An airline wishes to estimate the weight of hand luggage taken on board by passengers' The hand lugg

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An airline wishes to estimate the weight of hand
luggage taken on board by passengers. The hand
luggage of 200 passengers is weighed and the
average is found to be 19.1 pounds. Assume the
standard deviation is 5 pounds. 1. Form a 95
confidence interval estimate of the mean. 2.
What is the standard error of the mean? 3. What
is the margin of error? 4. What is the interval
length? 5. Interpret the interval estimate.
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Dont suggest that the parameter varies There is
a 95 chance that the mean luggage weight is
between 18.81 and 20.19 pounds. Sounds as though
the mean is a random variable. Dont claim that
other samples will agree with yours. In 95 of
the samples the weight will be between 18.81 and
20.19 pounds. The interval is not about other
sample averages, its about the mean
parameter. Correct We are 95 confident that the
mean luggage weight is between 18.81 and 20.19
pounds.
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An airline wishes to estimate the weight of hand
luggage taken on board by passengers. The hand
luggage of 20 passengers is weighed and the
average is found to be 19.1 pounds with standard
deviation is 5 pounds. 1. Form a 95 confidence
interval estimate of the mean. 2. What is the
standard error of the mean? 3. What is the
margin of error? 4. What is the interval
length? 5. Interpret the interval estimate.
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We are 95 confident that the mean luggage weight
is between 16.76 and 21.44 pounds.