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Title: Application of Environment Spatial Information System CHAPTER 1 FLUID PROPERTIES


1
Application of Environment Spatial Information
SystemCHAPTER 1FLUID PROPERTIES
Minkasheva AlenaThermal Fluid Engineering
Lab.Department of Mechanical EngineeringKangwon
National University
2
  • The engineering science of fluid mechanics has
    been developed through an understanding of fluid
    properties, the application of the basic laws of
    mechanics and thermodynamics, and orderly
    experimentation.
  • The properties of density and viscosity play
    principal roles in open- and closed-channel flow
    and in flow around immersed objects (stream,
    river, sewer line, pipe line, groundwater, sea
    water, overland flow).
  • Surface-tension effects are important in the
    formation of droplets, in the flow of small jets,
    and in situations where liquid-gas-solid or
    liquid-liquid-solid interfaces occur, as well as
    in the formation of capillary waves (phase,
    water, air, solid phase).
  • The property of vapor pressure, which accounts
    for changes of phase from liquid to gas, becomes
    important when reduced pressures are encountered.
  • We will use International System of Units (SI) of
    force, mass, length, and time units.

3
1.1 DEFINITION OF A FLUID
  • A fluid is a substance that deforms continuously
    when subjected to a shear stress, no matter how
    small that shear stress may be.
  • Shear stress Tangential (Shear )Force / Area
  • Normal Stress (pressure) Normal Force /Area
  • Shear force is the force component tangent to a
    surface, and this force divided by the area of
    the surface is the average shear stress over the
    area. Shear stress at a point is the limiting
    value of shear force to area as the area is
    reduced to the point.

4
In figure a substance is placed between two
closely spaced parallel plates so large that
conditions at their edges may be neglected. The
lower plate is fixed, and a force F is applied to
the upper plate, which exerts a shear stress F/A
on any substance between the plates. A is the
area of the upper plate. When the force F causes
the upper plate to move with a steady (nonzero)
velocity, no matter how small the magnitude of F,
one may conclude that the substance between the
two plates is a fluid.
Figure 1.1 Deformation resulting from application
of constant shear force
5
  • The fluid in immediate contact with a solid
    boundary has the same velocity as the boundary
    (no slip at the boundary).
  • In the figure 1.1 the fluid in the area abcd
    flows to the new position ab'c'd, each fluid
    particle moving parallel to the plate and the
    velocity u varying uniformly from zero at the
    stationary plate to U at the upper plate.
  • Experiments show that, other quantities being
    held constant, F is directly proportional to A
    and to U and is inversely proportional to
    thickness t. In equation form
  • Where µ is the proportionality factor and
    includes the effect of the particular fluid.

6
  • If t F/A for the shear stress,
  • The ratio U/t is angular velocity of line ab, or
    it is the rate of angular deformation of the
    fluid (rate of decrease of angle bad).
  • The angular velocity may also be written du/dy
    is more general.
  • The velocity gradient du/dy may also be
    visualized as the rate at which one layer moves
    relative to an adjacent layer, in differential
    form,

  • - Newton's law of viscosity
    (1.1.1)
  • is the relation between shear stress and rate of
    angular deformation for one-dimensional flow of a
    fluid.
  • The proportionality factor µ is called viscosity
    of the fluid.

7
  • Materials other than fluids cannot satisfy the
    definition of a fluid.
  • A plastic substance will deform a certain amount
    proportional to the force, but not continuously
    when the stress applied is below its yield shear
    stress.
  • A complete vacuum between the plates would cause
    deformation at an ever-increasing rate.
  • If sand were placed between the two plates,
    Coulomb friction would require a finite force to
    cause a continuous motion. Hence, plastics and
    solids are excluded from the classification of
    fluids.

8
  • Fluids may be classified as
  • Newtonian
  • non-Newtonian.
  • In Newtonian fluid there is a linear relation
    between the magnitude of applied shear stress and
    the resulting rate of deformation µ constant in
    Eq. (1.1.1), as shown in Fig. 1.2.
  • In non-Newtonian fluid there is nonlinear
    relation between the magnitude of applied shear
    stress and the rate of angular deformation.
  • An ideal plastic has a definite yield stress and
    a constant linear relation of t to du/dy.
  • A thixotropic substance, such as printer's ink,
    has a viscosity that is dependent upon the
    immediately prior angular deformation of the
    substance and has a tendency to take a set when
    at rest.
  • Gases and thin liquids tend to be Newtonian
    fluids, while thick, long-chained hydrocarbons
    may be non-Newtonian.

