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Organic Chemistry

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Title: OC 2/e Ch 10 Alkynes Subject: Alkynes Author: Bill Brown Last modified by: Bill Brown Created Date: 7/18/1997 11:31:07 AM Document presentation format – PowerPoint PPT presentation

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Title: Organic Chemistry


1
Organic Chemistry
  • William H. Brown Christopher S. Foote

2
Alkynes
Chapter 10
  • Chapter 10

3
Nomenclature
  • IUPAC use the infix -yn- to show the presence of
    a carbon-carbon triple bond
  • Common names prefix the substituents on the
    triple bond to the name acetylene

4
Cycloalkynes
  • The smallest cycloalkyne isolated is cyclononyne
  • the C-C-C bond angle about the triple bond is
    approximately 156

5
Physical Properties
  • Similar to alkanes and alkenes of comparable
    molecular weight and carbon skeleton

6
Acidity
  • A major difference between the chemistry of
    alkynes and that of alkenes and alkanes is the
    acidity of the hydrogen bonded to a triply bonded
    carbon (Section 4.4E)
  • the pKa of acetylene is approximately 25, which
    makes it a stronger acid than ammonia but weaker
    than alcohols

7
Acidity
  • Acetylene reacts with sodium amide to form sodium
    acetylide
  • it can also be converted to its metal salt by
    reaction with sodium hydride or lithium
    diisopropylamide (LDA)

8
Acidity
  • Water is a stronger acid than acetylene
    hydroxide ion is not a strong enough base to
    convert acetylene to its anion

9
Alkylation of Acetylides
  • Acetylide anions are both strong bases and good
    nucleophiles
  • They undergo SN2 reactions with alkyl halides,
    tosylates, and mesylates to form new C-C bonds to
    alkyl groups that is, they undergo alkylation
  • because acetylide anions are also strong bases,
    alkylation is practical only with methyl and 1
    halides
  • with 2 and 3 halides, E2 is the major reaction.

10
Alkylation of Acetylides
  • Alkylation of acetylide anions is the most
    convenient method for the synthesis of terminal
    alkynes

11
Alkylation of Acetylides
  • Alkylation can be repeated and a terminal alkyne
    can be converted to an internal alkyne

12
Alkylation of Acetylides
  • With 2 and 3 alkyl halides, E2 is the major
    reaction

13
Preparation
  • Treatment of a vicinal dibromoalkane with two
    moles of base, most commonly sodium amide,
    results in two successive E2 reactions and
    formation of an alkyne

14
Preparation
  • Alkynes are also prepared by double
    dehydrohalogenation of geminal dihalides

15
Preparation
  • An alkene can be converted to an alkyne
  • for a terminal alkene to a terminal alkyne, 3
    moles of NaNH2 are required
  • for an internal alkene to an internal alkyne,
    only 2 moles of NaNH2 are required

16
Preparation
  • A side product may be an allene, a compound
    containing adjacent carbon-carbon double bonds,
    CCC

17
Allenes
  • Most allenes are less stable than their isomeric
    alkynes, and are generally only minor products in
    alkyne-forming dehydrohalogenation reactions

18
Reduction
  • Treatment of an alkyne with hydrogen in the
    presence of a transition metal catalyst, most
    commonly Pd, Pt, or Ni, converts the alkyne to an
    alkane

19
Reduction
  • With the Lindlar catalyst, reduction stops at
    addition of one mole of H2
  • this reduction shows syn stereoselectivity

20
Reduction
  • Reduction of an alkyne with Na or Li in liquid
    ammonia converts an alkyne to an alkene with anti
    stereoselectivity

21
Na/NH3(l) Reduction
  • Step 1 a one-electron reduction of the alkyne
    gives a radical anion
  • Step 2 an acid-base reaction gives an alkenyl
    radical and amide ion

22
Na/NH3(l) Reduction
  • Step 3 a second one-electron reduction gives an
    alkenyl anion.
  • this step establishes the configuration of the
    alkene
  • a trans alkenyl anion is more stable than its cis
    isomer
  • Step 4 a second acid-base reaction gives the
    trans alkene

23
Hydroboration
  • Addition of borane to an internal alkynes gives a
    trialkenylborane
  • Treatment of a trialkenylborane with acetic acid
    results in stereoselective replacement of B by H

24
Hydroboration
  • To prevent dihydroboration with terminal alkynes,
    it is necessary to use a sterically hindered
    dialkylborane, such as (sia)2BH

25
Hydroboration
  • Treatment of a terminal alkyne with (sia)2BH
    results stereospecific and regioselective
    hydroboration

