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Interference and Diffraction

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Identify the conditions required for interference to occur. ... Describe how light waves diffract around obstacles and produce bright and dark fringes. ... – PowerPoint PPT presentation

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Title: Interference and Diffraction


1
Chapter 16
  • Interference and Diffraction

2
Chapter 16 section 1
  • Objectives
  • Describe how light waves interfere with each
    other to produce bright and dark fringes.
  • Identify the conditions required for interference
    to occur.
  • Predict the location of interference fringes
    using the equation for double-slit interference.

3
Interference
  • waves can superpose one another, bend around
    corners, reflect off surfaces, be absorbed, and
    change direction when entering new material
  • All of these characteristics vary with the
    wavelength of light
  • interference takes place only btwn waves w/the
    same wavelength
  • End up w/a resultant wave

4
Interference
  • light waves w/the same wavelength are
    monochromatic
  • Single colored
  • Constructive interference equals an increase in
    brightness
  • Destructive interference equals dimmer spots
  • for interference to be seen, there must be a
    constant phase difference and light must be
    monochromatic

5
In phase
  • Crest of one wave overlaps the crest of another
    wave
  • Phase difference is 0 degrees

6
Out of Phase
  • crest of one wave overlaps the trough of another
    wave
  • phase difference is equal to 180 degrees

7
Coherent and Incoherent
  • if phase difference stays constant the waves are
    said to be coherent
  • if phase difference is not constant btwn waves,
    no interference pattern is observed and waves are
    incoherent

8
Demonstration of Interference
  • interference can be demonstrated by using
    parallel slits
  • Result is bright and dark parallel bands
  • Bright constructive interference
  • Dark destructive interference
  • at the center of the screen, waves travel the
    same distance and arrive in phase (bright)
  • off the center, some waves are more distant and
    must travel Β½ a wavelength farther and are out of
    phase (dark)

9
White Light
  • is more difficult b/c it has waves of many
    different wavelengths
  • Pattern is less distinct b/o the many colors
  • Tends to be blurred and indistinct
  • ex. colors on soap bubbles

10
Path of Light
  • when using parallel slits, the distance btwn the
    two slits determines whether waves are in phase
    or not
  • the distance btwn the slits can be used to
    measure the wavelength of light
  • Each wave must travel a distance from the slit to
    the screen
  • Difference is equal to d(sin ?)
  • d is the distance btwn slits

11
Constructive Interference
  • path difference determines where the two waves
    are in or out of phase at the screen
  • If path difference is 0 or a whole number, they
    are in phase (constructive)
  • d(sin ?) m? m 0, 1,2 ..
  • m order
  • 0 the central maximum
  • 1 the 1st order maximum, etc.
  • Dark areas indicate minima

12
Destructive Interference
  • if the path difference is an odd number, the
    waves are out of phase (destructive)
  • d(sin ?) (m Β½)? m 0, 1,2

13
Review and Assignment
  • Describe how light waves interfere with each
    other to produce bright and dark fringes.
  • Identify the conditions required for interference
    to occur.
  • Predict the location of interference fringes
    using the equation for double-slit interference.
  • Page 603 1 4

14
Chapter 16 section 2
  • Objectives
  • Describe how light waves diffract around
    obstacles and produce bright and dark fringes.
  • Calculate the positions of fringes for a
    diffraction grating.

15
Diffraction
  • spreading of waves into a region behind an
    obstruction
  • Waves bend around obstacles
  • ex. hearing someone around the corner
  • Usually occurs when waves pass through small
    openings, around obstacles, or sharp edges
  • When the slit is narrowed, light begins to spread
    out and produce a diffraction pattern

16
Diffraction
  • results from constructive and destructive
    interference
  • each point on the slit acts as a source of waves
  • intensity d/o the angle of diffraction
  • Diffraction from monochromatic light through a
    single slit consists of a broad central band
    (central max.), flanked by a series of narrower
    less intense bands

17
Diffraction Gratings
  • diffraction grating can transmit/reflect light
  • Uses diffraction or interference to disperse
    light into separate color
  • Consists of many parallel slits
  • d(sin ?) m? m 0, 1, 2
  • d space btwn slits
  • All wavelengths combine at 0 or m 0 (zero order)

18
Diffraction Gratings
  • sharpness and range d/o number of lines in
    grating
  • number of lines in a grating is the inverse of
    the line separation (1/d)
  • 5000 lines/cm d 1/5000
  • if the number of lines on a grating increases,
    the separation decreases and the farther apart
    the wavelengths are
  • diffraction gratings are used in spectrometers
    to study chemical composition and temperature of
    stars

19
Review and Assignment
  • Describe how light waves diffract around
    obstacles and produce bright and dark fringes.
  • Calculate the positions of fringes for a
    diffraction grating.
  • Page 610 1 5

20
Chapter 16 section 2/3
  • Objectives
  • Describe how diffraction determines an optical
    instruments ability to resolve images.
  • Describe the properties of laser light.
  • Explain how laser light has particular advantages
    in certain applications.

21
Instruments that use Diffraction
  • microscopes and telescopes use diffraction
  • Each object seen has a bright center flanked by
    weaker bright and dark rings
  • If objects are close to each other, the
    diffraction patterns overlap
  • if objects are separated enough that the central
    maxima do not overlap, their images can barely be
    resolved
  • to get high resolution, the angle btwn the
    objects should be as small as possible

22
Resolving Power
  • ability of an optical instrument to separate two
    images that are close together
  • shorter the wavelength of light or the wider the
    opening of the aperature, the smaller the angle
    of resolution
  • if you increase resolving power it means a
    smaller portion of the object will be seen
  • ex. magnifying glass

23
Rayleigh Criterion
  • ? 1.22(?/D)
  • D is equal to the diameter of the lens
  • a small aperature is fine for shorter ?
    (x-rays)
  • a larger aperature is needed for longer ?
    (radio)
  • resolution power can be limited by air particles
    in the atmosphere

24
Lasers
  • Light Amplication by Stimulated Emission of
    Radiation
  • device that produces an intense, nearly parallel
    beam of coherent light
  • waves are in phase and do not shift relative to
    each other
  • b/c waves are in phase, they interfere
    constructively
  • waves behave like a single wave w/a very large
    amplitude
  • light is monochromatic
  • b/o these properties, intensity is greater
  • E/time/area

25
Lasers
  • very high E light source
  • lasers convert light, electrical E, or chemical
    E into coherent light
  • use an active medium and add E to it to produce
    coherent light
  • Active medium can be solid, liquid, or gas
  • Composition of medium determines wavelength or
    color of light produced

26
How lasers work
  • 1. when E is added to active medium, some E is
    absorbed by atoms and then released in the form
    of light waves
  • 2. atoms then return to original E level
  • 3. these initial waves cause other atoms to
    release their E w/same wavelength, phase, and
    direction (stimulated emission)
  • 4. mirrors reflect waves back into medium and
    increase intensity
  • Laser beams are very narrow

27
Uses of lasers
  • 1. measure distance by time it takes to travel
    to object
  • 2. in DVD and CD players
  • 3. medical procedures
  • Remove scars (body absorbs wavelength)
  • Cutting (vaporize water and heat)
  • Coagulates blood
  • Eye surgery
  • 4. read bar codes

28
Review and Assignment
  • Describe how light waves diffract around
    obstacles and produce bright and dark fringes.
  • Calculate the positions of fringes for a
    diffraction grating.
  • Page 612 1 6 and 618 1 - 3
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