9
Figure 1.2 Rheological diagram
10
  • For purposes of analysis, the assumption is
    frequently made that a fluid is nonviscous.
  • With zero viscosity the shear stress is always
    zero, regardless of the motion of the fluid.
  • If the fluid is also considered to be
    incompressible, it is then called an ideal fluid
    and plots as the ordinate in Fig. 1.2.

11
1.2 FORCE, MASS, LENGTH, AND TIME UNITS
  • Consistent units of force, mass, length, and
    time
  • greatly simplify problem solutions in mechanics
  • derivations may be carried out without reference
    to any particular consistent system.
  • A system of mechanics units is said to be
    consistent when unit force causes unit mass to
    undergo unit acceleration.
  • The International System (SI)
  • newton (N) as unit of force
  • kilogram (kg) as unit of mass
  • metre (m) as unit of length
  • the second (s) as unit of time.

12
  • With the kilogram, metre, and second as defined
    units, the newton is derived to exactly satisfy
    Newton's second law of motion
  • (1.2.1)
  • The force exerted on a body by gravitation is
    called the force of gravity or the gravity force.
    The mass m of a body does not change with
    location the force of gravity of a body is
    determined by the product of the mass and
    the local acceleration of gravity g
  • (1.2.2)
  • For example, where g 9.876 m/s2, a body with
    gravity force of 10 N has a mass m 10/9.806 kg.
    At the location where g 9.7 m/s2, the force of
    gravity is
  • Standard gravity is 9.806 m/s2. Fluid properties
    are often quoted at standard conditions of 4oC
    and 760 mm Hg.

13
Table 1.1 Selected prefixes for powers of 10 in
SI units
14
1.3 VISCOSITY
  • Viscosity requires the greatest consideration in
    the study of fluid flow.
  • Viscosity is that property of a fluid by virtue
    of which it offers resistance to shear.
  • Newton's law of viscosity Eq. (1.1.1) states
    that for a given rate of angular deformation of
    fluid the shear stress is directly proportional
    to the viscosity.
  • Molasses and tar are examples of highly viscous
    liquids water and air have very small
    viscosities.

15
  • The viscosity of a gas increases with
    temperature, but the viscosity of a liquid
    decreases with temperature it can be explained
    by examining the causes of viscosity.
  • The resistance of a fluid to shear depends upon
    its cohesion and upon its rate of transfer of
    molecular momentum.
  • A liquid, with molecules much more closely spaced
    than a gas, has cohesive forces much larger than
    a gas. Cohesion appears to be the predominant
    cause of viscosity in a liquid and since
    cohesion decreases with temperature, the
    viscosity does likewise.
  • A gas, on the other hand, has very small cohesive
    forces. Most of its resistance to shear stress is
    the result of the transfer of molecular momentum.

16
  • As a rough model of the way in which momentum
    transfer gives rise to an apparent shear stress,
    considering two idealized railroad cars loaded
    with sponges and on parallel tracks (see Fig.
    1.3).
  • Assume each car has a water tank and pump so
    arranged that the water is directed by nozzles at
    right angles to the track. First, consider A
    stationary and B moving to the right, with the
    water from its nozzles striking A and being
    absorbed by the sponges.
  • Car A will be set in motion owing to the
    component of the momentum of the jets which is
    parallel to the tracks, giving rise to an
    apparent shear stress between A and B. Now if A
    is pumping water back into B at the same rate,
    its action tends to slow down B and equal and
    opposite apparent shear forces result.
  • When both A and B are stationary or have the same
    velocity, the pumping does not exert an apparent
    shear stress on either car.

17
Figure 1.3 Model illustrating transfer of
momentum
  • Within fluid there is always a transfer of
    molecules back and forth across any fictitious
    surface drawn in it. When one layer moves
    relative to an adjacent layer, the molecular
    transfer of momentum brings momentum from one
    side to the other so that an apparent shear
    stress is set up that resists the relative motion
    and tends to equalize the velocities of adjacent
    layers in a manner analogous to that of Fig. 1.3.
  • The measure of the motion of one layer relative
    to an adjacent layer is du/dy.