26
Hydroboration
  • Treatment of an alkenylborane with H2O2 in
    aqueous NaOH gives an enol

27
Hydroboration
  • Enol a compound containing an OH group on one
    carbon of a CC
  • The enol is in equilibrium with a compound
    formed by migration of a hydrogen atom from
    oxygen to carbon and the double bond from CC to
    CO
  • The enol and keto forms are tautomers and their
    interconversion is called tautomerism
  • the keto form generally predominates at
    equilibrium
  • we discuss keto-enol tautomerism in detail in
    Section 16.11

28
Hydroboration
  • Hydroboration/oxidation of an internal alkyne
    gives a ketone

29
Hydroboration
  • Hydroboration/oxidation of a terminal alkyne
    gives an aldehyde

30
Addition of X2
  • Alkynes add one mole of bromine to give a
    dibromoalkene
  • addition shows anti stereoselectivity

31
Addition of X2
  • The intermediate in bromination of an alkyne is a
    bridged bromonium ion

32
Addition of HX
  • Alkynes undergo regioselective addition of first
    one mole of HX and then a second mole to give a
    dibromoalkane

33
Addition of HX
  • the intermediate in addition of HX is a 2
    vinylic carbocation
  • reaction of the vinylic cation with halide ion
    gives the product

34
Addition of H2Ohydration
  • In the presence of sulfuric acid and Hg(II)
    salts, alkynes undergo addition of water

35
Addition of H2Ohydration
  • Step 1 attack of Hg2 gives a bridged
    mercurinium ion intermediate, which contains a
    three-center, two-electron bond
  • Step 2 water attacks the bridged mercurinium ion
    intermediate from the side opposite the bridge

36
Addition of H2Ohydration
  • Step 3 proton transfer to solvent
  • Step 4 tautomerism of the enol gives the keto
    form

37
Addition of H2Ohydration
  • Step 5 proton transfer to the carbonyl oxygen
    gives an oxonium ion
  • Steps 6 and 7 loss of Hg2 gives an enol
    tautomerism of the enol gives the ketone

38
Organic Synthesis
  • A successful synthesis must
  • provide the desired product in maximum yield
  • have the maximum control of stereochemistry and
    regiochemistry
  • do minimum damage to the environment (it must be
    a green synthesis)
  • Our strategy will be to work backwards from the
    target molecule

39
Organic Synthesis
  • We analyze a target molecule in the following
    ways
  • the carbon skeleton how can we put it together.
    Our only method to date for forming new a C-C
    bond is the alkylation of acetylide anions
    (Section 10.5)
  • the functional groups what are they, how can
    they be used in forming the carbon-skeleton of
    the target molecule, and how can they be changed
    to give the functional groups of the target
    molecule

40
Organic Synthesis
  • We use a method called a retrosynthesis and use
    an open arrow to symbolize a step in a
    retrosynthesis
  • Retrosynthesis a process of reasoning backwards
    from a target molecule to a set of suitable
    starting materials

41
Organic Synthesis
  • Target molecule cis-3-hexene

42
Organic Synthesis
  • starting materials are acetylene and bromoethane

43
Organic Synthesis
  • Target molecule 2-heptanone

44
Organic Synthesis
  • starting materials are acetylene and
    1-bromopentane

45
Prob 10.9
  • Predict bond angles about each highlighted
    atom.

46
Prob 10.10
  • State the orbital hybridization of each
    highlighted atom.

47
Prob 10.11
  • Describe each highlighted carbon-carbon bond
    in terms of the overlap of atomic orbitals.

48
Prob 10.12
  • How many stereoisomers are possible for
    enanthotoxin?

49
Prob 10.13
  • Show how to prepare each alkyne from the
    given starting material.

50
Prob 10.15
  • Complete each acid-base reaction and predict
    whether the equilibrium lies toward the left or
    toward the right.

51
Prob 10.17
  • Draw a structural formula for the enol
    intermediate and the carbonyl compound formed in
    each reaction.

52
Prob 10.18
  • Propose a mechanism for this reaction.

53
Prob 10.21
  • Show how to convert propene to each compound.

54
Prob 10.22
  • Show how to bring about each conversion.

55
Prob 10.24
  • Propose mechanisms for Steps (1) and (2) and
    reagents for (3) and (4).

56
Prob 10.25
57
Prob 10.26
  • Show how to bring about each conversion.

58
Prob 10.31
  • Show how to bring about this conversion.

59
Alkynes
End Chapter 10
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