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Petroleum Engineering 406

- Lesson 20
- Directional Drilling
- (continued)

Lesson 17 - Directional Drilling contd

- Tool-Face Angle
- Ouija Board
- Dogleg Severity
- Reverse Torque of Mud Motor
- Examples

Homework

- READ
- Applied Drilling Engineering, Chapter 8
- (to page 375)

Tool Face (g)

Solution

Fig. 8. 30 Graphical Ouija Analysis.

Over one drilled interval (bit run)

GIVEN a 16o De 12o aN 12o

Tool Face (g)

Solution

New Inclination - 12o

De 12o

g ? o b ? o

Initial Inclination 16o

Fig. 8. 30 Graphical Ouija Analysis.

Fig. 8.33 Basis of chart construction is a

trigonometric relationship illustrated by two

intersecting planes

b

a

aN

b dogleg angle

De

Problem 1

- Determine the new direction (eN) for a

whipstock set at 705 m with a tool-face setting

of 450 degrees right of high side for a course

length of 10 m. - The inclination is 70 and the direction is N15W.

The curve of the whipstock will cause a total

angle change of 30/30 m.

Problem 1

- a 7o (inclination)
- e 345o (azimuth)
- g 45o (tool face angle)
- L 10 m (course length)
- d 3o/ 30 m (dogleg severity)
- eN ? o

g 45o

Solution to Problem 1, part 1

- I. Use Equation 8.43 to calculate .
- The dogleg severity,

Solution to Problem 1, part 2

- 2. Use Equation 8.42 to calculate the direction

change. - New direction 3450 5.30 350.30 N9.7W

Problem 2

- Determine where to set the tool face angle,

for a jetting bit to go from a direction of 100

to 300 and from an inclination of 30 to 50. Also

calculate the dogleg severity, assuming that the

trajectory change takes 60 ft. - a 3
- e 10
- Find

Solution to Problem 2, part 1

- 1. Find b using Equation 8.53

Solution to Problem 2, part 2

- 2. Now calculate ? from equation 8.48.

Solution to Problem 2, part 3

- 3. The dogleg severity,
- ? 4.01o / 100 ft
- Alternate solution Use Ouija Board

Fig. 8.31 Solution to Example 8.6.

Problem 3

- Determine the dogleg severity following a jetting

run where the inclination was changed from 4.3o

to 7.1o and the direction from N89E to S80E over

a drilled interval of 85 feet. - 1. Solve by calculation.
- 2. Solve using Ragland diagram
- L 85 ft

Da 7.1 - 4.3 2.8. De 100 - 89 11

Solution to Problem 3, part 1

- 1. From Equation 8.55

b 3.01o

Solution to Problem 3, part 1

- 1. From Equation 8.43
- the dogleg severity,

Solution to Problem 3, part 2

- 2. Construct line of length ? (4.3o)
- Measure angle ?? (11o )
- Construct line of length ?N (7.1o)
- Measure length ?
- (Measure angle ?)

4.3

11o

b

7.1

Ragland Diagram

Some Equations to Calculate b

Eq. 8.53

Eq. 8.54

Eq. 8.55

Overall Angle Change and Dogleg Severity

- Equation 8.51 derived by Lubinski is used to

construct Figure 8.32, - a nomograph for determining
- the total angle change ? and
- the dogleg severity, ?.

Fig. 8.32 Chart for determining dogleg severity

(aaN)/2 5.7o

aN - a 2.8o

b 3o

De 11o

d 3.5o/100 ft

(aaN)/2 5.7o

De 11o

aN - a 2.8o

b 3o

b 3o

d 3.5o/100 ft

(aaN)/2 5.7o

aN - a 2.8o

b 3o

De 11o

d 3.5o/100 ft

Problem 4 - Torque and Twist

- 1. Calculate the total angle change of 3,650 ft.

of 4 1/2 inches (3.826 ID) Grade E 16.60 /ft

drill pipe and 300 ft. of 7 drill collars (2

13/16 ID) for a bit-generated torque of 1,000

ft-lbf. Assume that the motor has the same

properties as the 7 drill collars. Shear modules

of steel, G 11.5106 psi. - 2. What would be the total angle change if

7,300 ft. of drill pipe were used?

Solution to Problem 4

- From Equation 8.56,

Solution to Problem 4, cont.

radians

Solution to Problem 4, cont.

- If Length of drillpipe 7,300 ft.,
- ?M 0.001043 ?15.6822278.88
- 4.77 radians

3/4 revolution!

137.2

Example 8.10

- Design a kickoff for the wellbore in Fig. 8.35.

e S48W 228o eN N53W 307o

a 2o L 150 ft aN 6o

De 79o Find b, g and d

From Ouija Board, b 5.8o, g 97o

New Direction

Where to Set the Tool Face

b 5.8o g 97o

High Side

High Side

Present Direction

Fig. 8.36 Solution for Example 8.10.

Dogleg Severity

- From Equation 8.43
- the dogleg severity,

With jetting bit 325o

345o

qM 20o

307o

Fig. 8.36 Solution for Example 8.10.

228o

Tool Face Setting

Where to Set the Tool Face

Compensating for Reverse Torque of the Motor

New Direction

Present Direction

High Side

High Side

Fig. 8.36 Solution for Example 8.10.