18
  • Molecular activity gives rise to an apparent
    shear stress in gases which is more important
    than the cohesive forces, and since molecular
    activity increases with temperature, the
    viscosity of a gas also increases with
    temperature.
  • For ordinary pressures viscosity is independent
    of pressure and depends upon temperature only.
    For very great pressures, gases and most liquids
    have shown erratic variations of viscosity with
    pressure.
  • A fluid at rest or in motion so that no layer
    moves relative to an adjacent layer will not have
    apparent shear forces set up, regardless of the
    viscosity, because du/dy is zero throughout the
    fluid.
  • Hence, in the study of fluid statistics, no shear
    forces considered, and the only stresses
    remaining are normal stresses, or pressures ?
    greatly simplifies the study of fluid statics,
    since any free body of fluid can have only
    gravity forces and normal surface forces acting
    on it.

19
  • The dimensions of viscosity are determined from
    Newton's law of viscosity Eq. (1.1.1). Solving
    for the viscosity µ
  • and inserting dimensions F, L, T for force,
    length, and time,
  • shows that µ has the dimensions FL-2T.
  • With the force dimension expressed in terms of
    mass by use of Newton's second law of motion, F
    MLT-2, the  dimensions of viscosity may be
    expressed as ML-1T-1.
  • The SI unit of viscosity which is the pascal
    second (symbol Pa s) or kilograms per
    meter-second (kg/m s), has no name.

20
Kinematic Viscosity
  • µ - absolute viscosity or the dynamic viscosity
  • ? - kinematic viscosity (the ratio of viscosity
    to mass density)
  • (1.3.1)
  • ? occurs in many applications (e.g., in the
    dimensionless Reynolds number for motion of a
    body through a fluid, Vl/?, in which V is the 
    body velocity and l is a representative linear
    measure or the body size).
  • The  dimensions of ? are L2T-1. The SI unit of
    kinematic viscosity is 1 m2/s, and has no name.
  • Viscosity is practically independent of pressure
    and depends upon temperature only. The kinematic
    viscosity of liquids, and of gases at a given
    pressure, is substantially a function of
    temperature.

21
  • Example 1.1
  • A liquid has a viscosity or 0.005 Pa s and a
    density of 850 kg/m3. Calculate the kinematic
    viscosity

22
  • Example 1.2
  • In Fig. 1.4 the rod slides inside a concentric
    sleeve with a reciprocating motion due to the
    uniform motion of the crank. The clearance is d
    and the viscosity µ. Write a program in BASIC to
    determine the average energy loss per unit time
    in the sleeve. D 0.8 in, L 8.0 in, d 0.001
    in, R 2 ft, r 0.5 ft, µ 0.0001 lb s/ft2,
    and the rotation speed is 1200 rpm.
  • Solution The energy loss in the sleeve in one
    rotation is the product of resisting viscous
    (shear) force times displacement integrated over
    the period of the motion. The period T is 2p/?,
    where ? d?/dt. The sleeve force depends upon
    the velocity. The force Fi and position xi are
    found for 2n equal increments of the period. Then
    by the trapezoidal rule the work done over the
    half period is found
  • Using the law of sines to eliminate f, we get
  • Figure 1.5 lists the program, in which the
    variable RR represents the crank radius r.

23
Figure 1.4 Notation for sleeve motion
24
Figure 1.5 BASIC program to determine loss in
sleeve motion
25
1.4 CONTINUUM
  • In dealing with fluid-flow relations on a
    mathematical or analytical basis consider that
    the actual molecular structure is replaced by a
    hypothetical continuous medium - continuum.
  • For example, velocity at a point in space is
    indefinite in a molecular medium, as it would be
    zero at all times except when a molecule occupied
    this exact point, and then it would be the
    velocity of the molecule and not the mean mass
    velocity of the particles in the neighborhood.
  • This is avoided if consider velocity at a point
    to be the average or mass velocity of all
    molecules surrounding the point. With n molecules
    per cubic centimetre, the mean distance between
    molecules is of the order n-1/3 cm.

