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PPT – Rigid Body: Rotational and Translational Motion; Rolling without Slipping 8.01 W11D1 Today PowerPoint presentation | free to download - id: 725f4a-ZjZjZ

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Rigid Body Rotational and Translational

MotionRolling without Slipping8.01W11D1Toda

ys Reading Assignment Young and Freedman 10.3

Announcements

Math Review Night Tuesday from 9-11 pm Pset 10

Due Nov 15 at 9 pm Exam 3 Tuesday Nov 22

730-930 pm W011D2 Reading Assignment Young and

Freedman 10.5-10.6

Overview Rotation and Translation of Rigid Body

- Thrown Rigid Rod
- Translational Motion the gravitational

external force acts on center-of-mass - Rotational Motion object rotates about

center-of-mass. Note that the center-of-mass may

be accelerating

Overview Rotation about the Center-of-Mass of a

Rigid Body

- The total external torque produces an angular

acceleration about the center-of-mass - is the moment of inertial about the

center-of-mass - is the angular acceleration about the

center-of-mass - is the angular momentum about the

center-of-mass

Fixed Axis Rotation

- CD is rotating about axis passing through the

center of the disc and is perpendicular to the

plane of the disc. - For straight line motion, bicycle wheel rotates

about fixed direction and center of mass is

translating

Center of Mass Reference Frame

- Frame O At rest with respect to ground
- Frame Ocm Origin located at center of mass
- Position vectors in different frames
- Relative velocity between the two reference

frames - Law of addition of velocities

Demo Bicycle Wheel

Rolling Without Slipping

Rolling Bicycle Wheel

Reference frame fixed to ground

Center of mass reference frame

Motion of point P on rim of rolling bicycle

wheel Relative velocity of point P on rim

Rolling Bicycle Wheel

Distance traveled in center of mass reference

frame of point P on rim in time ?t

Distance traveled in ground fixed reference frame

of point P on rim in time ?t

Rolling Bicycle Wheel Constraint Relations

Rolling without slipping

Rolling and Skidding

Rolling and Slipping

Rolling Without Slipping

The velocity of the point on the rim that is in

contact with the ground is zero in the reference

frame fixed to the ground.

Concept Question Rolling Without Slipping

- When the wheel is rolling without slipping what

is the relation between the center-of-mass speed

and the angular speed? - .
- .
- .
- .

Concept Question Rolling Without Slipping

- Answer 3. When the wheel is rolling without

slipping, in a time interval ?t, a point on the

rim of the wheel travels a distance ?sR??. In

the same time interval, the center of mass of the

wheel is displaced the same distance ?xvcm?t .

Equating these two distances, R??cm?t. Dividing

through by ?t, and taking limit ?t approaching

zero, the rolling without slipping condition

becomes

Table Problem Bicycle Wheel

- A bicycle wheel of radius R is rolling

without slipping along a horizontal surface. The

center of mass of the bicycle in moving with a

constant speed V in the positive x-direction. A

bead is lodged on the rim of the wheel. Assume

that at t 0, the bead is located at the top of

the wheel at x x0. - What is the position and velocity of a bead

as a function of time according to an observer

fixed to the ground?

Angular Momentum for 2-Dim Rotation and

Translation

- The angular momentum for a translating and

rotating object is given by (see next two slides

for details of derivation) - Angular momentum arising from translational

of center-of-mass - The second term is the angular momentum arising

from rotation about center-of mass,

Derivation Angular Momentum for 2-Dim Rotation

and Translation

- The angular momentum for a rotating and

translating object is given by - The position and velocity with respect to the

center-of-mass reference frame of each mass

element is given by - So the angular momentum can be expressed as

Derivation Angular Momentum for 2-Dim Rotation

and Translation

- Because the position of the center-of-mass is

at the origin, and the total momentum in the

center-of-mass frame is zero, - Then then angular momentum about S becomes
- The momentum of system is
- So the angular momentum about S is

Table Problem Angular Momentum for Earth

- What is the ratio of the angular momentum about

the center of mass to the angular momentum of the

center of mass motion of the Earth?

