Dr' K' Gururajan, MCE, Hassan - PowerPoint PPT Presentation

1 / 21
About This Presentation
Title:

Dr' K' Gururajan, MCE, Hassan

Description:

for the data given below: ... 3. Discussion on fitting an exponential curve of the form . We consider an illustrative example. ... – PowerPoint PPT presentation

Number of Views:50
Avg rating:3.0/5.0
Slides: 22
Provided by: VTU1
Category:

less

Transcript and Presenter's Notes

Title: Dr' K' Gururajan, MCE, Hassan


1
CURVE FITTING

Dr. M. SANKAR Professor and Head Department of
Mathematics Sapthagiri College of
Engineering Bangalore 560 057 Email
manisankarir_at_yahoo.com
Dr. M. SANKAR, SCE, Bangalore
Dr. K. Gururajan, MCE, Hassan
2
Fitting a curve of the form

Dr. M. SANKAR, SCE, Bangalore
Dr. K. Gururajan, MCE, Hassan
3
1. Discussion on fitting a curve of the form
Solution Consider the equation Taking logarithm
with respect to e on both sides,
Dr. M. SANKAR, SCE, Bangalore
4
Putting , ,
we obtain . Thus, the
problem reduces to fitting a straight line.
Therefore, normal equations are and
Dr. M. SANKAR, SCE, Bangalore
5
Fit a curve of the form for
the data given below
Solution First we
prepare the normal equations using which values
of a and b may be determined.
Dr. M. SANKAR, SCE, Bangalore
6
Here, n 6
The normal equations are
and
Dr. M. SANKAR, SCE, Bangalore
7

Dr. M. SANKAR, SCE, Bangalore
8
Thus, normal equations takes the form Solving
these equations for A and B yields A
0.3038 and B -0.02877.
Dr. M. SANKAR, SCE, Bangalore
9
Since A logea and Blogeb, we have a eA
e0.3038 2.013 and b eB e- 0.02877
0.936. Thus, the required curve is

Dr. M. SANKAR, SCE, Bangalore
10
2. Discussion on fitting a curve Consider
. First taking logarithms on either sides,
results in Choosing ,
, ,
Dr. M. SANKAR, SCE, Bangalore
11
The problem now gets reduced to fitting a
straight line of the form Y A bX. The
respective normal equations are and

Dr. M. SANKAR, SCE, Bangalore
12
Fit a power function (geometric curve) of the
form to the data given below.
Solution As discussed earlier, the normal
equations are

Dr. M. SANKAR, SCE, Bangalore
13

Here, n 5
Dr. M. SANKAR, SCE, Bangalore
14
Dr. M. SANKAR, SCE, Bangalore
15
Thus, normal equations are On solving these
two equations, we get
. Therefore,
. Thus, the least square
geometric curve is
Dr. M. SANKAR, SCE, Bangalore
16
3. Discussion on fitting an exponential curve of
the form . We consider an
illustrative example. Consider .
Taking logarithm on either sides leads to
Dr. M. SANKAR, SCE, Bangalore
17
Set and , above
expression reduces to . Thus,
normal equations are


Dr. M. SANKAR, SCE, Bangalore
18

Dr. M. SANKAR, SCE, Bangalore
19
Normal equations may be written as
and If we solve this system
of linear equations, thus,
and
and . The required fit
is

Dr. M. SANKAR, SCE, Bangalore
20
Thank You
Dr. M. SANKAR, SCE, Bangalore
21
  • Assignment problems
  • Fit a curve of the form for the
    data
  • 2. Fit a curve of the form for the
    data

Dr. M. SANKAR, SCE, Bangalore
Write a Comment
User Comments (0)
About PowerShow.com