26
  • Molecular theory, however, must be used to
    calculate fluid properties (e.g., viscosity)
    which are associated with molecular motions, but
    continuum equations can be employed with the
    results of molecular calculations.
  • In rarefied gases (the atmosphere at 80 km above
    sea level) the ratio of the mean free path the
    mean free path is the average distance a molecule
    travels between collisions of the gas to a
    characteristic length for a body or conduit is
    used to distinguish the type of flow.
  • The flow regime is called gas dynamics for very
    small values of the ratio the next regime is
    called slip flow and for large values of the
    ratio it is free molecular flow.
  • In this text only the gas-dynamics regime is
    studied.

27
1.5 DENSITY, SPECIFIC VOLUME, UNIT GRAVITY FORCE,
RELATIVE DENSITY, PRESSURE
  • The density ? of a fluid is defined as its mass
    per unit volume. To define density at a point,
    the mass ?m of fluid in a small volume ?V
    surrounding the point is divided by ?V and the
    limit is taken as ?V becomes a value e3 in which
    e is still large compared with the mean distance
    between molecules,
  • (1.5.1)
  • For water at standard pressure (760 mm Hg) and
    4oC, ? 1000 kg/m3.
  • (1.5.2)
  • The specific volume vs is the reciprocal of the
    density ? that is, it is the volume occupied by
    unit mass of fluid.

28
  • The unit gravity force, ? - the force of gravity
    per unit volume. It changes with location
    depending upon gravity.
  • (1.5.3)
  • Water ? 9806 N/m3 at 5oC, at sea level.
  • The relative density S of a substance - the ratio
    of its mass to the mass of an equal volume of
    water at standard conditions.
  • The average pressure - the normal force pushing
    against a plane area divided by the area.
  • The pressure at a point is the ratio of normal
    force to area as the area approaches a small
    value enclosing the point.
  • If a fluid exerts a pressure against the walls or
    a container, the container will exert a reaction
    on the fluid which will be compressive.
  • Pressure has the units force per area, which is
    newtons per square metre, called pascals (Pa).

29
1.6 PERFECT GAS
  • In this treatment, thermodynamic relations and
    compressible-fluid-flow cases have been limited
    generally to perfect gases.
  • The perfect gas is defined as substance that
    satisfies the perfect-gas-law
  • (1.6.1)
  • and that has constant specific heats.
  • p is the absolute pressure vs is the specific
    volume R is the gas constant and T is the
    absolute temperature.

30
  • The perfect gas must be carefully distinguished
    from the ideal fluid. An ideal fluid frictionless
    and incompressible. The perfect gas has viscosity
    and can therefore develop shear stresses, and it
    is compressible according to Eq. (1.6.1).
  • Eq. (1.6.1) is the equation of state for a
    perfect gas may be written
  • (1.6.2)
  • The units of R can be determined from the
    equation when the other units are known.

31
  • Real gases below critical pressure and above the
    critical temperature tend to obey the perfect-gas
    law. As the pressure increases, the discrepancy
    increases and becomes serious near the critical
    point.
  • The perfect-gas law encompasses both Charles' law
    and Boyle's law.
  • Charles' law states that for constant pressure
    the volume of a given mass of gas varies as its
    absolute temperature.
  • Boyle's law (isothermal law) states for constant
    temperature the density varies directly as the
    absolute pressure.

32
  • The volume V of m mass units of gas is mvs ?
  • (1.6.3)
  • With being the volume per mole, the
    perfect-gas law becomes
  • (1.6.4)
  • If n is the number of moles of the gas in volume
    V,
  • (1.6.5)
  • The product MR, called the universal gas
    constant, has a value depending only upon the
    units employed. It is
  • (1.6.6)
  • The gas constant R can then be determined from
  • (1.6.7)
  • ? knowledge of relative molecular mass leads to
    the value of R.