Earths Motion Orbital Angular Momentum about Sun

- Orbital angular momentum about center of sun
- Center of mass velocity and angular velocity
- Period and angular velocity
- Magnitude

Earths MotionSpin Angular Momentum

- Spin angular momentum about center of mass of

earth - Period and angular velocity
- Magnitude

Earths Motion about Sun Orbital Angular Momentum

- For a body undergoing orbital motion like the

earth orbiting the sun, the two terms can be

thought of as an orbital angular momentum about

the center-of-mass of the earth-sun system,

denoted by S, - Spin angular momentum about center-of-mass of

earth - Total angular momentum about S

Rules to Live By Kinetic Energy of Rotation and

Translation

- Change in kinetic energy of rotation about

center-of-mass - Change in rotational and translational kinetic

energy

Work-Energy Theorem

Demo Rolling Cylinders B113

Different cylinders rolling down inclined plane

Concept Question Cylinder Race

Two cylinders of the same size and mass roll

down an incline, starting from rest. Cylinder A

has most of its mass concentrated at the rim,

while cylinder B has most of its mass

concentrated at the center. Which reaches the

bottom first? 1) A 2) B 3) Both at the same

time.

Concept Question Cylinder Race

Answer 2 Because the moment of inertia of

cylinder B is smaller, more of the mechanical

energy will go into the translational kinetic

energy hence B will have a greater center of mass

speed and hence reach the bottom first.

Concept Question Cylinder RaceDifferent Masses

Two cylinders of the same size but different

masses roll down an incline, starting from rest.

Cylinder A has a greater mass. Which reaches the

bottom first? 1) A 2) B 3) Both at the same

time.

Concept Question Cylinder RaceDifferent Masses

Answer 3. The initial mechanical energy is all

potential energy and hence proportional to mass.

When the cylinders reach the bottom of the

incline, both the mechanical energy consists of

translational and rotational kinetic energy and

both are proportional to mass. So as long as

mechanical energy is constant, the final velocity

is independent of mass. So both arrive at the

bottom at the same time.

Table Problem Cylinder on Inclined Plane Energy

Method

- A hollow cylinder of outer radius R and mass m

with moment of inertia I cm about the center of

mass starts from rest and moves down an incline

tilted at an angle q from the horizontal. The

center of mass of the cylinder has dropped a

vertical distance h when it reaches the bottom of

the incline. Let g denote the gravitational

constant. The coefficient of static friction

between the cylinder and the surface is ms. The

cylinder rolls without slipping down the incline.

Using energy techniques calculate the velocity of

the center of mass of the cylinder when it

reaches the bottom of the incline.

Concept Question Angular Collisions

- A long narrow uniform stick lies motionless on

ice (assume the ice provides a frictionless

surface). The center of mass of the stick is the

same as the geometric center (at the midpoint of

the stick). A puck (with putty on one side)

slides without spinning on the ice toward the

stick, hits one end of the stick, and attaches to

it. - Which quantities are constant?
- Angular momentum of puck about center of mass of

stick. - Momentum of stick and ball.
- Angular momentum of stick and ball about any

point. - Mechanical energy of stick and ball.
- None of the above 1-4.
- Three of the above 1.4
- Two of the above 1-4.

Concept Question Angular Collisions

Answer 7 (2) and (3) are correct. There are no

external forces acting on this system so the

momentum of the center of mass is constant (1).

There are no external torques acting on the

system so the angular momentum of the system

about any point is constant (3) . However there

is a collision force acting on the puck, so the

torque about the center of the mass of the stick

on the puck is non-zero, hence the angular

momentum of puck about center of mass of stick is

not constant. The mechanical energy is not

constant because the collision between the puck

and stick is inelastic.

Table Problem Angular Collision

A long narrow uniform stick of length l and

mass m lies motionless on a frictionless). The

moment of inertia of the stick about its center

of mass is lcm. A puck (with putty on one side)

has the same mass m as the stick. The puck slides

without spinning on the ice with a speed of v0

toward the stick, hits one end of the stick, and

attaches to it. (You may assume that the radius

of the puck is much less than the length of the

stick so that the moment of inertia of the puck

about its center of mass is negligible compared

to lcm.) What is the angular velocity of the

stick plus puck after the collision?

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