the property is true for all elements
    by induction on the rule application

15
The general principle of rule induction
  • Let IRx - R x
  • Let P be a property
  • ?x ? IR P(X) ? for all the rule instances (X/y)
    in R for which X ? IR ?z ?X. P(z) ? P(y)

16
Justifying the principle of induction
  • A set Q is closed under rule instances or simply
    R-closed if for all rule instances X/yX ?Q ? y ?
    Q
  • Proposition 4.1
  • IR is closed and
  • If Q is an R-closed set then IR ? Q
  • Application
  • Q x ? IR P(x)
  • Examples
  • R (?/0) ?n/n1) n ? ?
  • Referential transparency for expressions

17
Expressing Syntax using Rules
  • a a0 a1
  • a0 Aexp a1 Aexp a0a1 Aexp

18
Special Rule Induction
  • Handles rules of different types
  • BNF
  • c X a if b then c0 else c1
  • Rules
  • X Loc a Exp Xa Com
  • b Bexp c0 Com c1 Com if b then c0 else c1
    Com

19
The special principle of rule induction
  • Let IRx ?R x
  • A ? IR
  • Let Q be a property
  • ?a ? A. Q(a) ? for all the rule instances (X/y)
    in R for which X ? IR and y?A ?x ?X?A.Q(x)
    ? Q(y)

20
Proof rule for operational semanticsArithmetic
Expressions
  • P(a, ?, n) is true of all evaluations lta, ?gt? n
    if it is preserved by the expression rules

21
Proof rule for operational semantics AExp
  • P(a, ?, n) is true of all evaluations lta, ?gt? n
    if it is preserved by the expression rules

22
Rule Induction for Arithmetic Expressions
?a?Aexp, ???, n ?N. lta, ?gt? n ?P(a, ?, n)
iff
?n ?N, ???. P(n, ?, n) ?X?Loc, ???. P(X, ?,
?(X)) ?a0, a1? Aexp, ???, n0, n1 ?N.lta0, ?gt ?
n0 P(a0, ?, n0) lta1, ?gt ? n1 P(a1, ?, n1)
?P(a0a1, ?, n0n1)
23
Proof rule for operational semantics BExp
  • P(b, ?, t) is true of all evaluations ltb, ?gt? t
    if it is preserved by the Boolean expression
    rules
  • Define a subset of
  • (Aexp???N) ?(Bexp???T)
  • Obtained from the special principle of induction
    for properties P(b, ?, t) on the subset Bexp???T

24
Rule Induction for Booleans
?b?Bexp, ???, t ?T. ltb, ?gt? t ? P(b, ?, t)
iff
????. P(false, ?, false) ????. P(true, ?, true)
?a0, a1? Aexp, ???, n0, n1 ?N.lta0, ?gt ? m
lta1, ?gt ? n mn ?P(a0a1, ?, true) ?a0, a1?
Aexp, ???, n0, n1 ?N.lta0, ?gt ? m lta1, ?gt ? n
m?n ?P(a0a1, ?,false) ?b ?Bexp, ?? ?, t
?T. ltb, ?gt ?t P(b, ?, t) ?P(?b, ?, ? t)
25
Proof rule for operational semantics of Commands
  • P(c, ?,?) is true of all evaluations ltc,
    ?gt??if it is preserved by the command rules
  • Define a subset of
  • (Aexp???N) ?(Bexp???T) ?(Com????)
  • Obtained from the special principle of induction
    for properties P(c, ?, ?) on the subset Com????

26
Rule Induction for Commands
?c?Com, ???, ???. ltc, ?gt? ? ? P(c, ?, ?)
iff
????. P(skip, ?, ?) ?X ?Loc, a ?Bexp, ???.
lta0, ?gt ? m ?P(Xa, ?, ?m/X) ?c0, c1? Com,
?, ?, ? ??.ltc0, ?gt ? ? P(c0, ?, ?) ltc1,
?gt ? ? P(c1, ?, ?) ?P(c0c1, ?, ?)
27
Proposition 4.7
Define LocL(c) to be the variables which appear
on the left side of some assignment in c
Let y ? Loc For all commands c and states ?, ?
Y ? LocL(c). ltc, ?,gt ? ? ? ?(Y) ?(Y)
28
Operators and their least fixed points
  • For a set of rule instances R
  • R(B)y ?X ?B, X/y ? R
  • Proposition 4.11 A set B is closed under R if
    R(B) ?B
  • R is monotonic
  • A ? B ? R(A) ? R(B)
  • Define the sequence of sets
  • A0 R0(?) ?
  • A1 R1(?) R(?)
  • A2 R2(?) R(R(?))
  • An Rn(?)
  • Define A ?n ?? An

29
Proposition 4.12
  1. A is R-closed
  2. R(A) A
  3. A is the least R-closed set

Let fix(R) denote the least fixed point of R
fix(R) ?n?? Rn(?)
30
Summary
  • Induction allows to prove properties of the
    programming language
  • Example properties
  • Deterministic
  • Referential transparency
  • Equivalent of small step and natural semantics

31
Exercise 3
  • (1) Using mathematical induction to show there is
    no string u which satisfies au ub for two
    distinct symbol a and b.
  • (2) Prove by structural induction that the
    evaluation of arithmetic expressions always
    terminates, i.e., for all arithmetic expression a
    and states ?, there is some m such that lta, ?gt ?
    m.
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