33
  • The specific heat cv of a gas is the number of
    units of heat added per unit mass to raise the
    temperature of the gas one degree when the volume
    is held constant.
  • The specific heat cp is the number of heat units
    added per unit mass to raise the temperature one
    degree when the pressure is held constant.
  • The specific heat ratio k cp/cv.
  • The intrinsic energy u (dependent upon P, ? and
    T) is the energy per unit mass due to molecular
    spacing and forces.
  • The enthalpy h is important property of a gas
    given by h u P/?.
  • cv and cp have the units joule per kilogram per
    kelvin (J/kg?K). 4187 J of heat added raises the
    temperature of one kilogram of water one degree
    Celsius at standard conditions.
  • R is related to cv and cp by

34
  • Example 1.3
  • A gas with relative molecular mass of 44 is at a
    pressure of 0.9 MPa and a temperature of 20oC.
    Determine its density.
  • Solution
  • From Eq. (1.6.7),
  • Then, from Eq. (1.6.2),

35
1.7 BULK MODULUS OF ELASTICITY
  • For most purposes a liquid may be considered as
    incompressible, but for situations involving
    either sudden or great changes in pressure, its
    compressibility becomes important. Liquid (and
    gas) compressibility also becomes important when
    temperature changes are involved, e.g., free
    convection.
  • The compressibility of a liquid is expressed by
    its bulk modulus of elasticity.
  • If the pressure of a unit volume of liquid is
    increased by dp, it will cause a volume decrease
    -dV the ratio -dp/dV is the bulk modulus of
    elasticity K.
  • For any volume V of liquid,
  • K expressed in units of p. For water at 20oC K
    2.2 GPa.

36
  • Example 1.4
  • A liquid compressed in a cylinder has a volume
    of 1 liter (L 1000 cm3) at 1 MN/m2 and volume
    of 995 cm3 at 2 MN/m2. What is its bulk modulus
    of elasticity?

37
1.8 VAPOR PRESSURE
  • Liquids evaporate because or molecules escaping
    from the liquid surface. The vapor molecules
    exert partial pressure in the space, known as
    vapor pressure.
  • If the space above the liquid is confined, after
    a sufficient time the number of vapor molecules
    striking the liquid surface and condensing is
    just equal to the number escaping in any interval
    of time, and equilibrium exists.
  • The vapor pressure of a given fluid depends upon
    temperature and increases with it. When the
    pressure above a liquid equals the vapor pressure
    of the liquid, boiling occurs.
  • At 20oC water vapor pressure - 2.447 kPa
    mercury vapor pressure - 0.173 Pa
  • When very low pressures are produced at certain
    locations in the system, pressures may be equal
    to or less than the vapor pressure ? the liquid
    flashes into vapor. This is the phenomenon of
    cavitation.

38
1.9 SURFACE TENSION
  • Capillarity
  • At the interface between a liquid and a gas, or
    two immiscible liquids, a film or special layer
    seems to form on the liquid, apparently owing to
    attraction of liquid molecules below the surface.
  • The formation or this film may be visualized on
    the basis of surface energy or work per unit area
    required to bring the molecules to the surface.
    The surface tension is then the stretching force
    required to form the film, obtained by dividing
    the surface-energy term by unit length of the
    film in equilibrium.
  • The surface tension of water varies from about
    0.074 N/m at 20oC to 0.059 N/m at 100oC (Table
    1.2)

39
Table 1.2 Approximate properties of common
liquids at 20oC and standard atmospheric pressure
40
  • The action of surface tension is to increase the
    pressure within a droplet of liquid or within a
    small liquid jet.
  • For a small spherical droplet of radius r the
    internal pressure p necessary to balance the
    tensile force due to the surface tension s
    calculated in terms of the forces which act on a
    hemispherical free body,
  • For the cylindrical liquid jet of radius r, the
    pipe-tension equation applies
  • Both equations show that the pressure becomes
    large for a very small radius of droplet or
    cylinder.

41
  • Capillary attraction is caused by surface tension
    and by the relative value of adhesion between
    liquid and solid to cohesion of the liquid.
  • A liquid that wets the solid has a greater
    adhesion than cohesion. The action of surface
    tension in this case is to causes the liquid to
    rise within a small vertical tube that is
    partially immersed in it.
  • For liquids that do not wet the solid, surface
    tension tends to depress the meniscus in a small
    vertical tube. When the contact angle between
    liquid and solid is known, the capillary rise can
    be computed for an assumed shape of the meniscus.
  • Figure 1.4 shows the capillary rise for water and
    mercury in circular glass tubes in air.

42
Figure 1.5 Capillarity in circular glass tubes
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