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Title: Course Title: Strength of Materials (CVE 202)


1
Course Title Strength of Materials
(CVE 202)
  • Course Lecturer Engr. F. M. Alayaki
  • Civil Engineering Department, College of
    Engineering,University of Agriculture
    Abeokuta,Nigeria
  • Course Unit 2Contact Time 2 HoursLaboratory
    Time 1 Hour

2
Course Content
  • Direct Stress Hookes experiment. Axially
    loaded bar, Tensile and compressive stresses.
    Strain tensile and compressive strains.
    Stress-stain curves for ductile and brittle
    materials. Modulus of elasticity. Mechanical
    properties of materials elastic limits,
    proportional limit, yield points, ultimate
    strength. Modulus of toughness. Percentage
    reduction in areas. Percentage elongation.

3
  • Principal stress Definition, deductions from
    Mohrs circle. Mohrs circle method of
    determining stress and strain. Working stress,
    proof stress, Poissons ratio, modulus of
    rigidity. Factors of safety. Lateral stresses
    and strains. Bars of varying cross sections
    compound bars under stress and strain.
    Temperature stresses.

4
  • Torsion effects of torsion. Twisting moment.
    Polar second moments of area. Torsional shearing
    stresses and strain. Modulus of elasticity in
    shear. Angle of twist. Rupture.
  • Shearing force and bending moments Simply
    supported beam. Loading forces and moments in
    beams. Shear and moment equations. Shear force
    and bending moment diagrams.

5
Typical Questions
  • 1. The following data were recorded during a
    tensile steel test
  • Diameter of bar 20mm
  • Distance between gauge points 200mm
  • Elongation due to load of 50KN 0.18
  • Load at yield point 79KN
  • Failing or ultimate load 127KN
  • Calculate in N/mm2
  • the stress at yield point, (b) the ultimate
    stress, (c) the modulus of elasticity of the
    steel
  • 2. ( a ) Define the following terms
  • Component of Forces
  • Resultant
  • Equilibrant
  • Moment of Forces
  • Centroid of a Body
  • ( b ) i Define the terms shear force and
    bending moment.
  • ii What do you understand by the term point of
    contraflexure?
  •  
  •  

6
  • ( c ) Using simple sketches show the
    following types of beams
  • Simply supported beam with a point load.
  • Simply supported beam with Uniformly Distributed
    Load (UDL).
  •  
  • 3. Three separate members of steel, copper and
    brass are of identical dimensions and are equally
    loaded. Youngs moduli for the materials are
    steel, 210,000N/mm2 copper, 100,000N/mm2 brass,
    95,000N/mm2. If the steel member stretches
    0.13mm, calculate the amount of elongation in the
    copper and brass members.
  • 4. (a) Define the terms shear force and bending
    moment.
  • (b) What do you understand by the term point of
    contraflexure?
  • (c) Using simple sketches show the following
    types of beams
  • Simply supported beam with a point load.
  • Simply supported beam with Uniformly
    Distributed Load (UDL).
  • Overhanging beam with UDL.
  • Cantilever beam with point load at its end.
  • Simply supported beam with uniformly varying
    load.
  •  

7
  • 5. A cantilever beam AB 1.5m long is loaded with
    a UDL of 2 KN/m and a point load of 3KN as shown
    in fig. 1. Draw the shear force and bending
    moment diagram for the cantilever beam. Indicate
    the positions and values of the following.
  • Point of zero shear force.
  • Maximum shear force.
  • Maximum bending moment.
  •  
  • 6 (a) Derive from first principle the formula for
    the moment of inertia of a rectangular section.
  • (b) Determine the moment of inertia Ixx of the
    section shown in fig. 2.
  •  
  • 7. Define stress, strain, and elasticity. Derive
    a relation between stress and strain of an
    elastic body.
  •  
  • 8. Two wires, one of steel and the other of
    copper, are of the same length and are subjected
    to the same tension. If the diameter of the
    copper wire is 2mm, find the diameter of the
    steel wire, if they are elongated by the same
    amount. Take E for steel as 200 x 103 N/mm2 and
    that for copper as 100 x 103 N/mm2.

8

  • 3
    KN 2KN/m A B
    0.25m 1.00m 0.25m
    Fig. 1
    24mm
    24mm 300mm
    Fig. 2 200mm


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